How rapidly would the following particles be moving (BEST ANSWER TO FIRST CORRECT ONE)?
how rapidly would the following particles be moving IF THEY ALL HAD THE SAME WAVELENGTH AS A PHOTON OF ORANGE LIGHT (=625.0 NM): AN ELECTRON OF MASS 9.10938x10^-28 A NEUTRON OF MASS 1.67493x10^-24g A PROTON OF MASS 1.67262x10^-24g AN alpha PARTICLE OF MASS 6.64x10^-24g
How rapidle would the following particles be moving if they all had the same wavelength as a photon of orange?
Frequency of orange light is approximately λ = 590–620 nm so let's use 605 nm as the wavelength of orange light. E = hc/λ = (6.626 x 10^-34 J*s)(2.997 x 10^8 m/s)/[(605 nm)(1 m)/(10^9 nm)] [(605 nm)(1 m)/(10^9 nm)] converts nm to meters. E = 3.28 x 10^-19 J for a photon of orange light, where λ = 6.05 x 10^-7 m Now, use deBroglie's hypothesis: λ = h/mv Now, solve for v and you get: v = h/mλ For electron: v = (6.626 x 10^-34 J*s)/(9.10939 x 10^-31 kg)(6.05 x 10^-7 m) Note: mass must be in kg. v = 1202 m/s For neutron: v = (6.626 x 10^-34 J*s)/(1.67493 x 10^-27 kg)(6.05 x 10^-7 m) Note: mass must be in kg. v = 0.654 m/s For proton: v = (6.626 x 10^-34 J*s)/(1.67262 x 10^-27 kg)(6.05 x 10^-7 m) v = 0.655 m/s For particle of mass 6.64 x 10^-24 I'll assume you are consistent and that this is in grams. v = (6.626 x 10^-34 J*s)/(6.64 x 10^-27 kg)(6.05 x 10^-7 m) v = 0.165 m/s Hope this is helpful to you. JIL HIR
How rapidly would the particles be moving if they all have the same wavelength as a photon of violet light?
Use the DeBroglie wavelength formula and it's simple plug and chug. wavelength = h / (mass x velocity) h = 6.626E-34 Convert the masses to kilograms and the wavelength to meters and your velocity come out in m/s. 4.000 x 10^-7 m. 4.000E-7 = 6.626E-34 / 9.10939E-31(v) 3.644E-37(v) = 6.626E-34 v = 1.818 x 10^3 m/s for the electron in part A. The rest are all the same. Convert mass to kg, wavelength to m, plug and chug.
What would be the speed of the following particles if they had the same wavelength as a photon of orange light (λ = 625.0 nm)?
Let's apply De-Broglie expression pλ=h (h: Planck constant, h=6.64·10^-34 Js) ---> mvλ=h ---> v=h/mλ and only a simple substitution of the parameters above is needed 1. Proton: v=6.64·10^-34/(1.673·10^-27*625·10^-9)=0... m/s (1 nm=10^-9 m, 1 g=10^-3 Kg) 2. Neutron: v=6.64·10^-34/(1.675·10^-27*625·10^-9)=0... m/s 3: Electron: v=6.64·10^-34/(9.109·10^-31*625·10^-9)=1... m/s 4. Alpha particle: v=6.64·10^-34/(6.645·10^-27*625·10^-9)=0... m/s
Find velocity given wavelength and grams of electrons...?
For each of these, you need to use the de Broglie wavelength formula: wavelength = h/p = h/(mv) where h is Planck's constant (6.63*10^-34 J*s), m is the mass of the particle, and v is the velocity of the particle. Just plug in the numbers and solve for v. And you'll want to convert those masses to kilograms.