How many atoms of phosphorus are in 7.80 mol of copper(II) phosphate?
The formula for copper(II) phosphate is Cu3(PO4)2, so there are two phosphorus atoms for each molecule of Cu3(PO4)2. (7.80 mol Cu3(PO4)2) x (6.022 x 10^23 molecules/mol) x (2 atoms P / molecule) = 9.39 x 10^24 atoms P
How many atoms of phosphorus are in 7.50 mol of copper (II) phosphate?
Let copper(II) phosphate, Cu3(PO4)2, be called CP. 7.50molCP x 2molP/1molCP x 6.02x10^23atomsP/1molP = 9.03 x 10^24 atoms P
How many atoms of phosphorus are in 8.80 moles of copper(II) phosphate?
... this is Cu3(PO4)2 and each mole has 3 mol of Cu atoms so 8.80 mol compound * 3 mol Cu / mol compound * 6.022E23 atm/mol = 1.60E25 atoms Cu When you get a good response, please consider giving a best answer. This is the only reward we get. You may have to wait an hour to award BA.