How many 4 digit whole numbers using the digits in the set...?
Using only 4 digit whole numbers in the following set set: 1, 2, 3, 4, 5, 6, 7, 8, 9, 0 How many numbers have exactly three digits which are sevens (with replacements)? How many numbers end with an even digit and can repeat digits (with replacement)? How many numbers begin with an odd digit and can repeat digits (with replacement)? How many numbers do not contain the same digit twice (without replacement)? How many numbers begin and end with a one (with replacement)? Can you please explain how you got the answers too. Thank you very much!!! I greatly appreciate it.
How many whole numbers are there that have 2 as ten digits?
How many whole numbers are there that have 2 as ten digits?Every whole number that has 2 as the tens digit can be broken down into the sum of three numbers: a number between 0 and 9, 20, and any multiple of 100.For instance, the whole number [math]31415926 = 6 + 20 + 31415900[/math]So the number of whole numbers that have 2 as a tens digit is equal to 10 times the number of multiples of 100.This number is called [math]\aleph_0[/math], and is the first of the “transfinite Cardinal” numbers. It is not a whole number. In fact, it is generally considered to be part of a different class of numbers than integers or whole numbers — the Cardinal numbers. While the Cardinal numbers that are less than [math]\aleph_0[/math] act just like the natural numbers (you can add, multiply, raise them to powers, and order them just like natural numbers), [math]\aleph_0[/math] is beyond finite — it’s “transfinite”, and transfinite Cardinals do not act like normal numbers. For instance, [math]\aleph_0 + \aleph_0 = 2\aleph_0 = \aleph_0[/math] and [math]\aleph_0\aleph_0 = \aleph_0^2 = \aleph_0[/math]. But [math]\aleph_0 < 2^{\aleph_0}[/math].
How many 4-digit whole numbers can be made using the digits 9,8,7,and 6 if no digit is used more than once in any number ?
24
How many numbers less than 500 can be made from the digits 0,1,2,3,5,7?
the first digit for a number less tha 500 can be 0,1,2,3 When repetition not allowed we go step by step 1) three digit nos (ABC) position A can have one of 1,2,3 or 3 ways 2) once A is selected we can pick up any other number from the rest for other positions B and C so out of 0,1,2,3,5,7 or total 6 nos we have only 5 numbers available (one is selected so only 5 available) for position (say B) and 4 ways for C so ABC be made up in 3*5*4 = 60 numbers 2) For 2 digit numbers (AB) A can be filled in with 1,2,3 or 3 ways and B can be filled with 5 nos so 3*5= 15 nos 3) For single digit (A) we have any of the 6 if 0 is to be counted or 5 if 0 is not allowed so total nos formed are 60+ 15 + 5 = 80 if 0 is not allowed and 60+15+6 = 81 if 0 is to be counted - Ans b)when repetition is allowed 1)three digit number (ABC) first position A (1,2,3) in 3 ways , B and C in 6*6 ways (all numbers can repeat for both positions) hence 3*6*6 = 108 ways 2)two digit (AB) 3* 6 = 18 3) single digit either 6 if 0 is allowed as a number or 5 if 0 is not be counted as an answer so we have 108+ 18+ 5 = 131 ways if 0 is not to be counted and 108+ 18 + 6 =132 ways if 0 is to be counted. Edit; probability we can also use the reverse way of calculating the numbers by taking 3 digit numbers greater than 500 and above and substracting from total 3 digit numbers that can be formed. then add the 2 digit and single numbers
How many positive 3 digit numbers can be made from the digits 1, 2, 3, 4, 5, 6, 7, 8, 9? (no repeats)?
Carry the 4 add the nine then u have to add e qns multiply pi so id say A LOT!!!!!!!!!!
How many 5 digit numbers are there in all?
That depends a bit on what you mean by a 5-digit number.I mean, technically 00123 is a 5-digit number, but I guess you’d say that is really just 123 so doesn’t count? And what about negative numbers? Do you count -12345 as a 5-digit number?Assuming we don’t count leading-zeroes and exclude negative numbers then the range is from 10000 to 99999.So how many numbers is that? Well you could count them all. That might get a little tedious!Or you could subtract 10000 from 99999 then add 1.Or you could look at each digit in turn… Starting at the right-hand end, the final digit can take one out of 10 different values - 0, 1, 2, 3, 4, 5, 6, 7, 8 or 9. Similarly for each of the 3 digits to the left of it. But the first digit can only be taken from 9 different values - because we’re excluding 0.So our 5-digit number is made up as one digit chosen from 9, followed by one digit chosen from 10, followed by one digit chosen from 10, followed by one digit chosen from 10, followed by one digit chosen from 10.The number of possibilities are thus 9 x 10 x 10 x 10 x 10.Good luck with the rest of your homework!
