Write the equation 81^1/2=9 in logarithmic form?
log (base 81) 9 = 1/2.
Write the exponential equation in logarithmic form?
Logv9 27=3/2
Logarithmic math questions>?
8. In the given logarithmic expression, name the base. log3 81=4 A. 3 B. 4 C. 81 D. log 9. In the previous problem, name the exponent A. 3 B. 4 C. 81 D. log 11. Write log12 144=2 in exponential form A. 144 1/2=12 B. 12^2=144 C. 2^12=144 D. square144=12 12. write 6^x=36 as a logarithmic function A. log6 36=x B. logx6=36 C. log36x=6 D. log6x=36 13. Write log6 36 in exponential form. A. 6^2=36 B. 36=2^6 C. 36^2=6 D36^6=2 14. Which of the following is an example of logarithmic function? A. y=sin(x) B. y=4^x C. y=log10 3 D. y=x^4 15. y=6^x is written as log6y=x A. True ] B. False 16. log9 81=2 rewritten in exponential form is 9^2=81 A. True B. False 17. Write 7^x=2401 as logarithmic function. A. logx2401=7 B. log7 2401=x C. log2401 7=x D. logx7=2401 Thanks Everyone !
Rewrite as logarithmic equation: 9^2=81?
Log base 9 of 81 is 2.
Write in logarithmic form 3^4=81?
1) 3^4 = 81 log_3 81 = 4 2) (1/2)^4 = (1/16) log_.5 (1/16) = 4 3) log_x 32 = 5 x^5 = 32 x = 2 4) log_2 64 = x log(64) / log(2) = 6 x = 6
Please help meee :((( I have to rewrite each of these in logarithmic form.?
Things you should know : log(a^b) = b*log(a) log(a/b) = log(a) - log(b) log(a*b) = log(a) + log(b) 1.) 4^-2 = 1/16 log(4^-2) = log(1/16) -2*log(4) = log(1) - log(16) Since log(1) = 0 -2log(4) = -log(16) 2.) 7^-2 = 1/49 Same : log(7^-2) = log(1/49) -2*log(7) = log(1) - log(49) -2log(7) = -log(49) 3.) (1/9)^-2 = 81 log((1/9)^-2) = log(81) -2*log(1/9) = log(81) -2(log(1) - log(9)) = log(81) log(1) = 0 2log(9) = log(81) 4.) 3^1/2 = 3 3^(1/2) is not equal to 3 Logs will not give a good answer 5.) 9^3/2 = 27 log((9)^(3/2)) = log(27) (3/2)*log(9) = log(27) 6.) 36^3/2 = 216 log((36)^(3/2)) = log(216) (3/2)*log(36) = log(216)
How do you write a number as a power of another?
If you want to write it on quora or another online website, you can generally use a carrot (8^2) . On paper, you can use a superscript (8 with a smaller two above and to the right). Your details seem to suggest that perhaps this isn't what you are asking, but rather you want to know how to write 8 as 2 raised to a power.To do this, let's walk through an example. We'll say I'd like to write 8 as a power of two. This has a few uses, generally related to factoring. I have 8 and I want to get it in the form 2^X. Two raised to the X power is the same as saying “"two multiplied by itself X times”. The general way to write and figure out an equation like this is by using logarithms. Your question, in exponential form, is “2^X=8”. Logarithmically, the equation is simplified into the expression “log(2)8”, where the number in the parentheses is a subscript of “log”. This can be solved on certain types of calculators, or by using a bit of backwards thinking. assuming you know some simple facts and patterns, determining which power to use is not difficult. Otherwise, guessing and checking may be the best option. Going back to “log(2)8”, or 2^X=8, simply multiplying two by itself a certain number of times will yield your answer. 2*2*2=8, So two multiplied by itself three times (2^3) yields 8. For a larger number, like 4096, guessing and checking using a calculator may be your best bet.Hope that helped!
Algebra- logarithmic form?
1.) Write equation in its equivalent logrithmic form: 7^3=343 2.) Evaluate without using calculator log (base)5 1/25 log (base)4 16 3.) Write equation in exponential form log (base)3 9=2 log (base)b 81=4