With Histograms Neeeeed Help

I need some help with my java histogram program?

Ask the user to input how many values (from 50 to 200) to be used. Write a verification of input loop to ensure their input is between 50 and 200. Generate random integers in the range of 1 - 100. As you create the random numbers, accumulate total counts for each of the number ranges on the histogram ie: 1-10, 11-20, 21-30, etc. - these values MUST be stored in an Array! Use a switch statement to put values into an array OR to print the table.

I need a bit of help for this so far this is what i have:

import java.util.Random;
import java.util.Scanner;

public class Histogram {

public static void main(String[] args) {

Scanner scan = new Scanner(System.in);

int num;

System.out.println("Please enter a number: ");

num = scan.nextInt();

while (num < 50 || num > 200)
{
System.out.println("Invalid number please reenter: ");
num = scan.nextInt();
}

int[] nums = new int[10];

}
}

beyond this i'm just completely, any help would be appreciated

Which statement about a histogram is true? HELP?

I really need help on this Answer!! I don't get it

Question:Which statement about a histogram is true?

A:Histograms can plot both positive and negative values on both axes.

B:Histograms can be used to exhibit the shape of distributions.

C:Histograms are plots of individual data values.

D:Histograms show the division of quartile regions for a distribution.

In statistics I need help in finding midpoints on a histogram and the percentage.?

1. ANSWER: Yes; valid probablity distribution because sum of percent of nurses = 1.00

3. ANSWER: 0.359


Why??
P(x > 60) = 0.25 + 0.091 + 0.018 = 0.359


5. ANSWER: STD DEV = SQRT(VARIANCE) = 13.66

Why????

x (INTERVAL MID-POINT)
24.5
34.5
44.5
54.5
64.5
74.5
84.5

P(x)
0.057
0.097
0.195
0.292
0.250
0.091
0.018

x * P(x)
1.40
3.35
8.68
15.91
16.13
6.78
1.52


x * P(x)
1.40
3.35
8.68
15.91
16.13
6.78
1.52



x^2*P(x)
34.21
115.45
386.15
867.31
1040.06
505.07
128.52
SUM = 3076.79

MEAN^2 = 2890.14
VARIANCE = SUM - MEAN^2 = 186.65
STD DEV = SQRT(VARIANCE) = 13.66

Histograms? Please help with Statistics homework! ?

I have several problems like this to do and don't understand it very well. I have read the literature over and over and still don't understand how to manually draw a histogram. The example I have makes no sense either. Help would greatly be appreciated.


(a) Find the Class Width
(b) Make a frequency table showing limits, class boundries, midpoints, frequencies, and relative frequencies.
(c) Draw a histogram
(d) Draw a relative frequency-histogram

The following data represents glucose blood levels (mg/100 ml) after a 12-hour fast for a random sample of 70 women

45 66 83 71 76 64 59 59
76 82 80 81 85 77 82 90
87 72 79 69 83 71 87 69
81 76 96 83 67 94 101 94
89 94 73 99 93 85 83 80
78 80 85 83 84 74 81 70
65 89 70 80 84 77 65 46
80 70 75 45 101 71 109 73
73 80 72 81 63 74

Use six classes

Acceleration Histogram?

You would need to know what the initial velocity is or, at least, the velocity at some point in time. Otherwise you can not determine a specific velocity. Does the object start from rest? I don't know, it doesn't say.

The velocity change during any given time interval will simply be the area under that interval of the graph.

So from 4 to 5 seconds the acceleration changes from 0 to -2. The object is slowing down. Since the area is triangular we can write:
change in velocity = (1/2)(5 - 4)(-2 - 0)
change in velocity = -1

From 5 to 6 it is constant at -2 so:
change in velocity = (6 - 5)(-2 - 0) = -2 ..... area is rectangular

And so. Just add up all the changes and the result will be the final velocity if the object started from rest. If it started with some velocity you will have to add that in.