If you wish to lose weight, you may rub a balloon on your head. If you charge the balloon to a charge of q = -?
If you wish to lose weight, you may rub a balloon on your head. If you charge the balloon to a charge of q = -1.23µC, how much weight did you lose? The mass of an electron is 9.11 × 10-31 kg. 7.69 × 10-17 kg 7.00 × 10-18 kg 1.23 × 10-16 kg 7.41 × 10-25 kg 1.30 × 10-13 kg
How to find q for this balloon?
omygosh, You need to know the following relations: DeltaE = q + w q = heat supplied = amount x specific heat x temperature change. w = work done to system = - (work done by system) = - P DeltaV Therefore, q = (39.1 mole)*(20.8 J/°C*mol)*(38°C) = 30905 J = 30.9 kJ w = -(1 atm)* (998-876) = -122 L-atm But 1 L-atm = 101.3 J, so w = -122*101.3 = -12359 J = -12.4 kJ This is negative, since work is being done by the helium in the balloon. Depta E = q + w = 30.9 - 12.4 = 18.5 kJ Hope that helped!
If you wish to lose weight, you may rub a balloon on your head. If you charge the balloon to a charge of q = -1.23µC ..,?
how much weight did you lose? The mass of an electron is 9.11 × 10-31 kg and charge of an electron is - 6.101 × 10-19 C 7.27 × 10-24 N 6.87 × 10-17 N 7.54 × 10-16 N 1.21 × 10-15 N 1.28 × 10-12 N