What will happen to simple pendulum set in motion on moon?
The force of gravity is less on the moon than on the Earth. Since the force of gravity is less on the Moon, the pendulum would swing slower at the same length and angle and its frequency would be less. Hence more time period .
One oscillation period of a pendulum equals the energy provided by the Earths rotation?
No, totally incorrect. The earth's rotation has nothing to do with the operation of an ordinary pendulum. It only needs a gravitational field to operate. And period, a time interval in seconds, cannot be equal to energy, measured in joules.
What is the time period of a seconds pendulum at the surface of the moon?
The question is slightly wrong. When we talk about a seconds pendulum, we already know that the time period is going to be 2 seconds. That is why we call it a seconds pendulum.So, in this formula, T is time period, l is the effective length of a pendulum and g is the acceleration due to gravity. On the surface of the earth, the effective length of a pendulum should be 99.2 cm so that its time period becomes 2 seconds and hence, we call it a seconds pendulum. When we go the moon, the acceleration due to gravity decreases. As acceleration due to gravity is inversely proportional to the time period, the time period shall increase. But we need to keep the time period equal to 2 seconds so we will have to decrease the length of the pendulum as the time period is directly proportional to the length. So the time period decreases and returns to 2 seconds.You can mathematically prove this by using the above formula. Take T as 2 seconds,g as 1/6 th of the acceleration due to gravity on earth and calculate the required length of the pendulum.
If you were conducting an pendulum lab experiment on the moon, how would the period be effected?
Simple pendulum http://en.wikipedia.org/wiki/Pendulum T = 2 pi sqrt (l / g) T - pendulum period where l is the length of the pendulum measured from the pivot point to the bob's center of gravity and g is the gravitational acceleration gearth = 9.8 m/s^2 gmoon = 1.622 m / s^2 http://en.wikipedia.org/wiki/Earth%27s_gravity because gmoon < gearth means that the period will increse
If a pendulum clock is taken to the moon, will it gain or lose time?
A simple pendulum oscillates at a period given by the expressionP = 2 pi sqrt(L/g),where L is the length of the pendulum and g is the acceleration of gravity. The mass of the pendulum bob does not enter. On the Moon the acceleration of gravity is less than it is on the surface of the Earth, so the period on the Moon will be greater than it would be at Earth’s surface. This results in fewer “ticks” of the clock in a given period of time. Therefore a clock on the Moon will run slower than an identical one on Earth. The Moon clock will lose time compared to the Earth clock.