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here they are! how smart are u?show the work or it will not win best answer! 1.27x13 2.45x62 3.33x51 4.42x51 5.65x92 6.15x47 7.87x93 8.46x41 9.87x65 10.23x50 11.84x19 12.22x38 13.47x25 14.48x62 15.83x60 16.758x61 17.382x27 18.524x43 19.618x59 20.742x57 and don't forget to show the work cause then i will not choose you as best answer!
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1)around the rink is the perimeter the perimeter of the rectangle will be (50*2)+(75*2)=250 ft the total cost is therefore 13.50*250 = $3375 2)the area of a rectangle is length*width for this rectangle its 50*75 = 3750 ft^2 the machine can clear 750 ft^2 per minute so the amount of lots of 750 ft^2 is 3750/750 = 5 ie it takes 5 minutes to clear the rink of ice ______________________________________... 1) find out the dimensions of the piece of wood previously we found area=length*width so width = area / length = 544/32 = 17 the length of the ruler is 30cm and the width is 5cm therefore we have to throw away the additional 2cm and cut the sheet to new dimensions of 17cm by 30cm the amount of rulers that you can get out of 17cm is 17/5(the width of the ruler) = 3.4 rulers the 0.4 of a ruler is useless and as such it must be thrown away. the number of rulers able to be cut out is therefore 3 rulers (the scrap leftover will be (2*30+2*17)=94cm^2
How to do these math questions?
To balance the apparatuses you need the same amount of torque on each side of the fulcrum. For the first problem the torque on the first side is 150 kg * 3m = 450 kgm. You need the same amount of torque on the other side. So your equation is 200 kg * xm = 450 kgm. To balance this equation, divide both sides by 200 kg and you get x = 2.25m. So to balance the apparatus, you should place the 200kg object 2.25 meters from the fulcrum. You do the same exact thing for the second problem. The torque for the first side is 12lb * 8 in. = 96 lb.in. So the second half of the scale need to have the same torque, 96 lb.in. Your equation is 18 lb * x in. = 96 lb. in. Divide both sides by 18 lb and you should get 5.33 in. So to balance this apparatus, you should place the 18 lb. 5.33 inches from the fulcrum.
How to do these math questions?
Santi here it is The inland taipan of central australia is the world's most toxic venomous snake. Just 1 mg of its venom can kill 1000 mice. One bite contains up to 100 mg of venom. About how many mice could be killed with just one inland taipan bite? Given: 1 mg = 1000 100 mg = m m = number of mice killed 100/1 = m/1000 m = 100 x 1000 ===================================== Ans:::m 100,000 mice killed ===================================== A rattle snake grows a new rattle segment each time it sheds its skin Rattlesnakes shed their skin an average of 3 times per year However segments often break off. If a rattlesnake had 44 segments break off in its life time and it had 10 rattles when it died about how many years did the rattlesnake live? Given: segment = skin sheds 3 segment = 3 skin shed / year Since it is not given as to how many rattles it have per year. So i will just steak to the segments. 44 segments break off is equal to the number of segment growing b = number of rattle born per year rattle snake life span = 44/3segment /year + number of rattle/number of rattle born per year rattle snake life span = 14.67year +(10 rattle)/b ======================================... Rattle Snake Life Span = 14.67 + 10/b ======================================... All snakes shed their skin the shed skin of a snake is an average of 10% longer than the actual snake. If the shed skin of a coral snake is 27.5 inches long about how long is the coral snake? Length of Shed = 10% longer than the actual. S = Length of Snake. Shed Skin x 10% + Shed Skin = Length of Shed Skin 10%S + S = 27.5 0.1S + S = 27.5 1.1S = 27.5 S = 27.5/1.1 ===================================== Ans::S = 25 inches long ===================================== hope this helps
