Series and parallel circuit - Determine the power supply?
For R2 and R3 in parallel the total resistance is half of one since they are both equal. Also, since that resistance will be half of R1 the voltage drop across R2 and R3 will be half that across R1. So you have V1 = 80 Volts and V2 = V3 = 40 Volts And Power is equal to voltage squared over resistance. P1 = 80^2/576 = 11.11 Watts P2 = 40^2/576 = 2.78 Watts P3 = 2.78 Watts For reference and greater understanding you can read about: Kirchoff's loop rule Resistors in parallel
What are the functions of series and parallel circuits?
Parallel and series configurations in circuits can have many effects. For all circuits, if the loads are connected in parallel, when one goes out, all of them go out. if one of the lamps dies in series, they all will no longer work since the lamp is directly a part of the other lamps' circuits. However in parallel, the lamps aren't connected to each other directly, and you can see that the wires going to the lamp on the far right don't pass through the lamp on the left on their path to it. In batteries and other voltage sources (e.g. transformers):When batteries are connected in series, the total voltage of them increases, by the amount of the voltage rating for individual batteries, but the capacity is that of one battery. Take two batteries rated at 3000mAh and 5VIf you connect two of them in series, the voltage will be 10V and the capacity will be 3000mAh, equal to one of the batteries alone. When batteries are connected in parallel, the total capacity of them increases, again by the amount of capacity for individual batteries, but the voltage is again still the same. Both series and parallel can be used at the same time, to increase the voltage and capacity. Say you have 10 100mAh batteries, rated at 2V. You want to have a power supply of 500mAh, at 4V. You can put the batteries in pairs of 2, in series, making virtually 5 4V batteries. Now you can wire these in parallel, since the "4V" sections are each 100mAh. Since there are 5 of the "4V" batteries, you can put these in parallel and since the total capacity is the individual capacity added up, the resulting capacity would be 500mAh, of 4V batteries. So in conclusion: Series: more voltageParallel: more capacity
What is the difference between a series circuit and a parallel circuit?
The difference between series circuit and parallel circuit.★ Series CircuitIn series circuit each resistor in the circuit are not directly connected to supply.In series circuit in, there is only one path through which current flow. So, the value of current in series circuit are same at each point.The voltage drop across resistor are different for different value of resistors and same for same value of resistors.The sum of total voltage drop across resistors are equal to emf source.The value of equivalent resistance is larger than the value of largest resistor connected in series circuit.If any resistor burn out the whole circuit will be disconnected from supply.★ Parallel circuitIn parallel circuit resistors are connected in end to end and directly connected to supply.In parallel circuit, the current is divided. Because, there are many Path through which current can flow.The voltage drop across each resistors are same for same value of resistors and different for different value of resistors.The current supply by the battery is equal to the sum of all current flow across each resistors in circuit.The value of equivalent resistance is lesser than the value of smallest resistors connected in parallel circuit.The current is not interrupted in circuit if any of resistor damage.
Finding an unknown resistor for series and parallel circuits?
Let the Resistor with known resistance value be named as X and with unknown value as Y. Let resistance of X be Rx and that of Y be Ry. Let voltage drop across X be Vx and across Y be Vy. Let the current through X be Ix and through Y be Iy. SERIES CIRCUIT: Same current flows in both the resistors, so Ix = Iy = say I. by Ohm's law, Voltage across resistor = current through the resistor * resistance of the resistor. Vx =IRx Vy = I*Ry So, Vy/Vx = IRy/IRx Vy/Vx = Ry/Rx Ry =Rx* Vy/Vx Unknown resistance value = Known resistance value*Voltage across unknown resistor/Voltage across known resistance. PARALLEL CIRCUIT: Voltage across both the resistors is same. So Vx = Vy = say V. By ohm's law, current through a resistor = Voltage across the resistor / Resistance of the resistor. Ix = V/Rx Iy = V/Ry So, Ix/Iy =(V/Rx) / (V/Ry) Ix/Iy = V/Rx*Ry/V Ix/Iy = Ry/Rx Ry = Rx*Ix/Iy Unknown Resistance value = Known Resistance value * Current through known resistance / Current through unknown resistance.
