Urgent: I need help with this physics problem?
Two masses are joined together by a massless, inextensible string. A vertical force of 30 N applied to the upper mass gives the system a constant upward acceleration of 3.2 m/s^2. If the tension in the connecting string is 18 N, what is the smaller of two masses? If the tension in the connecting string is 18 N, what is the bigger of two masses? The lower block can be solved for by: T/(g+a) = M which is 1.4kg but I can't get the value of the upper block(which I know should be smaller then 1.4) M=(F+T-ma-mg)/(a+g) F=30 T=18 m=1.4 a=3.2 g=9.8 when I do this M= 2.3 but it should be smaller then 1.4 because I know 1.4 is the larger block.
Physics Energy Problem?
the first question was "With what minimum speed must you toss a 160g ball straight up to just touch the 10m--high roof of the gymnasium if you release the ball 1.7m above the ground? Solve this problem using energy." for this problem, I subtracted 10-1.7 and got 8.3 as the actual height. then i used the equation PE=mgh where m=160 g=9.81 h=8.3. so 160*9.81*8.3 gave me 13027.68J. since i know that PE=KE, I used the equation KE=1/2mv^2 next. m=160 KE=13027.68 v^2 =? so SQRT(13027.68/160) gave me 13m/s. Therefore, the answer to this is 13 m/s. the second question is "With what speed does the ball hit the ground?" i don't know how to answer this one.
Urgent Physics Problem?
A 100.0 m long rod with a diameter of 3.0 mm has a charge of 1066 C. What is the approximate electric field 3 mm from the surface of the rod, not near either end? (The constant ε0 is 8.85 × 10^-12 C^2/N∙m*2.) 3.4 × 10^11 rˆ N/C 4.3 × 10^13 rˆ N/C 2.6 × 10^13 rˆ N/C 3.0 × 10^11 rˆ N/C Those are the 4 answer choices. 10 Points!
Physics Problems (Urgent!)?
Convert: 1. 2.5 days to seconds 2. 35 km to millimeters 3. 43 cm to kilometers 4. 22 mg to kilograms 5. 671 kg to micrograms 6. 8.76 x 10^7 mW to gigawatts 7. 1.753 x 10^-13 seconds to picoseconds
Physics Net Displacement! Urgent Need Help!!?
What you need is a straight line distance from start to end positions. If you sketch it all out, you can add the east directions together, then subtract the west directions for a net east displacement, so (75 + 98 + 6) - 2 = 177m. east. Now do the same with the south and north parts. (13+ 8) - 5 = 16m south. From there, sketch a right triangle, with the base 177m., and a height (in a south direction) of 16m. The length of the hypotenuse is the net displacement. Either trigonometry or Pythagoras' theorem will determine this, Pythagoras is faster. Sqrt. (177^2 + 16^2) = 177.72m., the direction S of E. If you need the angle, trig (tan) will give you that.
Please help with these 3 Physics problems?
1. A 1857 kg car rounds a circular turn of radius 21 m. The road is flat and the coefficient of friction between tires and road is 0.58. The acceleration of gravity is 9.8 m/s^2. How fast can the car go without skidding? Answer in units of m/s. 2a. An air puck of mass 0.026 kg is tied to a string and allowed to revolve in a circle of radius 1.9 m on a frictionless horizontal surface. The other end of the string passes through a hole in the center of the surface, and a mass of 1.1 kg is tied to it, as shown. The suspended mass remains in equilibrium while the puck revolves on the surface. What is the magnitude of the force that maintains circular motion acting on the puck? The acceleration due to gravity is 9.81m/s^2. Answer in units of N 2b. What is the linear speed of the puck? Answer in units of m/s. Thank you!
MAGNETISM AP PHYSICS PROBLEM?!?!? PLS HELP?
MAGNETISM AP PHYSICS PROBLEM?!?!? i think the formulas u need to use are r=mv/qB or m=er^2B^2/2v ....or maybe none of those...lol i have the answer...( 1.63 x 10^ -2m) but not sure how 2 get to it..... Two isotopes of carbon, carbon-12 and carbon-13 have masses of 19.93 x 10^ -27kg and 21.59 x 10^ -27kg. These two isotopes are singly ionized ( +e ) and each is given a speed of 6.667 x 10^5 m/s. The ions then enter the bending region of a mass spectrometer where the magnetic field is 0.85 Tesla. Determine the spatial seperation (d) between the two isotopes after they traveled through half a circle.... the answer is 1.63 x 10^ -2 meters....any ideas?
How do I solve physics problems faster?
PracticeI am sorry if this sounds like an extremely generic advice which everyone gives but there is a reason for its ubiquity. Doing anything fast is a skill. Skills are always perfected via practice. For example, learning addition of numbers is not a skill, it's gaining knowledge. Learning addition of numbers fast is a skill.Try finding the sum of these numbers,6+7+2+5+5+4+8+3 = ?If you have learnt addition of number recently, you will take some time to do this. But since we have added sequence of numbers from our childhood, we can see a pattern here. In our mind once we restructure this sequence like this, it becomes easier to add.6+4+7+3+8+2+5+5 = 40This idea of converting them to multiple of 10's comes with practice. Same is the case with JEE problems, speed comes with looking for patternsin a similar set of problems. You learn to look for such patterns by solving a vast amount of problems. So practice.All the best!
Physics - Homework Help. Extremely Urgent. All Help Appreciated?
tennis racket slows down because some of its energy is transferred to the ball. conservation of energy the ball changes its direction when hit and as well as its speed. this requires lots of energy that can only come from something hitting it. pushing a book while at rest depends on the surface and on the material. normally the force required to push any object from rest is greater than pushing object that are moving. this is because of static friction. even a large force if it can't overcome the static friction cannot move anything. the book could also stay at rest if the force is not enough to overcome the static friction. the force exerted by the cord on the ankle is the same as the force exerted by the ankle on the cord. newton's third law of equal and opposite reaction
A tricky physics problem could someone please help me?
You don't provide quite enough information. A torque is a force multiplied by a length. In your case, you need to know the size of the wrench. Suppose the wrench is 1 meter long, then the force will be 41 Newton. A normal wrench will be 25 cm and the force will be 164 Newton.