In a double-slit experiment using the light of wavelength 600 nm, the angular width of a fringe formed on a distant screen is 0.1 degree . What is the spacing between the two slits?
Wavelength of light (λ) = 6000 nm = 600 x 10-9m(10 raised to -9)Angular width of fringe (θ) = 0.1° = 0.1 x λ/180 = 3.14/1800 radAngular width of a fringe is related to slit spacing (d)θ = λ/dd = λ/ θ= 600 x 10-9(10 raised to -9)/ 3.14/1800= 3.44 x 10-4 mTherefore, the spacing between the slits is 3.44 x 10-4 m.
Two slits of width a and separation d are illuminated by a coherent beam of light of wavelength λ.?
I have included a drawing which explains the trigonometry of a double slit interference pattern you want X I called distance L which you will change to D note that for small angles tan and sin are approximately equal which simplifies things greatly If someone gives you a good answer, please consider giving a best answer. This is the only reward we get.
Does the spacing between fringes in a two-slit interference pattern increase, decrease or stay the same if (a) Slit separation is increased (b) Color light is switched from red to blue?
The closer the slits, the further apart the fringes.The smaller the wavelength, the closer together the fringes, so blue light will produce narrower fringes than red.Or so I believe, off the top of my head, from my memories of doing this experiment in high school some 40 years ago.