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... . . . 4.85 g . . . . . . . . . . . . . . 14.7 g . . 2C4H10 . + . 13O2 . → . 8CO2 . . + . 10H2O (58.12g/mol) . . . . . . . . (44.01g/mol) 0.08350mol . . . . . . . . . 0.3340mol . . . . |_____1 to 4________| so 4.85 g of C4H10 When you get a good response, please consider giving a best answer. This is the only reward we get.
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1. What volume of water is needed for 0.196 mol of CdCl2 to prepare a 3.91M solution? You should not be asking this question because it cannot be answered. You do not prepare a molar solution by taking a known mass or moles of solute and adding some volume of water , What you must ask , and which can be answered is: What volume of 3.91M solution must be prepared which contains 0.196 mol CdCl2 3.91M solution of CdCl2 means 3.91 mol CdCl2 in 1000mL solution You have 0.196 mol CdCl2 Volume of solution = 0.196mol / 3.91 mol /L * 1000mL/L = 50.1mL Final volume solution = 50.1mL NOTE: This is NOT the volume of water that must be added to the 0.196 mol CdCl2 2. Calculate the number of moles of KClO3 which would be needed to prepare 20.0 mL of a 0.010 M solution? 0.010M solution meaqns 0.010 mol in 1000mL solution mol of KClO3 to prepare 20.0mL of 0.010M solution = 20.0mL / 1000mL/L * 0.010mol/L = 0.0002 mol KClO3 3. To what volume would you have to dilute 4.00 moles of NaOH in order to have 0.10 M solution? 4mol NaOH in 4.0L solution = 1.0M solution You want 0.10M solution . Dilute 10X - final volume = 4.0L * 10 = 40.0L 4. To what volume would you have to dilute 10.0g NaOH in order to make .20 M solution? (Converting to moles first) Molar mass NaOH = 40g/mol mol NaOH in 10.0g = 10.0g/40g/mol = 0.25 mol NaOH Volume of 0.20M solution = 0.25mol / 0.20mol/L / 1000mL/L = 1,250mL solution.
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11.classify each of the following as a physical change or a chemical change a]frying an egg b]percolating coffee c]letting paint dry d]toasting bread e]letting cement set f]growing a plant 12.classify each of the following samples of matter as an element,compound,solution,suspension,mec... mixture or colloid a]egg b]mercury c]ketchup d]detergent e]fog f]sand g]18 carat gold h] hair conditioner i]$2coin j]compost k]copper l]muddy water
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Lancenigo di Villorba (TV), Italy The reaction involved follows CO2(g) + H2O(l) ---> H2CO3(l) Since you said me that Water is IN EXCESS, so Carbon Dioxide results as the Limiting Reactive. In this fashion, Carbon Dioxide determines the obtained Molar's Amount of Carbonic Acid. The stoichiometric relationships CO2 : H2CO3 = 1 : 1 so 2.57 moles give 2.57 moles I hope this helps you.
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Either method II or method III would work in theory. However, an electronic balance is not usually designed for weighing things the size of rocks. So the correct answer is II.
I really need help with this chemistry question. Atoms to moles.?
There are 6.02 X 10^23 atoms in a mole.... so::: 13.21 X 10^22 atoms --------------------- 6.02 X 10^23 atoms/mole = 0.219 mole
I need help with this chemistry question; i keep getting the wrong answer.?
Density = Mass / Volume OR D = M / V Your'e looking for V, so re-arrange the above equation: D = M / V so V = M / D Now plug and chug: V = 5.00g / (1.48 g/cm3) V = 3.37 cm3
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so here is the question... when surface water dissolves carbon dioxide, carbonic acid (H2CO3) is formed. When the water moves underground through limestone formations, the limestone dissolves and caves are sometimes produced. CaCO3+H2CO3==>Ca(HCO3)2 what mass of limestone must have dissolved if 3.05 x 10^10kg of calcium hydrogen carbonate was produced?
Chemistry question: Please HeLp!! :) Thanks?
A student prepares a salt solution by dissolving 85.638 g of NaCl in enough water to form 237 cm3 of solution. Calculate the number of grams per cubic centimeter of solution
Chemistry questions plzz help me i really need to know ...?
So long as it's only 4 questions and not 10: 10. First you need a balanced chemical reaction. Reading your question Hydrogen and Nitrogen combine to make NH3 so: H2 + N2 -->NH3 Balance: 3 H2 + N2 --> 2 NH3 Next, if you have 5.39 moles of H2 in this reaction, look at the coefficients (number in front of the molecule) to tell the story. In this reaction, every 3 moles of H2 makes 2 moles of NH3. So the number of moles of H2 times 2/3 is the moles of NH3. In your question then, 5.39 moles * (2/3) = 3.59 moles. If you have any trouble getting the ratio, remember, it's always what you want divided by what you begin with. 7. Again, a chemical reaction is needed: KClO3 --> O2 + KCl Balance: 2 KClO3 --> 3 O2 + 2 KCl In this case you have 26 mol O2 and you want to find moles of KClO3. Well, there are 2 KClO3 for every 3 O2, so the ratio is 2/3. 26 mol O2 * (2 KClO3 / 3 O2) = 17.3 mol KClO3 It doesn't matter which side of the chemical reaction you go to or from, it's always moles wanted divided by moles you begin with. 6. First, CCl4 means there are four Cl atoms in every molecule of CCl4. So: 4.17 * 10^20 * 4 = 1.668 * 10^21 atoms of Cl. If you're confused on this step, you can also think of this as a reaction: CCl4 --> C + 4 Cl So, 1.668 * 10^21 atoms of Cl, you need moles. Well, the number of moles = #atoms / 6.02 * 10^23 Moles = 1.668 * 10^21 atoms / 6.02 * 10^23 Moles = 0.00277 mol 5. This is a similar problem. 0.09 moles of H2SO4 has twice the number of hydrogen atoms in it: H2SO4 --> 2 H + S + 4 O using the same ratio: 0.09 moles * (2 H / 1 H2SO4) = 0.18 mol H And the same equation as before, the definition of a mol says that there is 6.02 * 10^23 atoms in a mol. 0.18 mol * 6.02 * 10^23 = 1.08 * 10^23 atoms of H I hope this helps. Remember a lot of it is understanding the ratios in chemical reactions. Once you understand the ratios you can take the moles of any one thing in a chemical reaction and find the moles of every other thing in the same reaction.