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Use The Quadratic Formula To Solve The Equation 4x^2-6x-10=0

Solve the equation using the quadratic formula 4x^(2)+3x-10=0.?

I understand one of the answers will be -2
but in my answer choice I also see 1.25.
I don't understand how that person got it because all I got was 5/4 and -2.

Solve quadratic equation, 4x^2=100, 3x^2+2x-10=0, 4t^2=3t+12, ?

4x²=100
x²=100/4
x²=25
x=5, x=-5


3x^2+2x-10=0, a=3, b=2 and c=10
use x = {-b ± √(b² - 4ac)} / 2a
x = {-2 ± √((-2)² - 4(3)(-10))} / 2(3)
x = {-2 ± √124)} / 6 = {-2 ± 2√31)} / 6
x = (-1+√31)/3 and x = (-1-√31)/3


4t^2=3t+12, a=4, b=-3 and c=-12
x = {-3 ± √(9 - 4(4)(-12))} / 2(4)
x = {-3 ± √(201)} / 8
x = (-3+√201)/8 and x = (-3-√201)/8

Solve Quadratic equation 5x^2+2x-3=0?

5x^2 + 2x - 3 = 0
x = (- b +- √b^2 - 4(a)(c)) / 2a
Remember that 2a is the denominator of the entire formula.
a = 5
b = 2
c = -3

x = (-(2) +- √(2)^2 - 4(5)(-3)) / 2(5)
x = (-2 +- √4 + 60) / 10
x = (-2 +- √64) / 10
x = (-2 +- 8) / 10

x =(-2 + 8) /10
x = 6 / 10
x = 3/5

x =(-2 - 8) / 10
x = -10 / 10
x = -1

x = 3/5, -1

Solve 2x2 + 4x +10 = 0 using the Quadratic Formula. What is the solution set?

X= -3.5

How can the quadratic equation [math]x^2  - 3x - 10 = 0[/math] be solved?

Factorisation !-> First multiply the co-efficient of x^2 and the constant in the equation.     Here, 1 * (-10) = -10->Find out the factors of 10.    Here, 5 * 2 = 10->Arrange the factors in such a way that when you add/subtract them you   get the answer equal to the co-efficient of x.   Here, co-efficient of x is -3.Hence, the equation can be arranged in the following way.-> x^2 -5x +2x -10 = 0  => x(x-5) + 2(x-5) = 0  => (x-5)(x+2) = 0Either one of the factors must be zero. 1 ) Assuming (x-5) = 0     We get x = 52) Assuming (x+2) = 0     We get x = -2The roots of this particular equation is 5 and -2.

1. What are the solutions of the quadratic equation? 2x2 – 16x + 32 = 0?

A few for questions i have if someone could help me, are:

2. What is the solution of the equation?
5x2 = 50

3. Use the quadratic formula to solve the equation.
4x2 – 6x – 10 = 0

4. Simplify the number using the imaginary unit i.
square root -16

5. Simplify the expression.
-5+i/2i

6. What is the solution of the linear-quadratic system of equations?
y=x^2+5x-3
y-x=2

For any of these, i dont want just an answer. I actually want to understand how to do them.

How do you solve (x - 3) ^2= 10 by using the quadratic formula?

If you take the square root of both sides you get:x-3 = positive root10 or negative root10So the first solution is x = root10 + 3Second solution: x = negative root10 + 3Edit: Just realised it said quadratic formula, sorry.So first you need to expand out the brackets to get:[math]x^2-6x+9 = 10[/math]Now take 10 away from both sides:[math]x^2-6x-1=0[/math]Plug this into the quadratic formula:[math]x = (-(-6)+root((-6)^2-4(1*-1)))/2(1)[/math]Or:[math]x = (-(-6)-root((-6)^2-4(1*-1)))/2(1)[/math]Simplify:[math]x = (6+root(40))/2 [/math]or [math]x = (6-root(40))/2[/math][math]root(40)=root(4)*root(10)=2*root(10)[/math]so you can simplify further:[math]x = (6+2*root(10))/2 [/math]or [math]x = (6-2*root(10))/2[/math]And divide by 2 to get the solutions:[math]x = 3+root(10) [/math]or[math]x=3-root(10)[/math]

Where can you practice quadratic equations?

Start with these!5x^2+85x+72=0-1x^2+10x+21=0-2x^2+2x-6=05x^2+50x+24=0-5x^2-35x+10=02x^2-28x+48=05x^2+5x-12=04x^2-48x+32=04x^2+60x+56=03x^2-6x-35=0-3x^2-3x-72=0-3x^2+15x-24=0-1x^2-8x-9=02x^2-2x-6=0-1x^2-8x+15=04x^2+20x-6=02x^2+2x-72=0-4x^2-44x+28=0-2x^2-8x+4=0-5x^2-10x-8=0-1x^2+9x+8=0-2x^2-34x+72=04x^2+0x-16=0-3x^2-6x-8=02x^2+2x-30=03x^2-21x+12=04x^2+20x+6=03x^2+30x+16=03x^2+3x-72=0-2x^2+26x+42=01x^2+1x-12=04x^2+16x+3=01x^2+4x+4=0-1x^2+10x+21=03x^2+36x+36=01x^2-14x+49=01x^2+13x+40=02x^2-8x-32=0-1x^2+9x+14=0-4x^2-12x-4=0

How can I solve “x²-3x-2=0” by using the factorization method?

We cannot use factorization method for solving the given equation so we can use either quadratic formula or Completing the square method to solve the given quadratic equation.we can solve the given equation by using Quadratic formula asa=1 (Coefficient of x²)b=-3 (Coefficient of x)c=-2 (Constant)Applying the quadratic formula asx=(-b±√ b²-4ac)/2a (1)Putting the values of a, b and c in equation (1)x=(-(-3)±√(-3)²-4(1)(-2))/2*1x=3±√9-(-8))/2x=3±√(9+8)/2x=3±√17/2Solution set={3+√17/2,3-√17/2}In order to understand the other ways of solving the quadratic equation please subscribe You Tube Channel by using following links and search for "How to solve quadratic equation by Factorization""How to solve quadratic equation by completing square method"https://www.youtube.com/channel/...

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