Maths genius' i need your help!?
Okay, I'm going to do (a), then I think you'll see how to do ther rest: (a) log5(x^2/y) = log5(x^2) - log5(y) = 2(log5(x)) + (-1)(log5y) = 2a - b (b) log5(25xsqrt(y)) = log5(25) + log5(x) + log5(sqrt(y)) = 2 + a + log5(y^(1/2)) = 2 + a + (1/2)log5(y) = 2 + a + (1/2)b
Math geniuses I need your help !!!!!!!!!!!!!!!!!!!!!!!!!!!!!!...
Alona told her son Frank to paint the fence. Frank whined and complained. So she said " OK, you dont have to do it today. Instead paint 1/2 of one board today. Tomorrow paint 1/3 of a board and 2/3 of a board. I dont care which board you paint. The next day paint 1/4 of a board, 2/4 of a board, and 3/4 of a board. That will cover 3 days; continue like that for another 22 days. I'll do the rest." If you add up all the boards Frank completed and the parts he painted, Frank paint the eqivalent of how many boards? Be sure to answer with steps/ exlpanation
Math geniuses I need your help, can you please help me with the following?
convert 0.015 g=_______mg I don't understand how to do this and frankly I am going to fail unless someone can explain it in really simple terms please and thank you.
Math geniuses, I need help?
So let's start off with: P(winning) = 1/9 P(losing) = 8/9 So we just took the ratio's and turned them into probabilities. Next you said that either getting a 1 or 2 will give us a winning probability. In other words: P(1 or 2) will win But P(winning) = 1/9 So P(1 or 2) = P(winning) = 1/9 Therefore P(1 or 2) = 1/9 Now, whenever we're dealing with probabilities with "OR" we can add probabilities (we would sometimes subtract the intersection but in this case we have to assume that it is impossible for a ball to be 1 AND 2 at the same time) We also have to assume that we're working with uniform probability here. What I mean by that is that the probability of getting a 1 or 2 is the same as the probability as getting a 3 or a 4 (think of a fair die: you have the same chance of rolling a 2 as you would a 4) So let's say we have n balls: 1,2,3,.....,n Then P(1 or 2) = P(1) + P(2) but P(1) = 1/n P(2) = 1/n So P(1 or 2) = 1/n + 1/n = 2/n But we also know that: P(1 or 2) = 1/9 So we can substitute to get: 2/n = 1/9 Cross multiply to get n=18 If we check it out, it works: P(1 or 2) = 2/18 = 1/9 P(not getting 1 or 2) = 16/18 = 8/9 Hope that helps!
Math/Algorithms geniuses need your HELP!!!?
The problem of searching for cycles in graphs arises naturally in financial trading applications. Consider a firm that trades shares in n different companies. For each pair i != j, they maintain a trade ratio Rij, meaning that one share of i trades fo Rij shares of j. Here we allow the rate R to be fractional: that is, Rij = 2/3 means that you can trade three shares of i to get two shares of j. A trading cycle for a sequence of shares i1, i2, ..., ik consists of successively trading shares in company i1 for shares in company i2, then shares in company i2 for shares i3, and so on, finally trading shares in ik back to shares in company i1. After such a sequence of trades, one ends up with shares in the same company i1 that one starts with. Trading around a cycle is usually a bad idea, as you tend to end up with fewer shares than you started with. But occasionally, for short periods of time, there are opportunities to increase shares. We will call such a cycle an opportunity cycle, if trading along the cycle increases the number of shares. This happens exactly if the product of the ratios along the cycle is above 1. In analyzing the state of the market, a firm engaged in trading would like to know if there are any opportunity cycles. Give a polynomial-time algorithm that finds such an opportunity cycle, if one exists. HINT: Bellman-Ford Algorithm I am completely lost on this problem. If someone would be kind enough to not only solve this but tell me how you solved it. Thanks
How do I beome a math genius?
weew2005, im not either that good in math though. because i simply don't like the subject, my attention was with other subjects like science, english, history etc. when it comes to math, i simply dont like the concept of the numbers mostly when its college math, however i have a goal that i need not to fail for the subject because i love my parents. they're the one whose paying for my tuition fees, besides, i don't to be genius or need a high grade, i just need a passing mark on math then focus the rest on other subjects where i can excel myself. another thing is that, what specific math are we talking about here? algebra? trigonometry? calculus? differential? etc, if your in high school level, math is way too easy to comprehend, you need to spend time learning it, even if you don't like it. college math? no comments, that's why i shifted my course from BS Electronics & Communications Engineering (which has all of the maths that i hated most) to BS Information & Technology (where math is not a priority but computer subjects) Did you get my point? God bless
How are math geniuses in real life?
I had a friend as an undergrad that was one year ahead of me and as a graduating senior received the Presidents Award for Excellence in Mathematics. This happened to be at one of the best private universities in the U.S. I'm not shabby when it comes to mathematics. In fact, I received a free ride to grad school in mathematics, but my friend blew me away. There was absolutely no way that I could keep up with him, but then there was no one that could keep up with him.This guy was nothing short of amazing when it came to mathematics. In class he was able to absorb the information presented during the lecture with ease. He never studied except for one or two hours on the night before an exam. This included both midterm and final exams. I asked him about his study habits. His reply follows:“I study one or two hours the night before a exam. Anything more would be a waste of time.”He was able to take what was taught in class and apply it in ways that surprised some of the professors. I was certain that he would go to grad school and eventually get a PhD in mathematics. There was no doubt in my mind that he was going to have an amazing career in theoretical mathematics. However, just a few days prior to graduating he told me that he was moving to Africa to teach high school mathematics. I graduated the following year, but never heard from him. However, I will always remember him.
Need Math Statistic Genius for help!?
Some games of chance rely on tossing two dice. Each die has six faces, marked with 1, 2, . . . , 6 spots called pips. The dice used in casinos are carefully balanced so that each face is equally likely to come up. When two dice are tossed, each of the 36 possible pairs of faces is equally likely to come up. The outcome of interest to a gambler is the sum of the pips on the two up-faces. Call this random variable . If all pairs have the same probability, what must be the probability of each pair (assuming that we distinguish between, e.g., "(1,2)" and "(2,1)")? Answer is 3 decimal places.
I NEED a mathematical Genius PLEASE help me.....?
If you invest, say, $1000 at 7%, the interest is 1000 x (7/100) = $70 So if you invest $x thousand (note I work in thousands to make the numbers a bit simpler), then the interest will be $x x (7/100) = 0.07x And if $x thousand are invested at 7%, that leaves $(16 - x) thousand to invest at 5%, therefore interest will be $(16 - x) x (5/100) = 0.05(16 - x) The total interest is $970, but since we are working in thousands, this must be written as 0.97 thousand. So, 0.07x + 0.05(16 - x) = 0.97 0.07x + 0.8 - 0.05x = 0.97 0.02x = 0.17 x = 0.17/0.02 = 17/2 = 8.5 which is 8.5 thousand of course, or $8500 So $8500 is invested at 7% Check : 7% of $8500 = $595 and 5% of $7500 = $375 $595 + $375 = $970.