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Is The Reaction Between Hcl And Na2co3 Exothermic

Is the reaction between NaHCO3 and HCl exothermic or endothermic?

Offhand, I'm pretty sure that this reaction is exothermic. You could always figure it out using Hess's law.
DH = sum(DHf products) - sum(DHf reactants)
NaHCO3 + HCl(aq)--> NaCl(aq) + CO2(g) + H2O(l)

The is the net ionic equation. These are the only ions and compounds for which you need to find the heats of formation (DHf).
HCO3- + H+ --> CO2(g) + H2O(l)

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By the way, just because a reaction is spontaneous doesn't make it exothermic. Spontaneity is given by Gibbs free energy. DG = DH - TDS.

Is the reaction between HCl and Na2CO3 exothermic?

Im doing a lab report, im pretty sure my calculations are correct, but all three of the problems ive tried are exothermic. not one is endothermic and that seemed a little odd to me! does anyone know if the reaction between HCl and Na2CO3 is exothermic?

Is the decomposition of baking soda endo or exothermic?

Julie,

Actually, since baking soda is NaHCO3, its decomposition would be
2NaHCO3(s) ---> Na2CO3(s) + H2O(g) + CO2(g). This is an endothermic reaction.

You can calculate the heat absorbed by taking the heats of formation:

Heat of reaction = ΔHf°(Na2CO3) + ΔHf°(H2O) + ΔHf°(CO2) - 2*ΔHf°(NaHCO3) = (-1130.8 kJ/mole) + (-241.8 kJ/mole) + (-393.5 kJ/mole) - 2*(-947.7 kJ/mole) = +129.3 kJ/mole; a positive value makes it endothermic.

Hope that helped!

Chemistry equations exothermic or endothermic?

both equations are neutralization reactions between basic salts and acids to produce salt,carbonivoxid and water.And a neutralization reaction can Proceed on it's own without any external supply of energy, so therefore it is an exothermic reaction.
NOTE
here an exothermic reaction is not necessarily defined in terms of heat gain or heat loss but in terms of spontaneity(ability of the reaction to go on on it's own)

10.5 g of Na2CO3 was reacted with excess HCl. What volume of CO2 gas is generated at 25oC and 780 torrs? Na2CO3 + 2 HCl ® 2 NaCl + H2O + CO2?

The Old Thermodynamist says:We have 10.5g of Na2CO3 which is 10.5g/106.0g/mol = 0.0991molSo the reaction is:0.0991Na2CO3+0.1982HCl=0.1982NaCl+0.0991CO2(g)+0.0991H2O(l)Change in Free Energy: ΔG(20C) = -9.6kJ (negative, so the reaction runs)Change in Enthalpy: ΔH(20C) = -1.8kJ (negative, so the reaction is exothermic)This reaction produces 4.361g (2.221L) of CO2 at STP.Using the Combined Gas Law,P1V1/T1 = P2V2/T2So 1 x 2.221 / 273.15 = 1.04 x V2 / 298.15V2 = 2.221 x 298.15 / (273.15 x 1.04) = 2.331LThe reaction produces 2.331L of CO2 at 25C (298.15K) and 780torr (1.04bar).

Endothermic or Exothermic?

it's exothermic.

the simple definition of exothermic is "giving out heat" and for endothermic is "absorbing heat".
so if the reaction is exothermic, the temperature of the overall reaction will be going up but if it's endothermic the temperature of the end reaction went down.

example for exothermic : burning fuels
when the fuels are burnt, it's releasing heat energy. that's why if you stand near fire, you will feel very hot.

example for endothermic : evaporation of water
when water evaporate, it changes state from liquid to gas. the liquid absorb heat from the surrounding to increase the kinetic energy between its molecules so it becomes gas.

sorry for the lousy words :) hope it helps!

What is the reaction of sodium carbonate and acetic acid? How does this reaction occur?

Sodium carbonate is a basic salt.. While acetic acid is acidic.. So neutralization reaction is carried out that leads to the formation of a salt,  sodium acetate and carbon dioxide and water is formed along with it

What is the reaction between sodium carbonate and nitric acid?

It’s a typical acid-base reaction:2HNO3 +Na2CO3 → CO2 + H2O + 2NaNO3End product is Sodium Nitrate in solution, plus plenty of carbon dioxide gas bubbles and water. The sodium and hydrogen cations essentially trade places, but the carbonic acid produced (H2CO3) dissociates into carbon dioxide & water due to the exothermic nature of the reaction, with the CO2 coming out of solution.

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