Algebra 2 math question about sequences, help!?
Here is the question straight from the homework: 1. Determine whether or not 447 is a term of each sequence below. If so, which term is it? a.) t(n) = 5n - 3 b.) t(n) = 24 - 5n c.) t(n) = -6 + 3(n - 1) d.) t(n) = 14 - 3n e.) t(n) = -8 -7(n - 1) ...I dont need ALL the answers, i just really need a good explanation on how to do a couple of them so i can get the hang of it...if you can help me out id be reaaaally grateful<3 please and thank you(:
Algebra 2 question on sequence and series?
1) Well, 1 + 2 + 4 + 8 + . . + 64 is equivalent to 2^0 + 2^1 + 2^2 + 2^3 + . . + 2^6 In sigma notation, this can be represented as 6 ∑ 2^n n=0 2) One day = 24 hours. We can represent the problem as a geometric series with a = 3 million, r = 2 (since population doubles in size every 4 hours) and n = 24/4 = 6 S(sub6) = a(r^n - 1)/(r - 1) = (3)(2^6 - 1)/1 = 189 million After 24 hours, the population will be 189 + 3 = 192 million.
Algebra One Question terms sequence?
Here is your error: "i got you times 648 by .5 which equals 216" 648 x .5 = 324, not 216 But, 648 x 1/3 = 216 So, each number in the series is 1/3 of the previous number. 648 x 1/3 = 216 216 x 1/3 = 72 72 x 1/3 = 24 24 x 1/3 = 8 8 x 1/3 = 8/3 = 2.67 8/3 x 1/3 = 8/9 = .89 Answer number one is the closest to correct. 8/3 is actually: 2.6666666..., which rounds to 2.7, but close enough.
Algebra 2: Geometric Sequences Question?
If the sequence is geometric then there is some r such that a11/a6 = r^(11 - 6) 4096/-128 = r^5 r^5 = -32 so r = -2 a6/a1 = r^5 a1 = -128/-32 = 4 a2 = a1*r = -8 a3 = a2*r = 16 a4 = a3*r = -32 a5 = a4*r = 64 a6 = a5*r = -128 etc.
Algebra 2 question -- geometric and shifted geometric sequences?
Okay, so I get that geometric sequences make curved graphs and arithmetic sequences make linear graphs, but how do you tell a shifted geometric graph from a geometric graph? Here's the problem I'm working on: http://img687.imageshack.us/img687/1740/wutz.png
Algebra 2 Question? It's about Geometric Sequences?
If you work out a few examples it will make sense... If r= 5; and the first term is 7; 7, 35, 175, ... You multiply by r to get to the next term. To find the 10th term you will start with 7 and multiply by 5 , 9 times I hope this helps!
Algebra Questions:Arithemtic sequence series and Geomatric sequence series?
1.) an = a1 + d(n - 1) a2 = 12 + d(2 - 1) 10 = 12 + d d = -2 a3 = 12 + d(3 - 1) 8 = 12 + 2d 2d = -4 d = -2 an = 12 - 2(n - 1) an = 12 - 2n + 2 an = -2n + 14 The common difference is 2. --------------------------------------... 2.) a2 = 3 + d(2 - 1) 10 = d + 3 d = 7 a3 = 3 + d(3 - 1) 17 = 3 + 2d 2d = 14 d = 7 Formula : an = 3 + 7(n - 1) a15 = 3 + 7(15 - 1) a15 = 3 + 7(14) a15 = 3 + 98 a15 = 101 --------------------------------------... 3.) a2 = 2 + d(2 - 1) 5 = 2 + d d = 3 a3 = 2 + d(3 - 1) 8 = 2 + 2d 2d = 6 d = 3 an = 2 + 3(n - 1) a10 = 2 + 3(10 - 1) a10 = 2 + 3(9) a10 = 2 + 27 a10 = 29 Sn = (n/2)(a1 + an) S10 = (10/2)(2 + 29) S10 = 5(31) S10 = 155 --------------------------------------... 4.) an = a1 * r^(n - 1) an = 2 * r^(2 - 1) a2 = 2 * r^1 2r = 6 r = 3 a3 = 2 * r^(3 - 1) 18 = 2r^2 9 = r^2 r = 3 an = 2r^(n - 1) a10 = 2(3)^(10 - 1) a10 = 2(3^9) a10 = 2(19683) a10 = 39366 --------------------------------------... 5.) Sn = (a1(1 - r^n))/(1 - r) S12 = (5(1 - 3^(12)))/(1 - 3) S12 = (5(1 - 531441))/(-2) S12 = (5(-531440))/(-2) S12 = (5(265720)) S12 = 1328600
Algebra 2 question from Series & Sequences chapter. Please help.?
it's a geometric sequence, with a CR of 2. sooo.... 1(2)^(20-1) b/c of the explicit formula of an=nr^(n-1). Just plug all of that into a calculator.
Can someone answer these sequences and series questions for me its algebra 2?
1.c 2.d 3.d 4.a 5.b 6.c 7.a 8.d 9.b 10.b 11- 12.a 13.b 14.c 15.c 16.d 17.a 18.- 19.b 20.c 21.a 22.b 23.c 24.c 25.c Hope they're right just contact me at christine_baduria@yahoo.com if you need help.
Stuck on algebra problem for sequence...?
4 - 2 = 2 8 - 4 = 4 This is not an arithmetic sequence (there is no common difference) 4 ÷ 2 = 2 8 ÷ 4 = 2 16 ÷ 8 = 2 This is a geometric progression (with common ratio = 2)