How many milliliters of 0.165 M HCl are needed to neutralize completely 35.0 mL of 0.101 M Ba(OH)2 solution?
Moles Ba(OH)2 = 0.101 M x 0.0350 = 0.003535 Moles OH- = 2 x 0.003535 =0.007070 = moles HCl needed V = 0.007070 / 0.165 M = 0.0428 L=> 42.8 mL
In a titration experiment 50.0 mL of 0.375 M HI solution is required to neutralize 35.0 mL of Ca(OH)2 solution. What is the concentration of?
In a titration experiment 50.0 mL of 0.375 M HI solution is required to neutralize 35.0 mL of Ca(OH)2 solution. What is the concentration of the Ca(OH)2 solution?