Finding the avg speed of a car using algebra?
Let the speed be x mph 360 /x - 360/ (x+4) = 1 360 ( x+4) -360x = x^2 +4x 1440 = x^2 +4x ADD 4 1444 = x^2 +4x +4 1444 = ( x+2)^2 x = 38-2 = 36 mph ANSWER CHECK 360/36 = 10 hours 360/40 = 9 hours 10-9= 1 hour
A car travels from A to B at the rate of 40 miles per hour, and then returns from B to A at the rate of 60 miles per hour. Is the average rate for the round trip more or less than 50 miles per hour? Why?
it 'll be 48 mph.let, the distance of A to B be 1mile.so,first the time=1/40hr.on return,it'll be 1/60hrso, in all for 2 mile the time=1/40+1/60hr.so, avg=2/(1/40+1/60)=48.
Algebra help???????????
North bound car speed be x South bound car speed = x + 4 Nett speed = x + x+4 = 2x +4 2x + 4 = 117 / 3/4 = 156 2x = 152 x = 76 x+4 = 80 ANSWER 80 km per hour. CHECK 80+76 = 156 km / hour 45 minutes = 3/4 X 156 =117 km
College algebra help?
Wind resistance or atmospheric drag tends to slow down moving objects. Atmospheric drag varies jointly as an object's surface area A and velocity v. If a car traveling at a speed of 60 mph with a surface area of 31 ft2 experiences a drag of 204.6 N (Newtons), how fast must a car with 38 ft2 of surface area travel in order to experience a drag force of 305.14 N?