Can someone help me on my Statistic Homework?
the meat department of a local supermarket packages ground beef using meat trays of two sizes: one designed to hold approximately 1.5 pounds of meat, and one that holds approximately 3 pounds. A random sample of 36 packages in the smaller meat trays produced weight measurements with an average of 1.51 pounds and a standard deviation of .20 pounds. Construct a 99% confidence interval for the average weight of all packages sold in the small meat trays by this supermarket chain.
Can someone help me with statistics homework?
Ok i Have a homework question for my statistics intro course. I cant really figure it out. Any help is much appreciated. Heres the question: "Mensa is an organization that allows people to join only if their IQ's are in the top 2% of the population." Question 1: What is the lowest IQ you could have and still be eligible to join Mensa? (remember that the mean is 100 and the standard deviation is 16) Question 2: Mensa also allows members to qualify on the basis of certain standard tests. If you were to try to qualify on the basis of the GRE exam, what score would you need on the exam? (Remember that the mean is 497 and the standard deviation is 115) Thanks again
Can someone help me with my statistics hw?
The American Resorts hotel chain gives an attitude test to job applicants and considers a multiple choice test question to be easy if at least 80% of the responses are correct. A random sample of 6503 responses to one particular question includes 84% correct responses. Construct the 99% confidence interval for the true percentage of correct responses
I got this problem wrong can someone help me with my statistics homework?
Assume that she buys one horse. That leaves $90 to buy 99 animals. Represent the number of cows that she can buy as C. The number of sheep that she can buy is then 99 - C. Since she has $90, we can say that $1*C+ $0.50*(99-C) = $90. Doing the math gives the result of 81 cows and 18 sheep. Similarly, if she buys 2 horses, she would have $80 to buy 98 animals. C + 0.5(98-C) = 80. Result: 62 cows and 36 sheep. Generalizing, if H is the number of horses, then C + 0.5(100-H-C) = 100 - 10*H C + 50 -0.5*H -0.5*C = 100 - 10*H 0.5*C + 9.5*H = 50 Multiplying both sides by 2 for simplicity yields C + 19*H = 100 or 100 - 19*H = C The maximum number of horses she can buy is 5 Edit: I'm surprised to see that Morenita's answer got a thumbs up and mine got a thumbs down. Her answer is wrong because the genie also specified that the number of animals must be 100. Morenita's answer correctly spends the proper number of dollars but ends up with the wrong number of animals. There are only five possible correct solutions, involving the purchase of 1, 2, 3, 4, or 5 horses (since she must buy at least one of each type of animal)
Can someone out there help me with my (math) statistics homework?
This question has to do with X (squared) test for a variance or standard deviation... Eighteen 5-gallon containers of fruit punch are selected and each is tested to determine its weight in ounces. The variance of the sample is 6.5. Test the claim that the population variance is greater than 6.2, at alpha = 0.01. I hope somebody can help.
Can someone help me with my statistics homework? I don't get this stuff at all.?
Suppose a student measuring the boiling temperature of a certain liquid observes the readings (in degrees Celsius) 102.5, 101.7, 103.1, 100.9, 100.5, and 102.2 on 6 different samples of the liquid. He calculates the sample mean to be 101.82. If he knows that the standard deviation for this procedure is 1.2 degrees, what is the confidence interval for the population mean at a 95% confidence level? In other words, the student wishes to estimate the true mean boiling temperature of the liquid using the results of his measurements. If the measurements follow a normal distribution, then the sample mean will have the distribution N(mean,stddev/sqrt(n)). Since the sample size is 6, the standard deviation of the sample mean is equal to 1.2/sqrt(6) = 0.49.
Can someone help me with my statistics Home work?
Solve the problem. Round results to the nearest hundredth. The mean of a set of data is 0.92 and its standard deviation is 2.42. Find the z score for a value of 3.81. 1.49 1.07 1.31 1.19
Can someone help me with Stats?
Add more detail to your question. I am not sure how to begin answering. However, you will be testing a null hypothesis which is essentially a no difference hypothesis. If you reject it, then you can conclude that your alternative hypothesis is true. You reject the null hypothesis based on the value of the t statistic or z statistic you will have calculated. If your z or t calculated is bigger than the critical value (which you get in the statistical tables) then you reject your null hypothesis. Your alternative hypothesis (or your research hypothesis) can say any of the following: •there is a treatment effect, •there is a significant difference between two sample means, •a relationship is significant, •a sample mean is different from zero (or any other value). •etc. ----------------------------- In light of the additional details you provided, see below. Testing the sample mean: Z = (Xbar – 24,000)/328.6 = 1.28 You get the 328.6 by dividing 1944 by the square root of 35. Decision rule: reject Ho if Z (calculated) is greater than Z (critical) Since 1.28 is less than 1.96, fail to reject Ho and conclude that the sample mean is less than or equal to 24,000. The second part wants you to calculate a confidence interval about the sample mean. The upper bound of your Confidence interval is 24,644. This is the largest value for which Ho is not rejected. This confirms the earlier decision that Ho should not be rejected when the sample mean is 24,421. The probability that the change will not be detected should be the significance level 0.05. Send me a message if this helps!! Ok.