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What Is The Oxidation Number Of Phosphorus P In Mg3 Po4 2

What is the oxidation number of phosphorus (P) in sodium phosphate (Na3PO4)?

let the oxidation no. of P be x.
and we know tht oxidation no. of Na= +1, O= -2
therefore,
3*1 + x+ 4* -2 = 0 (net charge on the molecule)
3+x -8 =0
x=+5
therefore, the answer is C)+5

What is the oxidations number of phosphorus in Ca3(PO4)2?

PO4 is 3- overall

O is 2- x 4 = 8-

P must cancel out all but 3- of the 8- so P must be 5+

What is the oxidation number of phosphorus (P) in Mg3(PO4)2?

1) Review this link http://www.800mainstreet.com/4/0004-0010...

2) Once you understand that the subscripts are just the "charges" of each compound/element then you can proceed to finding the oxidation number of each element.

3) Mg3(PO4)2 --> That is, Mg+2 (PO4)-3

Here we know Mg2+ is on its own and we can therefore exclude it from the equation in terms of finding the oxidation number of Phosphorous.

Oxygen has an oxidation number of 2- and so we can simply multiply the two numbers.

O4 * -2 = -8

If you don't have a periodic table to look up the group number of Phosphorous, you can simply solve the equation:

X + -8 = -3

That is, what number (X) will give you a -3?
Answer: 5+

What is the oxidation state of phosphorus in Na3PO4?

+5. Oxygen always has an oxidation state of -2 & sodium’s is always +1. So the 4 O atoms combined makes -8 and the trio of Na atoms takes +3 off that. As a compound’s oxidation state is always 0, the phosphorus has to be at +5 to balance things out.

What id the oxidation number for each element in Ca3(PO4)2?

P is +5

the rest looks fine

What is the oxidation number of each element in: Ba3(PO4)2 ?

Ba is +2
O is -2
P is +5.... . from... 3x(+2) + 2xP + 8x(-2) = 0

What is the oxidation number of P in PO4?

The oxidation state of P in PO4 can be calculated as under.PO4 has 3- charge on it.Lets suppose that charge on P is x. Also the charge on oxygen is -2.So form a linear equation.x + 4(-2) = -3x-8=-3x=-3+8x= 5.Hence the charge on P is +5.

What is the oxidation number of Ca3(PO4) 2?

Oxidation no. of Ca is +2.Let oxidation no. Of Ca in the given compound be xThen easily we can write the equation (from the formula of Ca3(PO4)2 given)as follows3x + {(-3)*2 } = 0or, 3x =+ 6or, x=+ 2

How many phosphorus atoms are represented by Sr3(PO4)2?

The Phosphorus atoms come from the group PO4 (phosphate). Since there are two PO4 groups and each group has one phosphorus atom, we can conclude that there are two phosphorus atoms

What is the chemical formula of magnesium phosphate? How is it calculated?

Magnesium phosphate is Mg3(PO4)2.Okay, onto how I found that:Magnesium phosphate is an ionic compound, because firstly, there is no numerical prefix on the second word of the name, so we know it is not a covalent compound.In the names of ionic compounds, the first word is always the cation. So, the cation of this compound is magnesium (Mg (2+) ), with a charge of 2+. The latter word is always the anion, which is phosphate (PO4 (3-) ) in this compound, with a charge of 3-. We can use this information to determine the formula later.The sum of charges of the cation and the anion of any ionic compound is always zero. The amount of the cation and the anion needed for the sum to be zero can be determined simply with the criss-cross method. This involves taking the charge of one ion, and making the absolute value of that charge the amount of the other ion.Magnesium has a charge of 2+; therefore, we will have 2 phosphate cations. Phosphate has a charge of 3-, so we will have 3 magnesium cations. We end up with our final formula: Mg3(PO4)2.Ions are not in parentheses unless they are polyatomic, and there is more than one of the polyatomic ions. This is why the NO3 in NaNO3 is not in parentheses, and in parentheses in Mg(NO3)2.

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