I am having a physics exam tomorrow and I haven't studied yet. What to do?
I can understand that you’re worried. The first thing that you have to do is calm down. I had the same worry back when I was in my 12th grade. I had to study for a chemistry test and I hadn’t prepared. I just had the night to study. I was scared of failing. I hadn’t failed before but it seemed like I would. There was no way for me or so I thought. It took me an hour to realise something. I had an entire night! This was around 7 PM and I think the test was at 9 AM. So I had around 9 hours. If I spent 1 hours per chapter (I had eight) and spent five hours sleeping I could manage to scrape by. Then I decided to make a call. I called a friend and spoke for ten minutes. I had to distract myself a bit and calm down. I was fretting but speaking to someone and letting out my worries helped (I wouldn’t suggest talking to a classmate or you’ll just end up getting even more worried). Eventually I decided that it’s more effective to focus on the chapters I felt confident in and just skim through the others. In the end I did pass but not with flying colours.So,Stop worrying about the marksTake a deep breath, it isn’t the end of the world (even though it might seem so)Plan and allocate the time you have for each chapter (take the ones you find easy first and then tackle the harder ones)Sleep well for at least 7 hours (no amount of studying will be fruitful if you don’t sleep)Some chapters are more of theory and rote learning. If you’re good at that stuff then take those out first then try the others. You shouldn’t feel frustrated. If you are more mathematically inclined then do the sums first.Talk to someone who you feel relaxed aroundGo write the paper with a smile.Don’t worry about the results if they aren’t great but always know you gave it your best.
Physics formulas? 10 pts to most help!?
I have exams tomorrow and I need some help getting the formulas. If you know any of the formulas you would use to solve the problems please leave em. I dont need the answer just the formulas. I'll give 10 pts to whoever gives me the most useful info. Thanks. 1. Two objects are charged and their centers are separated by 18.9 cm. Object A is charged to 74 nC and object B is charged to 85 nC. What is the magnitude of the electrostatic force between them? 2. A physics teacher shoots a .30 caliber rifle at a 0.40 kg block of wood. The rifle and wood are mounted on separate carts that sit atop an air track (like a linear air hockey table--ie. frictionless). The 5.3 kg rifle fires a 20 gram bullet at 235 m/s in the positive direction. What would be the velocity of the rifle after the bullet is fired? 3.Calculate the magnitude of the linear momentum (in kg m/s) for the following cases: A proton moving with a speed of 5.10E+6 m/s, whose mass is 1.67e-27 kg.
Physics/ mechanics question, help needed.?
A puck of 0.2kg is placed on a smooth slope at 20 degrees to the horizontal and hit up the slope with an initial velocity of 4ms. The force that causes the puck to slide DOWN the slope is the force parallel to the slope. F = m * a F parallel = mass * g * sin θ Acceleration = Force ÷ mass = (mass * g * sin θ) ÷ mass Acceleration = 9.8 * sin 20° = 3.25 m/s^2 DOWN The puck accelerates at 3.25 m/s^2 DOWN the slope, as it moves UP the slope. So the velocity of the puck decreases 3.25 m/s each second as it moves UP the slope. That’s why the answer is negative. The initial velocity does not affect the acceleration, but it does affect the time required to stop. Friction force = μ * m * g * cos θ The friction force also causes the velocity of the puck to decrease as it slides UP the slope. Total force decelerating the puck = m * g * sin θ + μ * m * g * cos θ Total force decelerating the puck = m * g * (sin θ + μ * cos θ) Total force = mass * acceleration m * g * (sin θ + μ * cos θ) = m * a a = g * (sin θ + μ * cos θ) = 9.8 * (sin 20 + 0.5 * cos 20) = 7.96 m/s^2 Of course, the acceleration is negative, since both forces cause the velocity to decrease. a = -7.96 m/s^2 Forces which are in the opposite direction of the initial velocity should be considered negative. The direction of Force parallel is always DOWN the slope. Since the initial velocity is 4 m/s UP the slope, the direction of the friction force is DOWN the slope! The initial velocity does not affect the acceleration, but it does affect the time required to stop. Final velocity = Initial velocity + acceleration * time 0 = 4 + (-7.96) * t -4 = (-7.96) * t t = -4/-7.96 = 0.5025 seconds Distance = average velocity * time average velocity = ½ * (4+ 0) = 2 Distance = 2 * 0.5025 = 1.005 meters