.write An Equation For The Line In Point-slope Form. Rewrite The Equation In Slope-intercept Form

Write an equation in point-slope form for the line.?

The point is provided in the form (x,y). Without doing any calculations, what are the values of x0 and y0 in the point-slope form? Calculate the value of m in the point-slope form.

Through (11,20) and is perpendicular to
 
 y=−3x−3.

Write an equation in point-slope form for the line.  ?

The point is provided in the form (x,y). Without doing any calculations, what are the values of m, x0, and y0 in the point-slope form?

Through (7,−6) and is parallel to y=5/4(x+10)

Write an equation for line L in point slope form and slope intercept form...?

If L is parallel to y = 4x, then the slope of L is 4.

If you have a point (3, -4), then you can write an equation:

y + 4 = 4(x - 3)
y + 4 = 4x - 12
y = 4x - 16

A line passes through (3, –2) and (6, 2). Write an equation for the line in point-slope form.?

there are 3 formula u have to remember
slope(m) formula=>
m=(y2-y1)/(x2-x1)

slope intercept formula=>
x/a + y/b =1

standard form =>
y=mx+c



now see
let A (3,-2) and B(6,2)
u can take any coordinate as x1 y1 and x2 y2

slope=(2-(-2))/(6-3)
=(2+2)/(3)
=4/3


now how to write equation u have given 2 points
take any point
y2-y1 = m(x2-x1)
y-2 = 4/3(x-6)
3(y-2)=4(x-6)
3y-6=4x-24
4x-3y-18=0 <=== answer

u can take this point(3,-2)
y-(-2)=4/3(x-3)
3(y+2)=4(x-3)
3y+6=4x-12
4x-3y-18=0 <=== answer

take any point u will get the same answer :D

edit-oh standand form-
4x-3y-18=0
3y=4x-18
y=4/3 x -6

:)

:)

A line passes through (1, –5) and (–3, 7).Write an equation for the line in point-slope form.Rewrite the equat?

y= -3x-2 is the answer

Equation of a line in point slope form?

Nice big picture! Bless your heart!
Slope is rise over run. Run is horizontal distance, left to right. Run is always positive because we always go left to right. Rise is the vertical change in that same distance. A negative rise means it drops. The given line runs 2 units from 0 to 2 and rises 4 units from -2 to 2 so the slope is 4/2=2.

The equation of a line is y = mx where m is the slope. That line passes through the origin. If you want it to pass through some point (a, b) you subtract the coordinates like this: y - b = m(x - a). That is the point-slope form, and you can rewrite it in other forms if it is convenient. You may do this with any point on the line. They all reduce to the same equation.

y - 2 = 2(x - 2)

y = 2x - 2 point-slope form

y - 2x + 2 = 0 Standard form, all variables on the left, no fractions, zero or a constant on the right.

How doi write the standardform ofan equation ofaline passing through(-1,-1)&perpendicular tothe line-4x-3y=-15?

first write your equation in slope intercept form
-3y=4x-15
y=-4/3x+15
than use point slope form and the opposite of the reciprocal of the slope
(y-y1)=m(x-x1)
(y-(-1))=3/4(x-(-1))
y+1=3/4x+3/4
y=3/4x+3/4-1
y=3/4x-1/4
-3x+4y=-1
(c)