Trig/calc help?
In this problem, please evaluate the trig functions without a calculator and do not use a decimal point in your answer. An equation of the tangent line to the curve y=sin(x) at x=3π/2 is y=______ +______ ⋅(x−3π/2) An equation of the tangent line to the curve y=cos(x) at x=11π/6 is y=_______ +_______ ⋅(x−11π/6)
Trig/Pre-calc question help?
1: Right: so we want to make a profit of $3. This means we need the production price to be $9.50 because $12.50-$9.50=$3. With this in mind, we set up a system of equations in which x represents the number of 25 cent pieces and y represents the number of 45 cent pieces. x+y=30 because we have 30 pieces of candy. .25x+.45y=9.5 because the production price is 9.50. solve for x in one equation: x+y=30 y=30-x Then substitute 30-x for y in the 2nd equation: .25x+.45y=9.5 .25x+.45(30-x)=9.5 solve for x: .25x+.45(30)-.45x=9.5 .25x+13.5-.45x=9.5 .25x-.45x=-4 -.2x=-4 x=20 Then we take our first equation again. We know x=20 so we plug it in: x+y=30 20+y=30 y=10 so we have 20 $.25 pieces and 10 $.45 pieces. Checking gives us: .25x+.45y=9.5 .25(20)+.45(10)=9.5 5+4.5=9.5 Easy! For #2: This is a simple chemistry problem. We have 2 molarities and one volume so we can apply this formula: molarity2(volume2)=molarity1(volume1) our volume1 is 20 ounces and our molarity1 is 40%. our molarity2 is 30%. plug in: .4(20)=30%(volume2) 8=.3x x=26.6667 so, your volume2=26 and 2/3 ounces. Since we started with 20 ounces, we added 6 and 2/3 ounces. There you go!
Calc with Trig. HELP!?
Consider the equation below. (Give your answers correct to two decimal places.) f(x) = 4sin(x) + 4cos(x) 0 ≤ x ≤ 2pi How can I find its intervals of increase/decrease? When I try to solve for the critical numbers, I have 0 = 4cosx - 4sinx. How can you solve for x here? Also, when looking for the inflection point, I take the seconds derivative and get 0 = -4sinx - 4cosx. How can I solve for x here to find a possible inflection point? Thanks!
I need help with these calc questions on derivatives and trig functions?
1. find f'(x) if f(x)=9cos(x)+7sin(x) 2. find f'(x) if f(x)=5csc(x)+cot(x) 3. Differentiate f(x)=4x^2 -7cosx Answer:f'(x)= 4. Find the equation of the tangent line to the curve y=5x cos x at the point (pi,-5 pi). The equation of this tangent line can be written in the form y = mx+b. Compute m and b. m= b= 5. In this problem, please evaluate the trig functions without a calculator and do not use a decimal point in your answer. An equation of the tangent line to the curve y= sin (x) at x = 4pi/3, is y = + , (x - 4pi/3) . An equation of the tangent line to the curve y = cos (x) at x = 7pi/4, is y = + , (x - 7\pi/4) . 6. If f(x)=cosx-4tanx, then f'(x)= 7. Let f(x) = -6 cos x + 2 tan x . f'(x) = f'(3 pi/4) = 8. Let f(x) = 7 sec x. Find the requested derivatives. f'(x) = f''(x) = 9. Find the equation of the tangent line to the curve y =3 tan x at the point ( pi/4, 3). The equation of this tangent line can be written in the form y = mx+b where m is: and where b is: 10. Let f(x) = 3 sin x + 4 cos x f'(x) = f'( -pi/3) = 11. Evaluate lim t→0 (sin2t)/(sin8t) Limit: 12. Evaluate lim θ→0 (sin3θsin9θ)/(θ^2) Limit: 13. Evaluate the following limit without using a calculator. Enter DNE if the limit does not exist. lim x→0 (xCSC(7x))/(Cos(2x))= 14. Evaluate the limit. lim x→0 (tan 8x)/(sin3x) 15. lim x→3 (Sin(x-3))/(x^2+3x-18)= 16. Evaluate lim θ→0 (sin^2 7θ)/(4θ) 17. Evaluate h→0 (sin 8h)/(6h) 18. lim x→0 (tanx)/(4x)
Really hard trig/calc question, please help me!?
The question is: Create your own trigonometric identity that contains at least 3 different trigonometric functions. Explain how you created it and know it is an identity. Please don't give me clues, I literally have no idea what I'm doing. If you could just give me the full answer to the question I'll send points your way. Thanks so much.
Pre-Calc/Trig Help?
1. Use fundamental identities to simplify the expression below and then determine which of the following is not equivalent. secΘ (sinΘ / tanΘ) a. sin^2Θ + cos^2Θ b. csc^2Θ - cot^2Θ c. 1 d. cos^2Θ - sin^2Θ e. sec^2Θ - tan^2Θ 2. Find the exact value of the given expression using a sum or difference formula. Show your work. sin345° Please and thank you so much in advance. I've tried both problems and am so stuck... I really don't get trig. Please show your work so I may see how to solve future problems. I always choose a best answer!
Really hard trig/calc question- please help me I'm desperate!??!?
The trick is to start with something that you KNOW is an identity, and then manipulate it into some new form. So for example, everyone should know that sin^2 + cos^2 = 1 If you divide both sides of this by cos^2 you get tan^2 + 1 = sec^2 Now subtract tan^2 from both sides of this to get 1 = sec^2 - tan^2 Going back to sin^2 + cos^2 = 1, we replace the 1 on the line above to get sin^2 + cos^2 = sec^2 - tan^2 And now we've got an identity with 4 different functions.
Trig/calc. problem about perihelion and aphelion distances... HELP!?
isn't 18.09 its aphelion? then it's peri should be e=1- 2/(a/p +1) where e is 0.97, 'a' is 18.09 and p is perihelion
Please, Help! Pre-Calc Trig!?
Your first step is correct: R(θ) = v² sin(2θ)/32 = 35,000 Now we solve for sin(2θ) sin(2θ) = 32*35,000/v² sin(2θ) = 32*35,000/2200² sin(2θ) = 28/121 2θ = sin⁻¹(28/121) θ = 1/2 sin⁻¹(28/121) θ = 6.68990082589° ≈ 6.69° NOTE: your answer seems to be in radians = 0.11676 which rounds to 0.12 (not 0.11). So I suspect you had your calculator set to radian mode instead of degree mode.