If a>0, then function f(x) = ax^2 + bx + c has minimum value at?
Lot of Questions Related to Quadratic Functions can be solved with the help of Graphs. It is easier to analyse and understand the problems with graphs .I Hope the solution will help in every regard.Thanks!!
Find values of a and b so that the function has a local maximum at the point (3, 9).?
f '(x) = (ax * b*e^(bx)) + (a*e^(bx) = a * (e^(bx) * (bx + 1) Since e^(bx) cannot be 0, either a = 0 or (bx + 1) = 0 f"(x) = ab*(e^(bx)) * (bx + 2) This must be negative if (3,9) is a maximum It won't be negative at a = 0, so the maximum is at 3b + 2 = 0 b = (-1/3)...............Substitute that into the original equation to find a. f(x) = axe^(bx) 9 = a * 3 * (e^-1)) a = 3e *************** a = 3e b = (-1/3) *************** .
The function f(x)=x^3+ax^2+bx+c, has a local minimum at x=-2. Determine the values of a and b.?
Hint: If f(x) has a local min at x=-3, then f'(-3)=0 and if f(x) has an inflection point at x=-2, then f''(-2)=0. Im so confused as to how to do this problem, please help with instructions?
What values of a and b make f(x)=x^3+ax^2+bx have a local maximum at x=-1 and a local minimum at x=3?
f ' (x) = 3x^2 + 2ax + b f ' (1) = 3 + 2a + b -3 = 2a + b f ' (3) = 27 + 6a + b -27 = 6a + b 24 = -4a -6 = a 9 = b b) f ' (x) = 3x^2 + 2ax + b f ''(x) = 6x + 2a f ' (4) = 48 + 8a + b -48 = 8a + b f ''(x) = 6 + 2a -6 = 2a -3 = a -48 = 8(-3) + b -24 = b
Find a cubic function f(x) = ax3 + bx2 + cx + d that has a local maximum value and min at...?
Find a cubic function f(x) = ax3 + bx2 + cx + d that has a local maximum value of 3 at x = −3 and a local minimum value of 0 at x = 1 I can't figure out how to solve this problem and it is due in 16 minutes. Any help would be appreciated!
Find a,b, and c, so that y=ax^3+bx^2+cx has local maximum x=1, local minimum x=-3?
y'=3ax^2+2bx+c y"=6ax+2b so you have an inflection point at x=-1. 0=6ax+2b -2b/6a=x -b/(3a)=x -b/(3a)=-1. plug this into y'.