How many electrons could occupy a subshell with the following quantum numbers?
• n == principal quantum number (major energy level). The values range from 1 to 7 (or 8, eventually) • ℓ == azimuthal quantum number (sublevel). The values range from 0 to n-1. 0 = s, 1 = p, 2 = d, 3 = f • mℓ == magnetic quantum number (orbital within a sublevel). The values range from -ℓ to 0, to +ℓ. For instance, when ℓ = 1 (p-sublevel), mℓ has values of -1, 0, +1. • ms == spin quantum number (electron within an orbital). The values are +½ and -½ which indicate the opposite spins of the electrons in an orbital. a; n = 5, ℓ = 4 ..... this refers to the hypothetical g-sublevel, in which there are 9 orbitals, and 18 electrons, 2 per orbital. b; n = 5, ℓ = 3, mℓ = -3 ..... this refers to a specific orbital in the f-sublevel, and of course, an orbital holds only 2 electrons.
How many electrons can occupy a subshell with the following values: I=0; I=1; I=2; I=3?
l=0; m=0; s=+1/2 and -1/2 so 2 electrons l=1; m=-1, 0, +1 and for each s=+/- 1/2 so 6 electrons l=2; m=-2, -1, 0, +1, +2 and s= +/- 1/2 so 10 electrons Do the same for l=3
How many electrons could occupy a subshell with n=4 and l=3?
since l=3 m=+3,+2,+1,0,-1,-2,-3 do there are 7 orbitals in all and since one orbital contains 2 electrons it can have a maximum of 14 electrons,thus 4f subshell can possess 14 electrons
How many electrons are in a subshell in which l=5?
The number of orbitals corresponding to a particular value of [math]l[/math] depends on the possible values of the magnetic quantum number, [math]m_l[/math]. [math]m_l[/math] can take any integer value between [math]-l[/math] and [math]l[/math], for a total of [math]2l + 1[/math] possible orbitals. When [math]l=5[/math], (an h orbital) there are 11 orbitals within the subshell, and they can hold up to 22 electrons.The general rule would be [math]4l+2[/math] electrons for a subshell with angular momentum quantum number, [math]l[/math].
What are the maximum number of electrons in a subshell with l=2 and n=4?
Maximum number of electrons in a subshell doesn't depend on [math]n[/math]. It is related to [math]l[/math] by the expression [math]2 (2l+1).[/math] So [math]l=2[/math] can have maximum of 10 electrons.
How many electrons can be accommodated in a subshell with n= 3 and l=3?
The constraints on the quantum numbers for electrons in a hydrogen-like potential are as follows:[math]n \in \Z \space \space n \geq 1[/math][math]l \in \Z \space \space 0\leq l
How many electrons can fit in the orbital for which n=3 and l=1?
‘l’ for sub shell orbital with formulano. of subshell = no. of orbits - 1l contains orbitals (sub sub shell/ orbital)foreach orbital contains 2 e.shell (n) subshell( l) orbital( m)n=1 . l = 0 . m=o = 1s2n=2. l = 0,1 m=0 and - 1,0,1.= 2s2 and 2p6n=3 l=1 then m= - 1,0,1 = 6 e.if u ask for m= 0 or 1 or - 1 for particular orbital then there will be only 2 e.if u not include l and m then e will be 2n^2
Quantum numbers and electrons? Help please :(?
The maximum number of electrons that any atomic orbital can have is two. Also, no two electrons can have the same four quantum numbers. s orbitals there is only one type of s orbital, so in a 2s orbital there can be only two electrons. electron 1 ==> n = 2, l = 0, ml = 0, ms = +1/2 (spin) electron 2 ==> n = 2, l = 0, ml = 0, ms = -1/2 (spin) n = 3, l = 2, indicates a d orbital, number of orbitals in a subshell is equal to 2l + 1, since l = 2, 2(2) + 1 = five 3d orbitals, so ten electrons in that subshell, 1. n = 3, l =2, ml = 2, ms = +1/2 2. n = 3, l =2, ml = 2, ms = -1/2 3. n = 3, l =2, ml = 1, ms = +1/2 4. n = 3, l =2, ml = 1, ms = -1/2 5. n = 3, l =2, ml = 0, ms = +1/2 6. n = 3, l =2, ml = 0, ms = -1/2 7. n = 3, l =2, ml = -1, ms = +1/2 8. n = 3, l =2, ml = -1, ms = -1/2 9. n = 3, l =2, ml = -2, ms = +1/2 10. n = 3, l =2, ml = -2, ms = -1/2 For 6d, same as 3d, except that n = 6, not 3. For any subshell, the possible numbers of ml values are tied up to the l value, since l = 2, ml values are five -2, -1, 0, 1, 2.
How many electrons can fit in an n=3 orbital?
2n^2= number of electionsHere, n=3Then, 2×3^2=2×9=18Hence 18 electrons when n=3