In Boolean algebra, is there any proof of A+BC=(A+B) (A+C) other than through truth tables?
LHS = A + BC = A.1 + BC ,using A.1 = A = A(1 + B) + BC ,using 1+B = 1 =A + AB +BC =A(1 + C) +AB +BC , using 1+C = 1 =A + AC +AB +BC =A*A + AC + AB + BC ,using A*A=A =(A+B) (A+C) =RHS