How many 4-digit whole numbers using the digits in the set {1, 2, 3, 4, 5, 6, 7, 8, 9, 0} can be formed using?
Here's a partial answer: 1) Numbers end with an even digit and can repeat digits. This means that all even numbers between 1002 through 9998 are valid, so Numb = (9998 - 1000) / 2 = 8998/2 = 4499 2) Numbers do not contain the same digit twice. Using combinations/permutations equations, we get Numb = 10! / (10-4)! = 3628800 / 720 = 5040 3) Numbers begin and end with a 1. This limits us to the numbers between 1001 and 1991, and since only the two middle digits can vary it is simply all numbers between 00 and 99, so Numb = 100 5) Numbers begin with an odd digit and can repeat digits. This is basically the same as (1), except using odd beginning digits instead of even ending digits so again Numb = 4499.
How many 4-digit numbers are there in all?
I love these sorts of questions. Let’s find out. So we have 4 numbers which is 4 spots for numbers. We have positive, negative, decimal, and fractional numbers. We also have ratios, exponents, roots, factorials, variables, and expressions. We also have inequalities. However, we only want the combinations of the numbers (not the numbers AND symbols/letters). We also do not want exponents. So the question translates to “How many real 4 digit whole numbers are there?” We have 4 spots and 10 possible different numbers to occupy those spots (0–9). To find the answer, we take 10 and raise it to the power of 4. This gives us 10,000. If we include negative numbers too, we get 20,000 possible combinations. -0 is still technically its own number even though its numerical value is 0. However, the question does not state that they have to be 1-digit numbers. This means that there are n to the 4th power possible combinations where n=the total amount of unique numbers. This means that there are infinite combinations. It also doesn’t say “possible combinations” which implies that it is how many combinations that there actually are. As far as we know, not all of the combinations have even been come up with yet. We cannot tell how many combinations exist, however. So the answer is unknown. I hope this helped.
How many whole numbers are there?
Infinitely many.But not nearly as many as the number of points on a line. No matter how hard you try, you cannot devise a system that assigns a (unique) whole number to each point on a line. If you could, you would say the points on a line are countable. They are not.We have names for the different types of infinity, these names are called cardinal numbers.The two lowest infinite cardinal numbers are described above. We use the first letter in the Hebrew alphabet, called ALEPH, supplied with a subscript, as symbols for these cardinal numbers. Thus the number of whole numbers is ALEPH-0 and the number of points on a line is ALEPH-1. Unfortunately I don’t know how to write these symbols here (can anyone tell me?).The series of magnitudes goes on forever: ALEPH-0, ALEPH-1, ALEPH-2 etc.My 7 years old grandson, Holger, heard me talk about this and was very excited about the idea. After a few days of thought, he invented the greates “number” of all infinite numbers: ALEPH-ALEPH. Now he and his schoolmates use that name for something that is greater than everything else.BTW: For many years mathematicians have disputed whether there exists a cardinal number between ALEPH-0 and ALEPH-1 and different from both of them. Kurt Gödel and Paul Joseph Cohen have shown the neither of the answers “yes” or “no” to that question can be proved to be neither right nor wrong.
How many 4 digit numbers can be formed from 1,2,4,5,7 and 8?
A. When the digits are not to be repeated_ _ _ _Start with the last place. We have the digits 1, 2, 4, 5, 7 and 8 available that can be used at the unit digit’s place. Number of possible choices = 6Now on the ten’s place, only 5 digits can be used, because no repetition is allowed. ( one of the six has already been used at the one’s place, so that leaves us with 5 digits only). Number of possible choices = 5Similarly, on the second and the first places 4 and 3 digits can be used respectively.Therefore the number of possible arrangements = 6*5*4*3 = 360360 numbers can be formed from the given digits.B. When the digits are repeated_ _ _ _Starting with the last place again, 6 digits can be used for the place .For the third, second and the first places, we again can use all the six digits. ( Since repetition is allowed)So the number of possible arrangements = 6*6*6*6 = 1296