I Need Help On A Math Question.

I need help with this math question.?

3-4i-5 = (9+ci) - 11
3-4i-5 = 9+ci -11
3-5-4i = 9-11 +ci
-2-4i = -2 - ci

You can see that in order for the equation to be true c=4.You can add the real numbers together.

I need help with this math question???

Fractions and decimal conversion is real simple!

5/11: Literally divide 5 into 11 and that will give you a decimal. That's probably the hardest of the problems you have on there.

0.4: Think of each space after the decimal point as a zero in your denominator (bottom part of the fraction). But don't forget that you're below one! That one wants to feel important so you have to make sure to add him into your denominator in the front spot. So since there is one point after your decimal point in this problem there is one zero. The four is in the tenths spot. Thus, it would be 4/10.

1/2: This one is real easy. I like to use money to teach this one. You have a dollar. That's $1.00 Notice the decimal point and the two zeros after it. How much is half of a dollar? 50 cents! How would you write 50 cents? $.50 So, for this answer, it would be .5 (you can drop the zero at the end in decimals since a zero doesn't contain any value in that case)

0.44: This would be the same case as the 0.4 problem only this time there are two fours. So you have two spots after the decimal. That means there are two zeros. Don't forget that one wants to feel important still! So add the one in the front spot on the denominator and it will be 44/100.

Good luck! I hope this helps! I don't know if you have to simplify the fractions. Your question didn't say that so I didn't go into that detail!

I need help with a math question!! HELP!?

Ok, I looked at your formula for a minute, and you don't used that formula how it is written. The 2(pi)r^2 is for the top and bottom of the cylinder (obviously a half-pipe does not have a top and bottom surface). So you need to discard that whole part. Which leaves you with 2(pi)rh, which is the cylinder complete side (obviously a half-pipe is only half a cylinder so you only need half of the side).

Therefore, the formula you need to use is: (pi)rh.
Therefore the answer is (250)(18)(pi)
=14,137 sq feet

In response to your additional details:

Not sure why you added additional details when I supplied the correct answer (the answer you even gave). You gave the formula for the entire cylinder which is 2(pi)rh + 2(pi)r^2.

If you notice the (pi)r^2 is area of a circle. For a cylinder it is multiplied by two because a cylinder has two circles (a top and bottom). But a half pipe does not have any top or bottom surface area, so this part of the equation must be discarded.

Now you are left with 2(pi)rh. This is the SA for the entire side of a cylinder. And like you said it’s a halfpipe, therefore this must be divided by two. Therefore you are left with (pi)rh. Plug in r and h you get the answer that matches your book.

Need help with this math question.?

Update: Corrected Mistakes
The shaded area is composed of two triangle
One of area = (1/2)bh = (1/2) (x+3)(x+1)
why height = SP , base = PQ
One of area = (1/2)bh = (1/2) ( x+3) ( x+2)
why height = SP , base = (1/2) (2x+4) = x+2
85 = (1/2)(x^2 + 4x + 3) + (1/2)(x^2 + 5x + 6)
85 = x^2 + 4.5x + 4.5
=== This is a quadratic
0 = x^2 + 4.5x - 80.5

To solve it , multiply by 2 first to have integer
0 = 2x^2 + 9x - 161

x = (-9 +/- sqrt(81 -4(2)(-161) ) / 4
x = (-9 +/- sqrt(1369) ) / 4
x = (-9 +/- 37 ) /4
x cannot be negative
x = -9/4 + 37/4 = 28/4 =7
== answer
x = 7 cm

I need help on this math question?

Let A be the annual payment on the loan.
n = 30 years
q = 1/(1+r) = 1/1.07

It can be shown that the present value of all 30 payments
= A * (1-q^n) / (1-q)
This must be equal to 300,000
So A *(13.278) = 300000
A = $22,594.32

Total payments = 30*A = $677,829.56
We have to add to this the initial downpayment of $75000
In all the bank made 677,829.56+75000-300000
= $452,829.56
= 1.21 times the cost of the house

I need help with a math question?

A certain concrete mixture contains 5.00% cement and 7.00% sand (see the figure below).

How many kilograms of this mixture and how many kilograms of sand should be combined with 215 kg of cement to make a batch that is 15.0% cement and 17.0% sand? Carry out all calculations exactly and round to three significant digits final answers only.

Need Help with some math questions??

1(A) 1 L = 1000 cm^3 therefore 2L = 2000 cm^3
1(B) 1 L = 1 Kg therefore 2L = 2Kg

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2)
Two thirds less than half of what number is five sixths
(1/2)X - (2/3) = (5/6)

multiply every term by 6
3x - 4 = 5

add 4 to both sides
3x = 9
x = 3

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3)
volume of a cube = side^3 = 12^3 = 1728 cubic inches
volume of square pyramid = (1/3)(b^2)(h)
where b = 12 and h = 8 (because the total height = 20)

v = (1/3)(144)(8) = 384 cubic inches

total volume = 2112 cubic inches

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4)
we do not know the relation ship between the segments, if they form a line, if they form a right triangle, or if they lie on top of each other....

if they form a line segment, where "b" is between "a" and d", then the total meximum length is 12 + c. if they lie on top of each, then they have a minimum distance of |12 - c| (absolute value of 12 - "c")

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5)
you would need (1 x 10^3 or 1000) to form 1 meter multiplied by 1000 to form 1 KM
1000 x 1000 = 1,000,000 or 1 x 10^ 6

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6)
x^2 + x : GCF = x
x(x + 1)


12m^2n^3 + 18mn^2 - 24m^2n^3
12m^2n^3 and 24m^2n^3 are like terms
therefore

= -12m^2n^3 + 18mn^2

GCF = 6mn^2

6mn^2(-2mn + 3) or 6mn^2(3 - 2mn)

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7)
-2 2/3w - 1 1/3 = 4

add 1 1/3 to both sides

-2 2/3w = 5 1/3

= -(8/3)w = (16/3)

multiply both sides by -(3/8)

w = -2

OK my sister needs help on a math question?? please help!?

Heptagon, sum of the angles is 900 degrees