Given the point (sqrt3,-1) in the rectangular coordinate system.?
Which of the following represents pairs of polar coordinates that correspond to this point? A (1,pi/4) B (-1,-pi/4) C (-2,3pi/4) D (3,11pi/6) E (1,-5pi/6) F (2,-pi/6)
Find the rectangular coordinates for the point whose polar coordinates are given. (4, 2pi/3)?
X = 4*cos(2pi/3) = -2 Y= 4*sin(2pi/3) = 2*sqrt 3
Give the rectangular coordinate of the point p whose polar coordinates are (4,pi/3)?
polar coordinates (r, t) <---> the rectangular coordinate (x = r cost , y = r sint )
What are the polar coordinates of point P whose rectangular coordinates are (4,9)?
I think you mis-categorized this question but to answer it I'd say you have to use the Pythagorean theorem and right triangle trig. r = sqrt(9^2 + 4^2) = sqrt(97) = 9.85 Ɵ = atan(9/4) = 1.15r
How do I change from rectangular to spherical coordinates and vice versa?
Spherical to Rectangular (4,pi,pi/2) and (4,pi/4,pi/6) Rectangular to Spherical(p,theta,phi) (0,3sqrt2,3sqrt2) and (3,3,-3sqrt6) These are quite confusing for me, any help on these will be greatly appreciated.
HELP Find the polar coordinates of the point whose rectangular coordinates are given?
x=1 y= sqrt(3) Since x = r * cos(theta) and y = r * sin(theta) x = r * cos(theta) = 1 y = r * sin( theta ) = sqrt(3) r = 1 / cos(theta) sin(theta) / cos(theta) = tan(theta) = sqrt(3) tan^-1(sqrt(3)) = theta = pi / 3 Since x is positive and y is positive, theta doesn't need to have pi added to it. r = 1 / cos(pi/3) = 2 (1, sqrt(3)) -> (2, pi/3)
The Cartesian coordinates of a point are given.?
Part a) Draw (6,-6). You have a right triangle with lengths 6 and 6 so the hypotenuse is 6sqrt2. That is your radius. Since its a 45-45-90 right triangle and the point is located in the 4th quadrant, the theta is - pi/4 polar coordinate is (6sqrt2, -pi/4) b) Similar to part a but r<0 so r = -6sqrt2 and theta is still -pi/4. (-6sqrt2, -pi/4) c) Draw (1, sqrt 3) Thus you have a 30-60-90 right triangle with sides 1 and sqrt3. Thus the hypotenuse is 2. Theta is opposite the side length of sqrt3 so theta = 60 = pi/3 Thus the coordinate is (2, pi/3)
FND THE POLAR COORDINATES 0=< Ɵ <2 pi, of the following points given in Cartesian?
FND THE POLAR COORDINATES 0=< Ɵ <2 pi, of the following points given in Cartesian coordinates a) (3sqrt(2),3sqrt(2)) b) (-2,2sqrt(3)) c) (-1,-sqrt(3)) The polar coordinates of the point (3sqrt(2),3sqrt(2)) are... The polar coordinates of the point (-2,2sqrt(3)) are... The polar coordinates of the point (-1,-sqrt(3)) are...