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i don't get how to do these math questions 240% of 3500 is x 19 is 7.5% of x what is the rate discount of a tape deck regularly priced at $200 if it sells for $175. The suggested retail price of a football is 65$. During a fall sale a discount of 15% was offered. what is the (a) discount and (b) the sale price of the football? After receiving a dicount of 20%, kelly paid $48 for a baseball glove. what was the regular price of the glove i have trouble with these ?s and i can't seem to figure it out please help
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1. what is this =, <, or > to make a true statement. 5/7___ 0.704 2. Divide. 3 2/5 divided by 5/8 3. Which item is the lowest cost per pound? 2lb bananas at 0.46 3lb oranges at 0.66 4lb pinapple at 1.00 4. Choose the most reasonable unit of measurement for the width of a computer screen. 54mm 54cm 54m 54km 5. If Ben drove 83.2 kilometers, how many miles did he drive? (1 mi = 1.6 km) 6. Solve. 6 cubic feet= __________ cubic inches 6 cubic feet=___________ cubic yards 7. Find the equivalent Celsius temperature to the nearest degree. 85F
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Take this one step at a time. take the 19 people that like to cook main dishes and subtract the ones that also like to bake desserts. 19-7. you get 12 to answer the next part of the question you take the 19 people who like to cook main dishes and add the 15 people who like to bake desserts. then you subtract the 7 people who were repeated. 19+15-7. you get 27. you take the total amount of people that were surveyed and subtract 27. 30-27. you get 3.
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19 like to cook main dishes - 7 like to do both = 12 really like to cook main dishes 15 prefer to bake - 7 like to do both = 8 really prefer to bake 12+8 + 7= 27 people 30 people in a life class - 27 people that like to cook and bake and both = 3 people that don't like to cook and bake.
How can I get the math 2018 CBSE question paper?
CBSE previous year question paper is one of the key tools that can help students to score good marks in CBSE final board examination and as you know maths requires a lot of practice and to do the practice you can solve the NCERT book questions and the previous year maths question paper. TheDownload CBSE 2018 MATHS Question paper for class 12 - 10 Years Question Paper: Mathematics Question Paper for CBSE Class 12 - 2018Download CBSE 2018 MATHS Question paper for class 10. - https://www.10yearsquestionpaper...This are some tools that 10 years question paper try to provide to the students of Delhi and Outside Delhi India (all region) preparing for 2018-2019 CBSE mathematics Board Exam. “FOLLOW YOUR DREAMS BELIEVE IN YOURSELF AND DON’T GIVE UP. “
How and why do you get the answers to these math questions?
"How" : using the right methods, which, in general, are many."Why" : seriously?Because you took the time to ask, I gave a try at the 9th question :[math] \sqrt{\frac{7}{3}+\sqrt{5}}[/math] : which is of the form [math]A\sqrt{B}[/math], with A = 1 and B = [math]\frac{7}{3}+\sqrt{5}[/math].But I am inclined to follow Bjarke point of view.Edit : detail of my answer.Let a = [math]\frac{\sqrt{10}+\sqrt{2}}{\sqrt{15}-\sqrt{3}}[/math].Factorize using [math]\sqrt{10}=\sqrt{2}\sqrt{5}[/math] and [math]\sqrt{15}=\sqrt{3}\sqrt{5}[/math], and one obtains a = [math]\frac{\sqrt{2}}{\sqrt{3}}\frac{\sqrt{5}+1}{\sqrt{5}-1}[/math].Simplify the second part by multiplying numerator and denominator by numerator, and use the identity [math](a+b)(a-b)=a^2-b^2[/math], to end with a = [math]\frac{\sqrt{2}}{2\sqrt{3}}(3+\sqrt{5})[/math].Now take a to the square, leading to [math]a^2=\frac{7}{3}+\sqrt{5}[/math].Taking back the root square, my first answer.So the how would be using the properties of square roots and one peculiar identity. The why would be to identify from the question that a good way to proceed is to guess that a is a root of a quadratic polynomial.