Need some help with my trig homework?
It says write in terms of the cofunction of a complementary angle. sec 34 degrees and the choices are csc 56 degrees, cos 56, sec 56, or sin 34 if anyone can help me out that would be great.. thanks.
Trigonometry Homework HELP!!!!!!!!!!!!!?
One degree is equal to 60 minutes. Add up the degrees, add up the minutes. Change the minutes to a mixed number by using 60 as the denominator, then add the whole number minutes to the minute total: 62 18 + 21 41 = (62 + 21) degrees and (18 + 41 minutes) 83 degrees, 59 minutes 90 degrees - 51 degrees 28 minutes 90 degrees = 89 degrees, 60 minutes (89 - 51) degrees, (60 - 28 minutes) 38 degrees 32 minutes
Trig homework Log. Help?
log a - log b = log (a/b) Hence log7 (36) - log7 (x)=log7 (36/x) =log7 (4) therefore 36/x = 4 , giving x=36/4=9 2, since the base is same, 3x + 10 = x^2 or, x^2-3x-10=0 or, (x+2)(x-5)=0 gives x= -2 or 5 hope it helps
I need help with trig homework asap?
write equation the line passes through (-1,1) and is parallel to y = -x +2 a geologist measures the movement of a glacier over a period of several weeks. after 3 weeks the glacier moved 9 centimeters relative to its starting point. after 8 weeks it moved an additonal 12c find the average weekly rate of change in glacier postion durin the first 3 weeks and from the 3rd week till 8th week you are measurin a bike ramp which is 15 feet wide at its base and 12 feet tall at its tallest point what is the slope of the bike ramp? does the ramp fall rise is it horizontle or verticle
Trigonometry homework help!!?
Given: sin(x) = -0.3 x is in the third quadrant Problem 1: find cot(x) ---------------------- First, determine the value of cos(x): sin^2(x) + cos^2(x) = 1 (-0.3)^2 + cos^2(x) = 1 0.09 + cos^2(x) = 1 cos^2(x) = 1 - 0.09 cos^2(x) = 0.91 cos(x) = +/- sqrt(0.91) However, since we know that x is in the third quadrant, then we know that cos(x) is negative. Therefore: cos(x) = -sqrt(0.91) Now, determine cot(x): cot(x) = cos(x)/sin(x) cot(x) = sqrt(0.91)/(-0.3) Approximating with a calculator: cot(x) = -3.17979733805648549716 Problem 2: find cos(x + 3pi) ---------------------------- First, we can reduce the argument by 2pi, since cos() is periodic every 2pi radians: cos(x + 3pi) = cos(x + 3pi - 2pi) = cos(x + pi) Next, apply the identity: cos(x+pi) = -cos(x) -cos(x) Since we have already determined cos(x), we simply need to negate it: = -(-sqrt(0.91)) = sqrt(0.91) Shifting by pi has placed this into the first quadrant, so it's consistent that it is positive. Thus: cos(x + 3pi) = sqrt(0.91) .
I need help with my trigonometry homework!?
Can someone help me answer this question? : In a right triangle whose hypotenuse measures 50 units, the shorter leg measures 30 units, find the measure of the projection of the shorter leg on the hypotenuse.
TRIGONOMETRY homework . i need help please.?
a) use this formula __A__ = __B__ ............................. sin a . sin b the problem is you have to find the other angle of the triangle. for example for the first treasure its 180=90+11+a. just find 'a' and substitute in the formula. b is 90 degrees and A is how deep the water is (115 m)...then you can find B.. very simple. do for both angles and you'd get which one is the furthest. thats the answer. b) use the same formula to find the bottom length of both triangles, where A is the ocean depth, B is the bottom length, a is either 11 or 36(you have to do both seperately), and b is what 'a' is above. then just subract the difference.