The heat of reaction for the combustion of a mole of Ti in this calorimeter is what in kJ/mol?
The combustion of titanium with oxygen produces titanium dioxide. Ti (s) + O2 (g) -----> TiO2 (s) When 2.060 g of titanium is combusted in a bomb calorimeter, the temperature of the calorimeter increases from 25.00 degrees C to 91.60 degrees C. In a seperate experiment, the heat capacity of the calorimeter is measured to be 9.84 kJ/K. Can you please show me how to do this step by step so i can see what you are doing?
The heat of reaction for the combustion of a mole of Ti in this calorimeter is what in kJ/mol?
Pay attention to the units as we go through this problem. First, find the change in Temperature: (Final Temp - Initial Temp) 91.60 - 25.00 = 66.60 degrees C Next, understand that Kelvin units are the exact same magnitude as Celcius. (1K=1C) therefore, the heat capacity of the calorimeter may also be written as 9.84 kJ/C. After that, you will need to multiply the change in temperature, which was 66.60 degrees C, by the heat capacity for the calorimeter - 9.84 kJ/C. 9.84kJ/C x 66.60 C = 655.344 kJ. Notice how the temperature units drop out and we are left with the total amount of energy that was produced by the combustion reaction. Now we must find kJ/mol. In order to do this, find the moles of Titanium that were reacted. We need the molar mass for titanium: 47.867g/mol To find the moles of titanium, divide the number of grams used (2.060g) by the molar mass (47.867g/mol) 2.060g / 47.867g/mol = 0.0430 moles. As expected, a relatively small amount of moles are present in 2.060 g of titanium. Now we are ready for the answer. Divide kJ by mol! 655.344kJ / .0430 moles = 1.524 x 10^4 kJ/mol. In order to determine the sign of the reaction, understand the direction of heat flow. In this case, energy (in the form of heat) was released via the combustion reaction. We know this because the temperature of the calorimeter increased. Therefore, the sign should be negative. -1.524 x 10^4kJ/mol is my answer. I would say that the answer -1.49 x 10^4 is the correct one. The difference could have been in the molar mass used.
Bomb Calorimeter question.?
When 0.424g of biphenyl (C12H10) undergoes combustion in a bomb calorimeter, the temperature rises from 26.8∘C to 29.6∘C. Find ΔErxn for the combustion of biphenyl in kJ/mol biphenyl. The heat capacity of the bomb calorimeter, determined in a separate experiment, is 5.86 kJ/∘C. Can somebody please help me with this? I've answered it incorrectly for my homework enough now that I will no longer receive anything for it and just want to know where I'm going wrong.
The heat of reaction for the combustion of a mole of Ti in this calorimeter is what in kJ/mol?
The combustion of titanium with oxygen produces titanium dioxide. Ti (s) + O2 (g) -----> TiO2 (s) When 2.060 g of titanium is combusted in a bomb calorimeter, the temperature of the calorimeter increases from 25.00 degrees C to 91.60 degrees C. In a seperate experiment, the heat capacity of the calorimeter is measured to be 9.84 kJ/K. These are the possible answers... -311 -0.154 19.6 -1.49 x 10^4 14.3 Can you please show me how to do this step by step so i can see what you are doing?
Chemistry problem regarding the heat of reaction for the combustion of Titanium?
this is much simpler than using that formula. It looks complicated, but its actually just trying to throw you off using Kelvin degrees... yet each increase in kelvin degree is exactly the same as an increase in a Celcius degree. Thus, the increase from 25C to 53.8C is 28.8 If each degree increase requires 9.84 kJ the total energy increase is 28.8x9.84 = 283.392kJ This is for 0.721grams of Titanium You need to find the kJ increase per mole. Seeing that titanium has an atomic mass of 47.9, the moles of 0.721grams of Titanium is: 0.721/47.9 = approximately 0.015moles Thus per 0.015051 moles, the kJ increase is 283.392kJ dividing by 0.015051, per 1mole, the increase is 283.392kJ / 0.015052 which gives you 18,827.3kJ per mole Using standard form and rounding up to 3 significant figures, this is the same as 18.88x10^4 kJ/mol heat given out. Watch out, though! This is energy given OUT, an exothermic reaction, therefore the heat of combustion is negative, ie -1.88 x 10^4 kJ/mol
What is a balanced equation of the reaction between hydrochloric acid and sodium carbonate?
2HCl + Na2CO3 → 2NaCl + H20 + CO2
Mastering Chem Practice exam question?
The combustion of titanium with oxygen produces titanium dioxide: Ti(s) + O2(g) → TiO2(s) When 2.060 g of titanium is combusted in a bomb calorimeter, the temperature of the calorimeter increases from 25.00°C to 91.60°C. In a separate experiment, the heat capacity of the calorimeter is measured to be 9.84 kJ/K. The heat of reaction for the combustion of a mole of Ti in this calorimeter is ________ kJ/mol. Can someone show me a step by step on how to do this.
The combustion of titanium with oxygen... please help?
The combustion of titanium with oxygen produces titanium dioxide: Ti (s) + O2(g) ---> TiO2 (s) When 3.82 g of titanium is combusted in a bomb calorimeter, the temperature of the calorimeter increases from 25.00°C to 31.4°C. In a separate experiment, the heat capacity of the calorimeter is measured to be 9.84 kJ/K. The heat of reaction for the combustion of a mole of Ti in this calorimeter is ________ kJ/mol. No idea what to do. Thanks for any help!
How do I calculate the quantity of heat required to convert 2.5 kg of water at 25 degrees Celsius to steam at 100 degrees Celsius?
To convert 2.5 kg of water at 25°C to steam at 100 °C, first we need to convert water at 25 °C to water at 100 °C and then water at 100 °C to steam at 100 °C.For first step,Q1= m*c*ΔΦQ1= 2500*1*75 calQ1=1,87,500 calFor second step,Q2= m*LQ2= 2500*540 calQ2=13,50,000 calThus total heat,Q= Q1 + Q2Q= 1,87,500 + 13,50,000Q= 15,37,500 calQ= 1537.5 kcalQ= 1537.5*4.184 kJQ= 6432.9 kJ
What is relationship between specific heat capacity and heat capacity?
Heat capacity (Cv) of a material is the amount of energy needed for the raise of one degree Celsius (or kelvin). Hence, it goes as Joules/Kelvin.Now. Any “specific” property, in thermodynamics, is an intensive property (Which means, as you know, is any property independent of it’s measuring parameter). And here, mass is the “measuring parameter”.Specific heat capacity (cv) of a material is, thus, the energy needed to raise one unit mass of that material through one degree Celsius (or kelvin). Hence it goes as Joules/(Kelvin*kilogram)As already answered, Cv= mass*cv.Extra- Specific volume is the volume per unit mass (unit- cubic metres/kilogram)