What is the total number electrons present in 64 g of methane CH4 ?
CH4 molecule contains 1 carbon atom and 4 hydrogen atom.Now, carbon atom contains 6 e, and hydrogen atom contains 1e each. So there are 6 + (1*4) = 10 e in methane molecule. [4 for hydrogen atom]Now, molecular weight of methane is 16gm or you may say it is the weight of 6.022 * 10^23 molecules of methane. Now, no. of moles of methane = Given mass/molar mass = 64/16 = 4.So, there are 4 moles of methane or 4* 6.022 * 10^23 molecules of methane [ one mole has weight as molecular weight in gm] or 10 * 4 * 6.022 *10^23 e in 64 gm of methane [as each molecule has 10e].:)
What total number of electrons are present in 32g of methane?
Methane is a chemical compound with the chemical formula CH4 (it means one atom of carbon and four atoms of hydrogen).The carbon atom (12C) contains 6 protons, 6 neutrons and 6 electrons, while each hydrogen atom (1H) contains 1 proton and one electron. In this compound exists (6 + 4 x 1) = 10 protons, (6 + 0) = 6 neutrons and (6 + 4 x 1) = 10 electrons.The proton mass is mp=1.672 621 898 x 10^-27 kg, the neutron mass is mn=1.674 927 471 x 10^-27 kg, the electron mass is me=9.109 383 56 x 10^-31 kg.Accordingly, one methane compound has a mass M of (10 mp+6 mn+10 me) = 2.677 578 380 60 x 10^-26 kg.In 32 grams of methane there are 32 g/M = 1.195 109 739 152 780 x 10^24 methane compounds.We conclude, in 32 grams of methane there are 10 electrons x 1.195 109 739 152 780 x 10^24 compounds, it is 1.195 109 739 152 780 x 10^25 electrons.In other words, in 32 g of methane there are 19.845 moles of electrons present.
Total number of electrons present in 1.6 g of methane ?
Methane => CH4 AMU of Carbon = 12 AMU of Hydrogen = 1 12 + 1 * 4 = 16 1.6 / 16 = 1/10 There's 1/10 of a mol of Methane present 6.02 * 10^(23) * 10^(-1) = 6.02 * 10^(22) There are 6.02 * 10^(22) molecule of Methane present There are 6 + 4 => 10 electrons per molecule 6.02 * 10^(22) * 10 => 6.02 * 10^(23) 6.02 * 10^(23) electrons
Find the total number of electrons in 3.2g of Methane(CH4)?
methane has a molecular weight of 12+4*1 =16 3.2g is in mole 3.2/16= 0.2 mole the number of methane molecules is 6.022 *10^23 in 1 mole a molecule of methane has 10 electrons (6 for 1 carbon and 4 for the atoms H) so number of electrons in 3.2 g 0.2*10*6.022*10^23 = 2*6.022*10^23 = 1.244*10^24 electrons
How to calculate the number of electrons present in 1.6 gram of methane?
[Methane is not an element.] Each molecule of methane (CH4) has 6 + (1 × 4) = 10 electrons (1.6 g CH4) / (16.0425 g CH4/mol) × (6.022 × 10^23 molecules/mol) × (10 electrons/molecule) = 6.0 × 10^23 electrons
How many electrons are present in 1.6g of methane?
Let’s think this through: 1.6 grams of methane, is some number of moles of methane. Methane is CH4, meaning it contains one carbon atom and four hydrogen atoms per molecule. One mole of carbon is 12 grams and one mole of hydrogen is 1 gram. CH4 is therefore 16 grams per mole.Now that we have this, we can say:Given Mass / Gram-Formula Mass = # of Moles1.6 grams / 16 grams = 0.1 moles of CH4So, we want to know how many electrons are in 0.1 moles of CH4 molecules. If I have 0.1 moles of CH4, I must have 0.1 moles of carbon atoms and 0.4 moles of hydrogen atoms. One mole is 6.02 * 10^23 entities.Because carbon atoms have 6 electrons, we must know how many electrons are in 6.02 * 10^22 carbon atoms. This would be (6.02*6)* 10^22 = 36.12 * 10^22 electrons. This is the number of electrons from carbon atoms.Because hydrogen atoms each have 1 electron, we must know how many electron are in 4 times 6.02* 10^22 hydrogen atoms, because each molecule has 4 hydrogen atoms. This gives us (6.02*4)* 10^22 = 24.08* 10^22 electrons. This is the the number of electrons from hydrogen atoms.Add these together: 36.12* 10^22 electrons from carbon and 24.08* 10^22 electrons from hydrogen. We then get 60.20* 10^22 electrons or 6.02* 10^23 electrons.Now, that I have answered your question in one way, I found shortcut. Because, our answer is the number of entities in a mole, I should have noted that one molecule has 10 electrons. I figured out that we have 0.1 moles of the substance. I could have noticed this and said we have one mole of electrons and then just use Avogadro's number to give me the number of electrons, which are the entities of concern here.
Calculate the total number of electrons present in 1.4 g of dinitrogen gas.?
Each atom of N contains 7 electrons. Each molecule of N2 contains 2 atoms of N. (1.4 g N2) / (28.01344 g N2/mol) x (6.022 x 10^23 molecules/mol) x (14 electrons/molecule) = 4.2 × 10^23 electrons
How many electrons are present in 16g of methane?
16g of methane constitutes 1 mole of it i.e. 6.022×10^23 molecules. Now , we have 10 electrons in 1 molecule of CH4 (6 from C + 1 each from four hydrogen atoms =10). So no. of electrons in 6.022 ×10^23 molecules will be 6.022×10^23 × 10 = 6.022 × 10^24 electrons.Final answer is no. of electrons in 16g of CH4 = 6.022×10^24.Hope this was helpful! ;-)
Calculate the total number 0f electrons present in 1.6g of methane?
Hi, A carbon atom has 6 electrons, and a hydrogen atom has 1 electron. A methane molecule has one carbon atom and four hydrogen atoms; and this makes 10 electrons in total. 1 molecule of methane contains one carbon atom (12 Dalton), and 4 hydrogen atoms (4*1=4 Dalton); their sum is 16 Dalton. 1 mole of methane molecules = N (=Avogadro number=6,023*10^23 pieces) methane molecules, and they weigh 16 grams. Which means 1,6 grams of methane molecules, make 0,1 mole of methane or 0,1*N methane molecules. Since every methane molecule has 10 electrons; 0,1 mole of methane molecules have 0,1*10=1 mole (=N=6,02*10^23) electrons. I hope it will be helpful.
Total number of electrons present in 18ml of water?
18 mL water X 1 g/mL = 18 g water moles H2O = 18 g / 18 g/mol = 1 mole H2O Number of H2O molecules = 1 mol X 6.02X10^23 molecules/mole= 6.02X10^23 molecules Total electrons in 1 H2O molecule = 10 electrons/molecule So, 6.02 X 10^23 molecules X 10 electrons/molecule = 6.02 X 10^24 electrons