Will HCl or H2SO4 (same concentrations in molarity) require more volume (in mL) to neutralize a solution of NaOH?
All of the other answers here are quite correct, however I thought I’d expand a little bit on the reason why sulphuric acid neutralises twice the molar quantity of NaOH that HCl does. Robert Goodman has hinted at the reason in his answer where he mentions Normality versus Molarity.The reaction of sulphuric acid and sodium hydroxide is normally written as;-H2SO4 + 2 NaOH —→ Na2SO4 + 2H2OFrom this it is clear that one mole of sulphuric acid will neutralise two moles of sodium hydroxide. However the reaction, as written above, is actually the overall reaction resulting from several separate, intermediate reactions.Sulphuric acid is a diprotic acid, which means its ionisation in aqueous solution to produce protons occurs in a two separate stages with the intermediate formation of a bisulphate (or hydrogen sulphate) ion;-H2SO4(l) + H2O(l) —→ H3O+(aq) + HSO4-(aq)HSO4-(aq) + H2O(l) —→ H3O+(aq) + SO4–2(aq)Each reaction releases one mole of hydronium ions (H3O+), each of which can neutralise one mole of NaOH;-H3O+(aq) + OH- (aq) ——-> 2 H2O(l)Similarly, a triprotic acid, such as phosphoric acid (H3PO4), would neutralise three molar equivalents of sodium hydroxide… and so on.
The radius of a planet is half the respective value of the Earth with the same mass. What is the value of acceleration due to the gravity of the planet?
Well, in a classic Newtonian sense, none. But acceleration is the second derivative of position, and first derivative of velocity, so the Earth isn’t accelerating in a linear fashion. It has rotational velocity and momentum, but no acceleration per se, in terms of how fast it’s whizzing along. Although as its angular momentum shifts, there is a technical acceleration, not in the speed it’s traveling through space, but in the relative speed it is traveling in any given direction.Secondly, something with half the radius would have one eighth the volume. So the same mass in one eighth as much space would be one heavy butt-nugget. Still, by standard Newtonian equations, so long as the mass was constant, the acceleration and angular momentum equations would be unchanged.But at the margins, given its new size, and its new relationship with the moon and sun in terms of distance (a 4000 mile shift, from an 8000 mile radius to a 4000 mile radius), there would be small shifts in the gravitational effects, due to distance rather than mass. These would be evident at the outset, in terms of a genuine acceleration to reflect a new orbit, and then reach an equilibrium, where the only acceleration was rotational.And we’d all be dead.
What is the best way to calculate speed from acceleration?
Acceleration is rate of change of velocity. So when talking of the velocity of an object which is accelerating, you can only know the instantaneous velocity at a given moment in time. Or the average velocity over a given time interval, starting or ending at a set point in time.At its simplest, assuming that acceleration is constant, the equation you need is:s=at+vWhere s is the instantaneous velocity. a is acceleration, t is time and v is the start velocity.
An object is travelling with a constant acceleration of 10m/s[math]^2[/math]. How much distance will it travel during the 3rd second of its journey assuming it starts from rest?
Here a body is moving with constant accleration so initial velocity musy be taken zeroSo, by formulaS= u+a/2 (2t—1)=0+10/2(2×3—1)=5(5)=25m
A ball is dropped from a height of 45m. What will be the time to reach the ground?
The distance is 45m. (s)Acceleration is 9.8 m/s^2 (acceleration due to gravity). (a)We have to find the time (t)By the 3rd equation of motion,s = ut + 1/2 at^2 (here u is the initial velocity of the ball)Since the initial velocity was 0 m/s, the formula becomes s = 1/2 at^2.(substituting the values in the formula)45 = 1/2 x 9.8 x t^245 = 9.8/2 x t^245 = 4.9 x t^2 (9.8/2 = 4.9)(divide 4.9 on both sides)45/4.9 = 4.9 x t^2 / 4.99.1836 = t^23.030 = tSo it takes approximately 3 seconds for the ball to reach the surface of the earth (neglecting air resistance).
Math help Please and thank you?!?
1C 2D 3C 4D 5? 6D 7C 8D 9C 10C 11A 12D 13C 14D 15D 16B 17B 18D 19D 20B
If the gravitational acceleration on the moon is 1/6th that of Earth, how much longer does it take for an object to fall on the moon compared to the Earth?
It's simple to calculate!S = u*t + 1/2* a*t^2Where ,S - is the displacementu- is the intial velocitya-is the acceleration due to gravityt-is the timeThis is the equation of motion (derived with the help of calculus) in one dimension when acceleration is a constant.Considering a free fall from a given height (here given height is S) where initially the object is stationary. Going by the equation , the time taken would amount to (2S/a)^0.5For earth :Let a = g;So t= (2*S/g)^0.5For moon:Let a= g/6So t=(12*S/g)^0.5Thus , the object would fall for a longer time in moon with approximately 2.45 times the time it takes to fall in earth.
How many moles of NaOH are needed to neutralize 2.5 moles of H2SO4?
The reaction between an acid, such as H2SO4 and a base, such as NaOH, is known as a neutralization reaction, which produces a salt compound and water. The balanced reaction between NaOH and H2SO4 can be represented by the chemical equation 2 NaOH + H2SO4 → Na2SO4+ 2 H2O.Based on the equation, the mole ratio between NaOH and H2SO4 is 2:1, meaning that it takes twice the amount of NaOH as H2SO4, for the base to completely neutralize the acid and produce sodium sulfate and water. Hence, the number of moles of NaOH needed to burn 2.5 moles of H2SO4 is calculated by multiplying 2.5 moles by 2.