MineCraft: What does my faction(clan) base need?
As a faction leader right now, my base has a farm, smelting room, enchanting room, cobblestone generator (lava and water), armory, public storage area, a mine, and many other things. I would definitely recommend a mine so that you can get resources (coal, iron, diamond, etc.) faster (sometimes) than exploring a cave. A farm is also useful so that you will have food for your faction. A bigger farm for a bigger faction, and a smaller farm for a smaller faction. Also, maybe have a public storage area where people can put cobble, wood, food, etc. for the others, and a personal room for each member that the others aren't allowed to go into where they have their personal chest(s). I also have a dining room with tables and chairs (which increase in number when someone new joins). I've found that it's best to have different ranks in your faction. For example, a miner, hunter, explorer, blacksmith, etc. You can set titles for person in your faction by doing /f title </br>An example of this would be /f title Legomann205 The_Master </br>You can only see the faction title in faction chat by doing /f chat f </br>In front of the person's name it will be *The_Master Legomann205: What should we do next? </br>This for me is very effective so that people aren't always asking you for things to do. they already have a specific job to do. </br>Other rooms that would be nice to have are a dining room, a kitchen, a war room, a bathroom, personal rooms for each person, crafting room, and a recreational room. Some other things to have would be traps around the base of the mountain so when enemies get washed down by the floodgates they will activate the traps and kill them. A doorbell would be fun to have. </br>If you have any questions about factions or if you want anymore ideas, then e-mail me at Legomann205@yahoo.com</p></section><section class="yan-answer"><p class="reply-topic">Really hard Quadratic Prob, PLEASE HELP!!!?</p><p class="reply-content">You'd need to first find an equation that describes using a formula the parabollic arch of the bridge. </br> </br>If you assume the lower left hand point of the bridge on the ground is the origin of an xy coordinate system, then then the parabola intersects the x-axis at x=0 and again at x=12 (units in meters). </br> </br>This means that the equation should have a form like x*(x-12) = y in order to have roots at the x=0 and x=12. </br> </br>You also know that the peak of the parabola is halfway under the bridge (x=6) at height y=6. You can use this to verify our initial guess of the equation. You'll see that the form actually needs to be (1/6)*x*(12-x) = y in order to have the roots given and be 6m high at the center </br> </br>rewrite: y=1/6*x*(12-x) = -1/6x^2+2x </br> </br>Now to figure out if the truck will fit, first find out what x is when y=3.2, since this is the minimum x location where the truck would have to be to fit under the bridge: </br> </br> </br> </br>=>3.2 = -1/6x^2+2x </br>=>-1/6*x2 +2x - 3.2 = 0 </br> </br>Use the quadratic equation to get </br> </br>x= [-2 +/-(2^2-4*(-1/6)*(-3.2))^0.5]/(2*(-1/6)) </br> </br>=>x=1.90 and x=10.1 </br> </br>These are the points on the bridge which are at the height of the truck. </br> </br>If you subtract the two you get a width of 10.1-1.90 = 8.2m </br> </br>Since this is smaller than the truck is wide, the truck should not fit. </br> </br>I hope this helps.</p></section> </article>
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