I NEED ALGEBRA 2 HW HELP ASAP!!!?
1. find k so that x^3+kx^2-kx+1 is divided by x-2, the remainder is 0 (synthetic preferred) 2. find k so that x^3+kx^2+k^x+14 is divided by x+2 the remainder is 0 3.when 3x^2-5x+c is divided by x+k the quotient is 3x+1 and the remainder is 3. find k 4. use long division to find (x^8-a^8)/(x^3-ax^2+a^2x-a^3) solve each simultaneous equation 5. (x/4)-1/3(y+1)=2 (x-2y)/3-(x-y)/2=0 6. (1/2)x-8=y/4+12 ((x+y)/5)-35-(2y-x)/4= -x/3 7. 5/(3x)+2/(5y)=7 7/(6x)-1/(10y)=3
Pre-algebra math homework help ASAP!?
Why not just divide the numerator by the denominator, and compare as decimals?
Algebra homework help!!! ASAP?
Please solve this problem. Ace Truck Rental charges $54.00 a day plus $0.09 per mile. Roni’s Truck Rental charges $38.00 a day plus $0.13 per mile. For how many miles will the cost of renting a truck for one day at Ace equal the cost at Roni’s?
Algebra homework help asap?
Find (4x^2 - 2x + 1) + (2x + 8) A) 4x2 + 9 B)4x2 - 2x + 9 C)6x2 + 9 D)6x2 - 2x + 9 Find the product of x^2 + 2x - 4 and 3x . A)-3x3 B)3x3 + 2x - 4 C)3x3 + 6x2 + 12x D)3x3 + 6x2 - 12x The expression (x+4)(6x-1) can be rewritten as which of the following using distribution? Select the correct steps for factoring the polynomial 27x^3+8 A)(3x)3 + (2)3 (3x + 2) (9x2 - 6x + 4) B)(3x)3 + (2)3 (3x - 2) (9x2 + 6x + 4) C)(3x)3 + (2)3 (3x + 2) (9x2 - 6x - 4) D)(3x)3 + (2)3 (3x - 2) (9x2 + 6x - 4 Solve the equation, 2x^2 - 11x - 6 = 0. Solve the equation, x2 - 2x - 8 = 0 by completing the square . x = 4 or x = -2 x = 4 or x = 2 x = -4 or x = -2 x = -4 or x = 2
Math homework help-algebra!!!??? Please help ASAP!?
Write two equations: S = J + 8 2/3 S + J = 23 Substitute the value of S in the top equation into the lower equation: J + 8 2/3 + J = 23 2J + 8 2/3 = 23 Subtract 8 2/3: 2J = 23 - 8 2/3 2J = 23 - 26/3 2J = 69/3 - 26/3 2J = 43/3 Divide both sides by 2: J = 43/6 J = 7 1/6 S = J + 8 2/3 S = 15 5/6 Double-check: 7 1/6 + 15 5/6 = 23 Jason is 7 years 2 months (7 1/6)
Need help on my algebra homework,please help me ASAP?
Gouda = X Edam = Y 3x + 2y = 24.40 4x + 5y = 47.70 You try to solve for 1 variable by getting rid of the other. So you get 1 equation to have a negative coefficient, and the other to have the positive of that coefficient. ( e.g. 7x and -7x ) First off, multiply the equation 3x + 2y = 24.40 by the negative of the second equations first term's coefficient ( the negative of 4x + 5y = 47.70's first term's ( 4x ) coefficient is "-4". ). This is the above step in an equation. -4(3x + 2y = 24.40) = -12x - 8y = -97.6 ( <---- remember this ) Then, you multiply the second equation by the positive of the first equation's first term's coefficient ( the first term's coefficient of the equation 3x + 2y = 24.40 is "3" ) This is the above step in an equation. 3( 4x + 5y = 47.70 ) 12x + 15y = 143.10 ( <---- remember this, too ) Bring the two things i told you to remember next to one another. -12x -8y = -97.6 12x + 15y = 143.10 See? The "x" values (-12x and 12x) cancel out each other when you add the two equations. Then you proceed to add these. 2nd terms (add) -8y + 15y = 7y The answers (add) -97.6 + 143.10 = 45.5 So in the end the "x" values cancel out and you get this 7y = 45.5 Divide by 7 and you get y = 6.50 Plug in the "y" ( 6.50 ) value into one of the original equations to find the value of "x". Let's use the first. 3x + 2y = 24.40 Now "y" = 6.50. Plug it in! 3x + 2(6.50) = 24.40 3x + 13 = 24.40 Subtract 13 from both sides and you get 3x = 11.40 Divide by 3 x = 3.8 Gouda = x Gouda = 6.50 Edam = y Edam = 3.80 Simple ( not really ) as that! Plug in the answers to the other equations to check.]
