What is the volume of a cylinder that has a radius of 6 inches and height of 8 inches?
V=pi/4*d^2*h V=pi/4*12^2*8 V=904.32in^3
The cylinder below has a volume of 536.94 cubic inches. What is the radius of the cylinder? Us 3.14 for pi.?
Use the volume formula for cylinders. V = pi * r^2 * h. Plug in all known values and solve for r. V = pi * r^2 * h 536.94 = pi * r^2 * 19 28.26 = pi * r^2 r^2 = 9 r = 3 Answer: Radius is 3 inches.
A cylindrical soup can is 4 inches tall and has a radius of 1 1/2 inches.?
You're trying to find the lateral area, which is the sides of the cylinder not including the top & bottom. First find the circumference (distance around) the base. The radius was 1.5 in., so the circumference would be 2 * pi * 1.5 = 3 pi. Take that result and multiply it by the height of the cylinder. 3 pi * 4 = 12 pi. If it needs to be estimated it would be about 37.68 in squared. Hope this makes sense.
Find the volume of the largest right circular cylinder that can be cut from a circular cone of radius 6cm?
Express the height in terms of the radius. h = (3/2)(6 - r) V = πr²h V = πr²(3/2)(6 - r) V = 9πr² - (3/2)πr³ dV/dr = 18πr - (9/2)πr² Let dV/dr = 0 18πr - (9/2)πr² = 0 4r - r² = 0 r(4 - r) = 0 r = 4 ............... Reject r = 0. V = πr²(3/2)(6 - r) V = 48π cm³
A cylinder is inscribed in a right circular cone of height 5 and radius (at the base) equal to 2.5. ?
let h be the inscribed cylinder's height and r the radius. (5 - h) / r = 5 / 2.5 h = 5 - 2r V(r) = πhr^2 = π(5 - 2r)r^2 = 5πr^2 - 2πr^3 V'(r) = 10πr - 6πr^2 = 0 2πr(5 - 3r) = 0 r > 0 yori, r = 5/3 answers : radius = 5/3 , height = 5/3
A cylindrical vessel of diameter 10 cm and height 8 cm is filled with water up to the rim. When 120 spherical lead shots are dropped into it, one tenth of the water flows out. Find the radius of each lead shot?
Volume of cylinder = pi r² h ( r radius, h height)=> volm = pi 5² *8 = 200 pi cu cm1/10 of (200 pi) flows out=> 20 pi cu cm water flows out=> 20 pi = volume of 120 spherical lead shots ( by Archimedes’ principle , volume of displaced water = volume of objects immersed)Hence, volume of 1 spherical shot = (20pi/120)cu cm = (pi/6) cu cm:> 4/3 pi r^3 = pi /6 ( r is radius of the lead shot)=> r^3 = 3/(6*4)= r^3 = 1/(2*2*2)=> r = 1/2 = 0.5 cmradius = 0.5 cm