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8 Hard Random Questions

Some More Questions on NRL 2010?

1. What is Your Favourite Team?
St George Illawarra Dragons

2. Who is your Favourite player?
Coops and B Moz

3. Who will be the top 8 for 2010?
In no order:
Dragons
Storm
Broncos
Knights
Souths
Eels
Bulldogs
Titans

4. Who is your least favourite team?
Bulldogs

5. What player would you like to be tranfered into your team?
Jarryd Hayne

6. What Player would you like to see gone from your team?
Dan Hunt

7. What is your favourite International side?
Aussie!!!!

8. Favourite State of Origin Side?
NSW.. Go the blues!

9. Least Favourite Player (from any team)?
Just one... too hard.

and last a RANDOM QUESTION

10. What position is your favourite?
On top... of the ladder ;)

Hard ACT Math Question?

Originally the fraction of red marbles is 12/32. Let x be the amount of marbles added. The added marbles are all red so the new fraction is (12 + x)/(32 + x). Set that equal to 3/5.

(12 + x)/(32 + x) = 3/5

Cross multiply.
5(12 + x) = 3(32 + x)
60 + 5x = 96 + 3x
2x = 36
x = 18

Hard AP Statistics probability questions?

One hundred Lower Wabash Tech students take a 10-question multiplechoice test with four answers to each question, exactly one of which is correct.
All of the students are unprepared and must guess at each question.

(a) Identify the random variable of interest, and justify your answer.
Determine the probability distribution of this random variable. That is, determine the probability of getting each possible score.
(b) Of the 100 test takers, how many are expected to get each possible score?
(c) Richard is one of the test takers. Determine the number of questions he
can expect to get correct on the test by random guessing.
(d) How many unprepared students would have to take this test to guarantee
ten scores of 6? Ten scores of 7? Ten scores of 8? Show your work or explain
your reasoning.
(e) Sarah also takes the test, and she wants to know how many correct answers
she and Richard can expect to get all together. Answer Sarah’s question.
(f) What is the standard deviation of the difference between Sarah’s and
Richard’s scores?
(g) Richard wants to know how many questions he will have to answer until
he gets one correct. Has the random variable changed (i.e., is it now different
from the one you identified in (a)?)? If so, identify this new random variable
and justify your answer. Then answer Richard’s question

Prob Question with 12 computers?

A computer retail store has 12 personal computers in stock. A buyer wants to purchase 3 of them. Unknown to either the retail store or the buyer, 3 of the computers in stock have defective hard drives. Assume that the computers are selected at random.

a) In how many different ways can the buyer's 3 computers be chosen? answer = 220


b)What is the probability that exactly one of the computers bought will be defective?

What are the trickiest Java questions?

There is plenty of tricky questions; but few are useful in interviews. e.g.1) What does this code do?for (char ch = 0; ch < Character.MAX_VALUE; ch++)
if (Character.isJavaIdentifierPart(ch) && !Character.isJavaIdentifierStart(ch))
System.out.printf("%04x <%s>%n", (int) ch, "" + ch);
This code compiles and runs inside a main method.Vanilla #Java: Hidden code2) What does this program do if you compile it on Windowsclass Con {
static final String hi = “\n\n\Hello World\n\n";
}
Hint: you only need compile it, not run it.Strange Hello World in Java3) How does this Hello World program using random numbers work?public static void main(String ... args) {
System.out.println(randomString(-229985452)+' '+randomString(-147909649));
}

public static String randomString(int seed) {
Random rand = new Random(seed);
StringBuilder sb = new StringBuilder();
for(int i=0;;i++) {
int n = rand.nextInt(27);
if (n == 0) break;
sb.append((char) ('`' + n));
}
return sb.toString();
}
printshello world
Randomly not so random4) A longer puzzle involving using String literals for locks while mutating them.Bad String5) What are the 22 possible types and values for x where this is truex == -x
6) How can you use Unsafe to show whether objects are being allocated forward, back word or randomly in memory? Similar; how can you use Unsafe to change the class of an object after it has been created?In short, never do any of these in Production, or ask tricky questions like these in interviews.Answers to question 5.you have 7 values for zero 0 for type byte, char, short, int, long, float, double.you have two more for -0.0 and -0.0f and floating point also has a negative zero.you have two more for Integer.MIN_VALUE and Long.MIN_VALUE as -Integer.MIN_VALUE overflows back to Integer.MIN_VALUEThat makes 11, expect you also have auto-boxing and the wrapper type for each of the answers above makes 22.

A HARD Stats Question About:Probability?

e. 6 women
Let x=the number of women in group 2. The probability that both the students are the same gender is (8/20)*(24/(24+x)) + (12/20)*(x/(24+x)).
This simplifies to (2/5)*(24/(24+x)) + (3/5)*(x/(24+x)).
So we get (48/(120+5x)) + (3x/(120+5x)) = 0.44
So now we cross multiply by (120+5x)
Which gives: 48 + 3x = 52.8 + 2.2x
Then by simple algebra 0.8x = 4.8
Therefore x = 6

I downloaded sample papers for the BITSAT. I found the question paper easy. I scored 392/450. Are the BITSAT questions really only of this standard?

I don't know the standard of the previous paper you have chosen or rather I can't comment on the credibility of the source from which you attempted these questions. BITS Admission Test is a test of your knowledge in Grade 11th and 12th NCERT syllabus of Maths, Physics and Chemistry. Additionally, it also tests English and Logical reasoning. While you must have noted down the number of questions from each of these respective sections, what nobody tells you is how a BITSAT question paper, on a given random day, is generated. Consider that there is a question bank containing 1.5 lakh plus questions from all sections. The server of BITSAT chooses over 250 questions on a given slot and assigns 150 questions to each student such that the level of difficulty is maintained according to the scale given below. 20% of questions are very easy 30% of questions are easy 30% of the questions are medium20% of the questions are hardHaving said that, this weightage ratio is applicable to the complete set ie. 150 questions and not to individual sections. For example, you might get all very easy and easy questions in math and not get all hard level questions in Chemistry. An additional point, keeping away from your exact question, is that as much as 7-8 can appear from a single chapter of a subject. Hence, it is advisable for you to keep track of your progress in all the subjects and all chapters equally.

(Probability Question) 3 parts?

A computer retail store has 10 personal computers in stock. A buyer wants to purchase 4 of them. Unknown to either the retail store or the buyer, 4 of the computers in stock have defective hard drives. Assume that the computers are selected at random.

(a) In how many different ways can the 4 computers be chosen?

answer: 10!/(6!*4!)

(b) What is the probability that exactly one of the computers will be defective?

answer:

(c) What is the probability that at least one of the computers selected is defective?


I need parts b and c still

Probability question!?!? please help?

a) 8C2 = 8! / [2!(8-2!)] = (8×7×6×5×4×3×2×1) / (2×1×6×5×4×3×2×1) = (8×7) / (2×1) = 28 ways
b) There are 6 ways to get a pair that has only the first defective computer in it, and 6 ways to get a pair that has only the second defective computer in it, for a total of 12 ways. The probability is 12/28 = 3/7
c) As we saw in part b, there are 12 ways to get exactly one defective computer. There is 1 way to get both defective computers. So the probability is (12+1)/28 = 13/28

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