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4a 7b 3a-2b 2a;a=-5 And B=3 Help

Algebra 2 Help Needed Please?

What's so hard about doing this? Just put in the stated values for the variables, and evaluate what the expression gives you. The alternates show what you get if you collect terms first. And of course you know that negative times negative equals positive...

1.) 4a + 7b + 3a − 2b + 2a; a = −5 and b = 3
[4 × (−5)] + [7 × 3] + [3 × (−5)] − [2 × 3] + [2 × (−5)]
= −20 + 21 − 15 − 6 − 10
= −30
or
4a + 7b + 3a − 2b + 2a
= 9a + 5b
= [9 × (−5)] + [5 × 3]
= −45 + 15
= −30

2.) 5y − 3z + 4y − 1z − 3y; y = 3 and z = − 2
[5 × 3] − [3 × (−2)] + [4 × 3] − [1 × (−2)] − [3 × 3]
= 15 + 6 + 12 + 2 − 9
= 26

3.) 12a² − 3ab + 2b; a = − 5 and b = 4
[12 × (+25)] − [3 × (−5) × 4] + [2 × 4]
= 300 − (−60) + 8
= 300 + 60 + 8
= 368

4.) −k² − (3k − 5n) + 4n; k = − 1 and n = − 2
−k² − 3k + 5n + 4n
= −[(−1)²] − [3 × (−1)] + [5 × (−2)] + [4 × (−2)]
= −[+1] − [−3] + [−10] + [−8]
= −1 + 3 − 10 − 8
= −16
or −k² − 3k + 5n + 4n
= −k² − 3k + 9n
= −[(−1)²] − [3 × (−1)] + [9 × (−2)]
= −[+1] − [−3] + [−18]
and as before.

5.) 3y − (4y + 6x); x = 3 and y = −2
3y − 4y − 6x
= [3 × (−2)] − [4 × (−2)] − (6 × 3)
= [ −6 ] − [ −8] − [ +18 ]
= − 6 + 8 − 18
= −16
or
3y − 4y − 6x
= − 1y − 6x
= − [1 × (−2)] − (6 × 3)
= [ 2 ] − [ +18 ]
= 2 − 18
= −16

Combining like terms help! 7b-(3a-8b) -(3x-4y)+x?

then can you help me with evaluating these expression for the given values or the variables

4a+7b+3a-2b+2a;a= -5 and b=3

-5(x+2y)+15(x+2y); x=7 and y=-7

thank you!

What is 4a + 7b + 3a - 2b + 2a =?

4(-5) + 7(3) + 3(-5) - 2(3) + 2(-5)
-20 + 21 + (-15) - 6 + (-10)
1 + (-15) - 6 + (-10)
(-14) - 6 + (- 10)
-14 + -6 + (-10)
-20 + -10
= -30

If 2a + 3b + 4c = 35 and 3a + 5b + 7c = 30, then how do I find a + b + c?

Starting with the second given equation;3a + 5b + 7c = 30(2a + 3b + 4c) + (a + 2b + 3c) = 3035 + (a + 2b + 3c) = 30a + 2b + 3c = -5______(1)Now, using the first equation2a + 3b + 4c = 35( a + 2b + 3c) + (a + b + c)=35-5 +(a + b + c)=35 [ using__(1)]a + b +c=40

What is this expression equals to: -5 (a + b) +2 (2a – b) + 4 a -7?

-5(a+b) + 2 (2a - b) + 4a - 7 ?-5a-5b + 4a - 2b + 4a - 7. By expansion-5a + 8a - 7b -7 …by addition and subtraction.. 3a - 7b - 7…or.. 3a - 7(b+ 1).answer.

If a=6 and b=5, what is the value of 3a+2b ?

The answer is 28.If a=6; b=5What is 3a+2b?Since the value of a and b are already given, we can now substitute it to 3a+2b.=3(6)+2(5)The given has two operations to be used: Multiplication and Addition.Don’t forget to follow PEMDAS.Let’s deal first with Multiplication before Addition.=18+10= 28Therefore,If a=6; b=5,Then3a+2b= 28

A+b=5 ab=3 then what is the value of a-b?

a+b=5 and ab=3Then (a+b)^2=25a^2+b^2+2(ab)=25a^2+b^2=25–6=19Then (a-b) ^2=a^2+b^2-2(ab) =19–6=13Then a-b =√13=3.6055

How do I simplify (2a - 3b) x (3a + 2b) where a and b are vectors and x represents the cross product between the two?

Multiply the two binomials, taking care to preserve the order of the factors:6 a x a + 4 a x b - 9 b x a - 6 b x b.The cross product is proportional to the sine of the angle between the two vectors, so the cross product of any two parallel vectors is zero. This leaves us with the second and third terms. Also, the cross product is anti-commutative (b x a = - a x b), so we are left with 4 a x b + 9 a x b = 13 a x b.

What's (4a+3b-6) + (2a-b+4) - (-3a-2b) simplified?

To simplify (4a+3b-6) + (2a-b+4) - (-3a-2b) you have to group all the terms with ‘a’, ‘b’ and all terms without a variable in them.To do this let's start with all terms that have an ‘a’ in them. If we look at the equation we see ‘+4a’, ‘+2a’ and ‘-(-3a)’. This will come down to 4a+2a-(-3a). Since minus times a minus equals a positive, the simplified a term will become: 4a+2a+3a = 9aNow we do the same for all terms with the ‘b’. We see ‘3b’, ‘-b’ and ‘-(-2b)’. This is equal to 3b-b+2b. This means that all terms with ‘b’ simplify to 4b.Now we group all terms without a variable. Here we see ‘-6’ and ‘+4’. This is equal to -6+4 which results in -2.Now on to the last step! Combining our results, in the form all ‘a’ terms + all ‘b’ terms + all terms without a variable. This results in:9a + 4b -2I hope this helped!

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