Total resistance in a Parallel circuit?
Since the resistors are in parallel, then the working formula is 1/Re = 1/R1 + 1/R2 + 1/R3 + 1/R4 where Re = equivalent resistance of the circuit R1 = 1 ohm R2 = 2 ohms R3 = 3 ohms R4 = 6 ohms Substituting appropriately, 1/Re = 1/1 + 1/2 + 1/3 + 1/6 1/Re = (6 + 3 + 2 + 1)/6 1/Re = 12/6 and solving for Re, Re = 0.5 ohm Hope this helps.
How do I find resistance in parallel circuit if total resistance is not given?
For problem no. 7Notes:I1 = I4 = I2 + I3V2 = V3, since they are in parallel.Solve for I1:V1 = 50 V, R1 = 40 Ω. I1 = V1/R1. Therefore, I1 = 50/40 A = 1.25 A.Solve for I2:V2 = 5V, R2 = 60 Ω. I2 = V2/R2.Therefore, I2 = 5/60 A = 1/12 A.Solve for I3:I1 = I2 + I3. -> I3 = I1 - I2 = 1.25 - 1/12 = 7/6 A.Solve for I4:I4 = I1 = 1.25 A.Solve for R3:V2=V3= 5V.R3 = V3/I3 = 5 / (7/6) = 30/7 Ω.Supplemental:Solve for R2, R3 equivialant resistance (Rp):Rp = (R3 * R2) / (R3 + R2)Solve for total resistance (Rt):Rt = R1 + RpSolve for total votlage (Vt):Vt = V1 + V2 = 55 V
Resistor in series and in parallel?
1. How would you hook up three resistor in a circuit to get a the maximum current b the minimum current 2. A 200 ohm resistor and a 500 ohm resistor are in series as a part of a larger circuit. If the voltage across the 200 ohm resistor is 2v, what is the voltage across the 500 ohm resistor? 3. If the equivalent resistance of the 2 resistor in series is 50 ohm and 12 ohm they are connected in parallel, what are the resistances of the 2 resistor? 4. Three resistors R1= 2 ohm, R2= 4 ohm, R3= 8 ohm are connected to a source with terminal voltage of 6V. Find the current that would pass through each resistor and the voltage across each if they are connected in a. series b. parallel 5. 4 ohm resistors is connected in series with parallel assembly of 3 ohm and 6 ohm resistors. The current through the 4 ohm resistor is 6 A. What is the current through the 3 ohm resistor?
If a resistor r1 is in a series with parallel connection of r2 and r3, what happens to total current if r2 opens? Does it increase or decrease?
A network of resistors can always be reduced to a single equivalent resistor.If one of them is removed, the resistance of the network is usually increased, perhaps to infinity!The current through the network will not increase.With a few resistors , as in in the question, the current will not be unchanged. With many resistors (more than five, at a quick guess) there is a possibilty that a bridge exists and removing a resisistor between two points of equal potential will not change the current flow.You may like to check my edits! I had forgotten about balanced bridges.With passive components this is always the case.This is not necessarily the case with active components, like transistors and valves (tubes). Amplifying devices often invert applied voltages and the circuit shows ‘negative resistance’.
Finding voltage and current in a parallel circuit?
Im having some trouble, maybe I am using the wrong formula, I have R1 = 3.3k, R2 = 4.7k, R3 = 15k So when I calculate total resistance I get 5.22k, when I calculate V1(3.3), V2(4.7), and V3(15), I get 7.59, 10.8 and some other number which I know is wrong, what am I doing wrong. I assumed the same fromulas are used for parallel as are for series. Can somebody help me out, help finding current would also be appreciated, as I cant remember how its done. Power supply is 12v, 15k is R3, 3.3k R1 and 4.7k R2 are in series with eachother but parallel to 15k, connected from power, they are as follows 12v | 15K | 3.3 & 4.7| where | is the path of the circuit