Algebra homework help? ASAP please! 10 points FOR SURE!?
1. Let length be l and let width be w. Length is twice the width P = 2l + 2w = 2(2w) + 2w = 6w P = 6w 36 = 6w w = 36/6 = 6 The width is 6cm and the length is 6*2 = 12cm. A = l*w = 6*12 = 72cm 2. Let Alice be a. Let Barbara be b. Let Kamran be c. a = 2b c = b - 2 a + b + c = 46 2b + b + b - 2 = 46 4b = 46 + 2 4b = 48 b = 48/4 = 12 Barbara is 12 years old. Alice is 12*2=24 years old and Kamran is 12-2=10 years old. 3. Let x be the no. of hits. x/100 = 0.25 x = 0.25*100 = 25 hits Jerry needs to do 25 consecutive hits to get a batting average of 0.250. (he needs to do 5 more hits)
Algebra homework help. ASAP. please? :)?
Please answer this as soon as possible. Algebra isn't my best subject and I'd like a little help, Thank you. #1, Show an equation and a solution for the problem. How much water must be added to 12 L (liters) of a 40% solution of alcohol to obtain a 30% solution? #2Show an equation and a solution. How much pure antifreeze must be added to 12 L of a 40% solution to obtain a 60% solution. (Remember that pure antifreeze is 100% = 1.) #3 Show an equation and a solution for the problem. Arnold needs a 25% solution of nitric acid. He has 20 milliliters (ml) of a 30% solution. How many ml of a 15% solution should he add to obtain the required 25% solution?
Pre Algebra Homework help. Quick!?
Solution: take the sum of the squares of the two smallest numbers and see if it is equal to the square of the third: 2.1, 2.8, 3.5 2.1 * 2.1 = 4.41 2.8 * 2.8 = 7.84 together: 12.25 3.5 * 3.5 = 12.25 So it is a Pythagorean Triple. So now you must be able to check the other 3 with your calculator.
Algebra Homework; Help Needed Asap "Graphing Systems of Equations"?
1) Standard form: x=-5; y=-6; Solution: x = -5; y = -6; (x, y) = (-5, -6) 2) Standard form: x+y=0; x-y=-2; substitute/eliminate x = -y-0 Solution: x = -1; y = 1; (x, y) = (-1, 1) 3) Standard form: -2x+y=-3; x+y=3; substitute/eliminate x = +1/2y+3/2 Solution: x = 2; y = 1; (x, y) = (2, 1) 4) Standard form: x+y=4; 2x+2y=8; substitute/eliminate x = -y+4 dependent system - infinitely many solutions.x=-y+4; 5) Standard form: x+y=6; x+y=3; substitute/eliminate x = -y+6 inconsistent system - no solutions. 6) Standard form: x+y=4; x-y=6; substitute/eliminate x = -y+4 Consistent, Solution: x = 5; y = -1; (x, y) = (5, -1) 7) Standard form: 2x-y=2; y=4; substitute/eliminate x = +1/2y+1 Consistent, Solution: x = 3; y = 4; (x, y) = (3, 4) 8) Standard form: x+y=4; x-y=0; substitute/eliminate x = -y+4 Consistent, Solution: x = 2; y = 2; (x, y) = (2, 2)