The length of the top of a table is 3 m greater than the width. the area is 88 m^2 find the dimensions of the?
The area of a rectangle is found using the formula A=LW. You need to express the length and width of this table using one variable. Since the length is described in terms of the width, let's call the width w. The length is 3m more than the width, so we can call the length w+3. Put these expressions of the length and width into the formula: A=LW, A=88m^2, L= (w+3), w=w substitute: 88=w(w+3) (ok I did WL instead of LW but it's the same thing) Distribute the w: 88 = w^2+3w subtract 88 from each side 0 = w^2+3w-88 factor. w^2 can only be factored by w*w so set that up: (w )(w ). Now look at the last term, it is -88. You need to find two factors of -88, and since factors multiply to get the number, you must have one positive and one negative factor to get -88, so go ahead and put them into your parentheses: (w+ )(w- ). Now find factors of -88 that when added together give you 3, the coefficient of the middle term. -8 and 11 add up to 3, so put those into your factors: (w+11)(w-8) and remember that this equals 0: (w+11)(w-8)=0 Now when you multiply two numbers and get a product of 0, at least one of those numbers must equal 0 since any number times 0 equals 0. Either one can be 0, so set each equal to 0: w+11=0 subtract 11 from each side w= -11 w-8=0 add 8 to each side w=8 Now you're asked to give the length and width of the table top. The table can't have a dimension that is negative, so we can discard the solution w= -11. We find that the width of the table is 8 feet. To find the length, go back to how we expressed the length, 3 more than the width: L=3+w, w=8 substitute L=3+8 add L=11. So the length of your table top is 11m and the width is 8m.
The length of the top of a table is 6m greater than the width. The area is 91m^2. Find the dimensions of the?
a = lw 91 = (6 + w)w 91 = w^2 + 6w 0 = w^2 + 6w - 91 0 = (w + 13)(w - 7) w = - 13 or w = 7 we can not have a negative length so w = 7 and l = 6 + w = 6 + 7 = 13
The length of the top of a table is 3m greater than the width. The area is 70m².?
Let the width be = x Therefore, length = x+3 Area = x*(x+3) = 70 Solving for x, we find x = 7 Therefore width = 7, Length = 10
If ratio of length and breadth of a rectangle is 3:2 & its area is 38400 then find its perimeter?
Let the length be [math]l[/math] and breadth be [math]b[/math]. Therefore, as per the given condition [math]\frac{l}{b}=\frac{3}{2}[/math].[math]\therefore l=\frac{3b}{2}[/math]Let the area of rectangle be [math]A[/math] which is given as [math]38400 units^{2}[/math][math]\therefore A=l×b[/math][math]\therefore 38400=\frac{3b}{2}×b[/math][math]\therefore \frac{38400×2}{3}=b^2[/math][math]\therefore 25600=b^2[/math]Taking square roots,[math]\therefore b=160[/math] units.Putting value of b in l, we get,[math]\therefore l=\frac{3×160}{2}[/math][math]\therefore l=240[/math] units.Let the perimeter be [math]P[/math]. Hence, [math]P=2(l+b)[/math][math]\therefore P=2(240+160)=800[/math] units.Hence, perimeter of the rectangle is 800 units.Hope this helps! You can also get such questions solved and get the detailed solution within seconds using the Scholr app by just uploading a picture of the question and also get to be a part of an ever-growing community of students.
How do I solve this math problem the length of the top of a table is 4m greater than the width. the area is 60?
L = W + 4 Area = L * W = (W + 4) W Set that equal to 60 and solve for W.
The length of the rectangle is 6cm more than its breadth. If the perimeter of the rectangle is 308cm, how do you find the area of the rectangle?
Let us begin by knowing the lengths of the sides of the rectangle. Since the length is 6 cm more than the width, let the width be represented by x, so using the formula for the perimeter of a rectangle [math]2L + 2W = P[/math][math]2(6 + x) + 2x = 308[/math][math](12 + 2x) + 2x = 308[/math][math]12 + 4x = 308[/math][math]4x = 308 - 12[/math][math]4x = 296[/math][math]x = 74 \space cm[/math], so [math]L = 80 \space cm[/math].To determine the area of a rectangle: [math]A = L \times W.[/math]So [math]A = 74 \times 80[/math][math]A = 5920 \space cm^2[/math]
A water tank is 3 m long, 2 m wide and 1 m high. How many litres can be stored in it?
First, let’s find the volume of the tank. This is a little tricky because it depends on what shape the water tank is. In this case, I will assume it’s cubic. We know the volume of a object is represented by the equation V=LWH, which tells that the volume is the product of the length, the width, and the height. In this case, the tank is 6 cubic meters.Although we found the volume, this is not the answer we’re looking for because we’re trying to find how many liters are in the tank, not cubic meters. The dictionary defines liter as equal to “1,000 cubic centimeters.” In that case, we convert the cubic meters to cubic centimeters, leaving us with 6,000,000 cubic centimeters. With our prior definition, we can divide 6,000,000 by 1,000 to get 6,000.Finally, assuming the tank is cubic, there can be at most 6,000 liters in a 3 x 2 x 1 tank.
The length and breadth of a rectangular field are in the ratio 3:2. If the area of the field is 294 square metres, what is the cost of fencing the field at 28 per metre?
Answer is Rs. 1960
Rectangle width, radicals and ratio.?
A room is approximately shaped like a golden rectangle. Its length is 17 ft. What is the room's width? Write your answer in simplified radical form and rounded to the nearest tenth of a foot. Note that the ratio of the length t the width of a golden rectangle is (1+√5):2 The width, in simplified radical form, is [___] ft. The width, rounded to the nearest tenth of a foot, is [___] ft.
If the perimeter of a rectangular lot is 68 m and the length of its diagonal is 26 m, what is its area?
The perimeter of a rectangular plot is 68 m. So it means the sum of two adjacent sides is 34 cm and the diagonal is given as 26 m.Let the two sides be x and (34-x).Applying Pythagoras theroem26^2 = x^2 + (34-x)^2, or676 = x^2 + 1156 - 68x + x^2, or2x^2- 68x + 480 = 0, orx*2–34x+240 = 0, or(x-24)(x-10) = 0x = 24 or 10So the length = 24 m and the width = 10mSo the area of the plot is 24 x 10 = 240 sq m.