Physics Help Asap I Can

Really Need help ASAP please! - physics?

firstly find the area of the triangle, this will give the total force produced.
using A=1/2base*height
I got A = 15,000N for this 30second period.
now using F=mv/t (from F=ma and a=v/t)
you can get the additional speed produced from:
15,000 = (415/30) *v
so, v = 15,000/(13.833...) = + 1084.3m/s
so the final speed is 1159.3m/s.
it reaches this speed at the 30second mark.

hope this helps

Physics! need help ASAP!!!!!!?

ok i have a physics question containing a chart but since i cant draw it here i'll just explain it so someone can draw it on a piece of paper. there are 3 columns and 3 rows.the column headings are Trial, Mass, and Accepted Value. now under TRIAL there are 3 rows that say 1, 2, and 3. Under MASS it says 23.26g, 23.18g, and 22.95g under Accepted Value it says 23.20g ?,?.
so, if you look at the chart from left to write it reads in the first row, 1, 23.26 g, and 23.20g
in the 2nd row 2, 23.18g, and a blank
in the 3rd row 3, 22.95 g, and a blank. so can someone please tell me how to fill out the two blanks? also, i need to find:
abs. error for trial 3
rel. error for trial 1
abs. deviation for trial 2
abs. deviation (average) for the data
and relative deviation for the data
so basically there are 7 questions to be answered in this problem please explain how you get the answer for each. thank you!

Physics help ASAP!!!!?

A box with a total surface area of 1.77 m2
and
a wall thickness of 2.83 cm is made of an insulating
material. A 7 W electric heater inside
the box maintains the inside temperature at
21.3
◦C above the outside temperature.
Find the thermal conductivity of the insulating
material.
Answer in units of W/m ·
◦ C

URGENT Physics Question? please help ASAP?

Let:
c=0.57
a=0.46
r=22.8
g=9.8
m:mass of copper block
W:Angular velocity.
It is clear that a blobk will start to slip only if cetrifugal force exceeds the friciotnal force provided by table. SO in order to maintain equillibrium frition shud balance centrifugal force:
Centrifugal Force=Frctional Force
mrW^2=cmg
W^2=cg/r
W=root(cg/r)
So if angular velocity is equal to W the block will just be in equillibrium.
ANgular Acceleration=W2-W1/t
So time taken to reach angular velocity W is
As it starts from rest: W1=0
t=W-0/a
t=W/a

Hence you can finfd 't'

Physics torque, dynamics, whatever it is... help asap please!?

A box of mass 5.6 kg, sits 3 meters from the right hand side of a 10 meter long beam (mass of 20 kg). The beam is supported on the left by a rope that is exactly .5 meters from the left end of the beam. On the very right edge, a man supports the beam on his head.

a) Determine the normal force by the man's head on the beam
b) Find the tension of the rope
c) The rope will break if 150 N of force is applied to it. If we slide the box to the left, the tension in the rope increases. How far can we slide the box (from its starting position) before the rope breaks?

Catch up problem Physics help ASAP!!!!!!!! Pleaseee?

First convert 100km/h into m/s

(100km/h) * (1000m/km) / (3600s/h) = 27.78 m/s

Let's say that the distance they will both travel before the cop catches up is x. This will be equal to both the speeder's constant speed times the time elapsed, and also equal to the equation:
Distance = Initial Velocity * Time + 1/2 Acceleration * Time²

So,
x = (27.78m/s)t, and also x = 0 + (1/2) (3.6m/s²)t²

27.78t = 1.8t²

t = 15s
This is your answer for A)

The distance travelled will be (27.78m/s)(15s) = 429m.
This is your answer for B)

The speed of the police car will be Initial Velocity + Acceleration * Time
= 0 + (3.6m/s²)(15s) = 56 m/s
This is your answer for C)

As to whether this is reasonable, 56m/s translates to 202 km/h, so no, this isn't reasonable.

To recap:
A) 15s
B) 429m
C) 56m/s (or 202km/h), not reasonable

PS You forgot to click "best answer" on my answer to your last question, where you thanked me xD

Buoyant Force-Physics Question. I am so lost ...need help asap.?

Nice hat. You have good taste :)


1. Since the cube is floating, the buoyant force on the cube will be equal to the weight of the cube.

Buoyant force=Weight of the cube=density of water X 9.8 (since we are considering a 1 meter cube, density is equivalent to mass)

density of water=1.0x10^6kg/m^3

2. Buoyant force acting on the balloon = weight of air displaced = density X volume of the balloon X g

the volume is (4/3)x(pi)x(r^3)
the air density is 1.2 kg/m^3
g=9.8 m/s^2

Look at this:

http://www.ac.wwu.edu/~vawter/PhysicsNet/Topics/Pressure/BouyantForce.html
r=.500 m
pi=3.14

Net force on balloon = Buoyant force - weight of balloon

Since you should have calculated the buoyant force, the weight of the balloon is all that is needed.

weight of balloon=weight of helium inside+weight of empty balloon

helium weight = volume of balloon X .179 X 9.8

empty balloon weight = .012 X 9.8


I hope this makes sense. Basically, buoyancy is a force that opposes the weight of an object. It makes the object seem lighter. The eq. for buoyancy is easy to remember if you realize that it is just the weight of the fluid (gas, liquid, etc...) displaced by the object.