Perimeter: Solve for w in the formula for the perimeter of a rectangle, P = 2L + 2W?
Subtract both sides by 2L to get: P - 2L = 2W Finally, divide both sides by 2 to get: W = P/2 - L i hope this helps!
Use the formula p = 2L + 2w for the perimeter of a rectangle to solve for the missing variable?
Do simple substitution and solve for w.. 100 = 2(30) + 2w 100 = 60 + 2w 40 = 2w w = 40/2 w = 20 m I hope this helps!
The formula for the perimeter of a rectangle is P=21+2W solve the formua for W? What is the width of a?
P = Perimeter = 30 m L = Length = 8 m W = Width = unknown P = 2L + 2W for rectangles So, let us solve for W: P -2L = 2L + 2W -2L Subtract 2L from both sides: P-2L = 2W Divide both sides by 2 (P-2L)/2 = W or P/2 - L = W Now just plug in the values you know: (30 - 16)/2 = 7 or 30/2 - 8 = 7 W = 7
THE FORMULA FOR THE PERIMETER OF A RECTANGLE IS P=2L+2W.?
14 = 8 + 2L 6 = 2L L = 3 feet.
The formula for the perimeter of a rectangle is P = 2W + 2L Rewrite the formula to solve for the length?
P = 2W + 2L P - 2W = 2L L = (P - 2W)/2
Solve the formula for the indicated variable : P = 2l + 2w, perimeter of a rectangle.?
if solved for L then: (P - 2W)/2 = L if solved for W then: (P - 2L) / 2 = W That is the formula for the perimeter of a rectangle, so its already been done, unless you want to solve for the L or the width
If the formula for the perimeter of a rectangle is P=2L+2w,then w can be expressed as?
P=2L+2W subtract 2L from both sides P-2L=2W divide by 2 on both sides (P-2L)/2 =W rewrite the equation W= P-2L / 2
The length of a rectangle is 7 feet. If the perimeter is 42 feet, what is the width of the rectangle?
l : lengthw : widthp : perimeterp = 2*l + 2*wso w = (p-2*l)/2 = (42-2*7)/2 = 28/2 = 14 feetso eventually w is bigger than l so w is the length and l is the width
What is the area of a rectangle with a perimeter of 32, if its length is two larger than its width?
The area A of a rectangle is given by the formula: A = lw, where w = the width of the rectangle, and l = the length of the rectangle.The perimeter P of a rectangle is the distance around a rectangle and is given by the following formula:P = 2l + 2wSince the length l is 2 larger than the width, then we can write the following equation which relates l and w: l = w + 2Now, substituting P = 32 and l = w + 2 into the perimeter formula, we have:P = 2l + 2w32 = 2(w + 2) + 2w32 = 2(w) + 2(2) + 2w32 = 2w + 4 + 2w32 = 2w + 2w + 432 = 4w + 432 - 4 = 4w + 4 - 432 - 4 = 4w + 028 = 4w4w = 28 (Since equality is symmetric, i.e., if a = b, then b = a)4w/4 = 28/4(4/4)w = 28/4(1)w = 7w = 7Therefore, ...l = w + 2l = 7 + 2l = 9CHECK:P = 2l + 2w32 = 2(9) + 2(7)32 = 18 + 1432 = 32Therefore, the area of the given rectangle is:A = lw = (9)(7)A = 63 square units
If the perimeter of a rectangle is 10 times the width of the rectangle, then the length of the rectangle is how many times the width?
The perimeter P, i.e., the distance around a rectangle, is given by the formula: P = 2l + 2w, where l and w are the length and the width of the rectangle, respectively.Since the perimeter P is 10 times the width w, then we can write this as:P = 10w, andsubstituting into the perimeter formula, we get:10w = 2l + 2wNow, solving for l, we first subtract 2w from both sides of the equation as follows:10w- 2w = 2l + 2w - 2wNow, collecting like-terms on both the right and left sides, we get:8w = 2l + 02l = 8wNow, dividing both sides by 2 to isolate l and thus solve for l, we have:(2l)/2 = (8w)/2(2/2)l = (8/2)w(1)l = 4wl = 4wCHECK: P = 2l + 2w10w = 2(4w) + 2w10w = 8w + 2w10w = 10wTherefore, the length of the given rectangle is indeed 4 times the width, i.e., l = 4w.