Two 2.0-cm-diameter disks face each other, 1.0 mm apart. They are charged to +/-13 nC.?
Two 2.0-cm-diameter disks face each other, 1.0 mm apart. They are charged to +/-13 nC. (a) What is the electric field strength between the disks? (Assume the plates form a parallel-plate capacitor.) N/C (b) A proton is shot from the negative disk toward the positive disk. What launch speed must the proton have to just barely reach the positive disk? m/s
Pair of charged rings- Electric Field?
Enet = E1 + E2 (A) Since the two rings are positive, they will repel each other. They both have the same magnitude, but their directions are opposite of each other, so: Enet = E1 - E2 = 0; E1 = E2 (B) The electric field at the center of a ring is 0, so the total electric field for the left ring is 0. The electric field from the left ring (E1) still repels the electric field from the right ring (E2), so: Enet = E1 - E2 = 0 [Edit]: If the answer isn't zero, then chances are the right ring will provide an electric field. Calculate its electric field I guess.
Two 10-cm-diameter charged disks face each other, 30cm apart. The left disk is charged to - 50 nC and the righ?
Two 10-cm-diameter charged disks face each other, 30cm apart. The left disk is charged to - 50 nC and the right disk is charged to + 50 nC . What is the electric field E , both magnitude and direction, at the midpoint between the two disks? Express your answer to two significant figures and include the appropriate units.
What is the electric field vector E, both magnitude and direction, at the midpoint between the two disks?
The electric field between these two plates is σ/εo where σ is the charge distribution = Q/A So E = 50x10^-9C/(π*(0.050m)^2*8.854x10^-12 (I'm assuming your charges are in nC) = 7.19x10^5N/C So F = E*q = 7.19x10^5*(1.0x10^-9) = 7.19x10^-4N directed toward the positive plate
Physics: elevtric fields of rings???
The trick to this: Only the axial component (z-component) matters, everything else cancels out. The second trick to this: The z-component contribution from both rings is the same, because both their relative position (relative to the center pint) and their charge are reversed. So you only have to consider the z-component of a single point charge of magnitude 20 (nC) located at some point on one ring, and double it: E_z = 2 * k(20e-9)*(1e-2)/(sqrt((1e-1^2 + 1e-1^2)^(3/2) = k*4*e-7/sqrt(2) = 4*8.988*e2/sqrt(2) = 2.54e3 (N/C), pointing left F = e*E_z = 1.6e-19 * 2.54e3 = 1.6*2.54*e-16 = 4.064e-16 (N), pointing right.
Electric Fields?
Two 10-cm-diameter charged rings face each other, 20cm apart. The left ring is charged to -22nC and the right ring is charged to +22nC . A) What is the magnitude of the electric field E⃗ at the midpoint between the two rings? B) What is the magnitude of the force F⃗ on a -1.0 nC charge placed at the midpoint?
Physics help !!?
Two 10-cm-diameter charged rings face each other, 26cm apart. The left ring is charged to -30nC and the right ring is charged to +30nC . Part A What is the magnitude of the electric field E⃗ at the midpoint between the two rings? E=____________________ Part B What is the magnitude of the force F⃗ on a -1.0 nC charge placed at the midpoint? F=_____________________