How would you put y=0x+5 in standard form?
Standard form is Ax + By = C. First just get rid of 0x because it is not needed because it's just zero. Then you have y=5. This is already in standard form because their is no "x" anymore in the equation.
How do you put y=2-3x into standard form?
Standard form is ax + by = c. y = 2 - 3x Add 3x to both sides: 3x + y = 2 So that's the equation in standard form. Hope that helps :)
How would you put y-4=5(x-8) in standard form?
y-4 = 5(x-8) y-4 = 5x-40 y= 5x-36 Get the variable x and y on the same side. Final answer: 5x-y = 36
X/2 = 10+ 2y/3 in standard form!?
Standard Form is Ax + By = C Times everything by 2 and 3 to get rid of fractions because there are no fractions in standard form. 3x = 60 + 4y 3x - 4y = 60 is the answer
How to put these equation in standard form?
The standard form is in the following format: Ax + By = C Question 1: y = 3/7x - 4 -3/7x + y = -4 multiply by -7 across the entire equation 3x - 7y = 28 Question 4: y = 1/2x + 3/4 -1/2x + y = 3/4 multiply everything by "-2" then x - 2y = 6/4 or (6/4 = 1 2/4 = 1 1/2 = 1.5) x - 2y = 1.5 You can try to do the rest.
How to put 12x=7y-10y and y=4x+x into standard form?
12x=-3y (Solve 7y-10y) 12x+3y=0 (Add 3y to both sides) Done! (A=12, B=3, C=0) y=5x (Solve 4x+x) 5x-y=0 (Subtract y from both sides) Done! (A=5, B=-1, C=0)
How can you go from slope intercept to standard form?
Slope Intercept: y= mx + bStandard form: Ax + By = CIn slope intercept form y is isolated. In standard form x and y are on the same side, but the coefficients, A and B must be integers.Start with y = mx + b and Subtract mx from both sides:-mx + y = b Multiply by any denominator in m, also it is preferred to have the coefficient of x as positive.Example: y = 2/3 x + 5subtract 2/3 x from both sides: (-2/3)x + y = 5Multiply everything by (-3): 2x - 3y = -15
How to put linear equations in standard form.?
A site with good explaination is http://courses.wccnet.edu/~palay/precalc/22mt01.htm The Standard Form for a linear equation in two variables, x and y, is usually given as Ax + By = C where, if at all possible, A, B, and C are integers, and A is non-negative, and, A, B, and C have no common factors other than 1. subtract 10 x from both sides of the equation and get -10x + 5y = -25 multiply all by -1 and get 10x - 5y = 25 divide out the common factor of 5 from all terms and get 2x - y = 5 which is in standard form.
Solve and put in standard form. Show work please.?
well standard form is y=mx+b, so from this we get that y=5, x=-1, and m= -2/3, so we get 5 =-2/3(-1)+b 5=2/3+b 5-2/3=b 15/3-2/3=b 13/3=b so in standard form we have y=-2/3x +13/3 Hope this helps!!