What is the equation of a circle with radius 9 and center (-2,3)?
equation of a circle with radius r and center (h, k) is (x-h)^2 + (y-k)^2 = r^2. (x+2)^2 + (y-3)^2 = 9^2
What is the center radius equation of the circle with the center @ (-3,-6) and passing through (-4,8)? Show your complete solution.
I donor know how to type in equation mode. Here is a handwritten solution.
What is the equation of the circle center (2, -3) and radius 4?
Any circle of radius [math]r[/math], centered at [math](a, b)[/math] has the equation:[math](x-a)^2 + (y-b)^2 = r^2.[/math]So, following this logic one can come to the conclusion that your particular circle has the following equation:[math](x-2)^2 + (y+3)^2 = 16.[/math]
How do I write the equation of a circle with center (5,-7) and radius 9 units?
(x-5)²+(y+7)²=81x²+y²-10x+14y-155=0
What is the equation of the circle whose center is (5, 6) and radius is 3?
(x-a)^2+(y-b)^2=(r)^2Where (a,b) is the centre of the circle and r is the radius.So, equation of circle is :(x-5)^2+(y-6)^2=9
What is the center of the circle with equation (x + 1)^2 + (y + 3)^2 = 9/4?
alright, ill tell you, but not without explaining it. im giving you the benefit of the doubt that you are not just cheating on your homework :) the standard equation of a circle, using only variables is (x-h)^2 + (y-k)^2 = r^2 where the center is at (h,k) and the radius is r that means that when you look at the equation youre given, the x coordinate of the center is whatever number is subtracted from the x (x+1) ---> (x- -1) so h = -1 you use the same process to determine "k", which is the y coordinate of the center (y+3) ---> (y- -3) so k = -3 that makes the center of the circle at (-1, -3) finding the radius is also simple using the standard equation. here it is again, just for reference: (x-h)^2 + (y-k)^2 = r^2 see how you can use that to get this? 9/4 = r^2 so just take the square root of both sides . . . r = +/- 3/2 because you took the square root, the 3/2 could technically be either positive or negative, but since youre talking about the radius of a circle and you can't have a negative distance, you only take the positive answer. so r=3/2
Write an equation of the circle with center (2, 3) and radius 4?
The equation is; (x - a)^2 + (y - b)^2 = r^2 center is at (a,b) and radius at r
3. The center of a circle is at (2, 3) and it has a radius of 3. What is the equation of the circle?
a. (x 2)2 + (y + 3)2 = 3 b. (x 2)2 + (y + 3)2 = 9 c. (x + 2)2 + (y 3)2 = 3 d. (x + 2)2 + (y 3)2 = 9 5.A bicycle is drawn on a grid such that the back tire is represented by the equation (x + 100)2 + y2 = 36. What is the tire's diameter? a.12 b.18 c.36 d.50
The center of a circle is at (7, -3) and it has a radius of 9. What is the equation of the circle?
The equation for a circle centered at (h, k) and with radius r is given by: (x - h)² + (y - k)² = r² So, if a circle is centered at (7, -3) and has radius 9, the only answer that fits is the second one. (x - 7)² + (y + 3)² = 81