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A Balloonist Is Preparing To Make A Trip In A Helium-filled Balloon.

Helium Filled Balloons in Heaven?

Yup. and that is precisely what handed off to this guy. Who can say what handed off to him up there? per chance, the skies opened in simple terms earlier his balloons gave and God in simple terms took him in His preserving. seems this become once now no longer his first stint with the get mutually balloons. He offered fortunate the widespread time and easily strayed from Brazil to the Argentine border. He needed a gimmick for some charity artwork. His disappearance confident attracted a spread of concentration. desire he's allright.

Helium Filled Balloons in Heaven?

Yup. and that is precisely what handed off to this guy. Who can say what handed off to him up there? per chance, the skies opened in simple terms earlier his balloons gave and God in simple terms took him in His preserving. seems this become once now no longer his first stint with the get mutually balloons. He offered fortunate the widespread time and easily strayed from Brazil to the Argentine border. He needed a gimmick for some charity artwork. His disappearance confident attracted a spread of concentration. desire he's allright.

I did my research before trying this out, and I think it’s safe. Just don’t abuse it. I inhaled it from a balloon, but I didn’t inhale several times. I just did it after I waited a while to do it again. Don’t do what I did though, because it may have different affects for others. For example, I’ve been swimming in a team and playing a brass instrument for years, so I have bigger lungs. If you still want to try it out, do your research, and DON’T abuse it! There has been some deaths related to this. If you’re are curious on how it feels, here’s my description: When you inhale it, the helium tastes like minty air, and your voice sounds just like how you would expect it would after inhaling helium.

As many others have answered, lead has been made to work. I'm confident that gold foil would work, too, and that's almost as dense as a substance can be. Your question has too many unknowns to answer more precisely than that.There is a way to do better, though. Assume the balloon is a sphere. The mass of the air that sphere displaces is[math]\frac{4}{3}\pi r^3\rho_{air}[/math]That's just the volume of a sphere times the density of air.The mass of the balloon is:[math]\frac{4}{3}\pi {r_1}^3 \rho_{He}+\frac{4}{3}[/math][math]\pi [/math][math](r - r_1)^3\rho_{skin}[/math]That's the volume of a sphere times the density of helium plus the volume of the balloon (which we treat as a spherical shell) times the density of the material you use for the skin. [math]r - r_1[/math] is the thickness of the shell.As you can see, you have three unknowns. The thickness and the density of the skin, and the size of the balloon.It turns out that the bigger the balloon, the less lift you need to pick it up. At a certain size, the mass of the air is huge compared to the skin (So long as the skin is thin) and so it almost doesn't matter what it's made of. But very small balloons cannot float unless they are made of something very lightweight.Take my chemistry class - you'll learn all about this while building a paper hot air balloon.

What is the average speed of a particle of helium inside the balloon? What is the thermal energy of the helium in the balloon?

a) Use root-mean-square velocity:
v = √(3RT/M),

where v is velocity,
R is universal gas constant,
T is temperature (absolute),
and M is molar mass.

Make sure the units all match. If R is 8.314 J/mol/K, then T needs to be in K and M needs to be in kg/mol.

v = √( 3 * 8.314 J/mol/K * 293 K / (4g/mol * 1kg/1000g) )
v = 1350 m/s (rounded to 3 sig-figs)

b) Thermal energy is equal to the kinetic energy:
KE = 1/2 m v²

We already found velocity, now we need to use the ideal gas law to find the mass:
PV = nRT
n = PV/RT
n = (1.1 atm * 10 L) / (0.0821 L atm / K / mol * 293 K)
n = 0.457 mol

m = n * M = 0.457 mol * 4 g/mol = 1.829 g

KE = 1/2 m v²
KE = 1/2 (0.001829 kg) (1350 m/s)²
KE = 1670 J

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Ah this is the beauty of physics. You don’t need to break the calculations. Just take a reference and let physics do it’s magic.Let’s assume ground to be a reference and upward direction as positive.[math]x = x_o + ut + (1/2) at^2[/math]where x = final position = 0 [since ground is reference][math]x_o[/math] = initial position = +25 [above the reference level]u = initial velocity = +7 m/s [positive because it is in upward direction]t = time taken to strike the grounda = -g [negative because gravity is acting in negative direction]so,0 = 25 + (7 * t) + (0.5) * (-10) * [math]t^2[/math]=> [math] 5t^2 - 7t -25 = 0[/math]Solve for t. It comes out to be 3.1 seconds

In order to get a floating balloon you want a gas which is as light as possible.  Helium is quite a lot lighter than air weight.  It’s about and eighth of the density of air.  Hydrogen is about a sixteenth the density of air.  So it’ll float in air and will even float upwards. You’d have thought that hydrogen would be a better gas as it would give slightly more lift than helium because it’s lighter.  This is true.  The problem is hydrogen is explosive and if you have children running around with balloons that could catch fire and blow up in their faces, it may have some health and safety implications.  The other thing is that although hydrogen is half as heavy as helium it doesn’t give you twice as much lift because the amount of lift you get is in its difference in density with [respect to] air.  It’s actually only another sixteenth of the density of air.  It’s a little bit better but not very much, so it’s not worth the danger.Helium is quite expensive, though, because it’s a limited resource here on the planet. It's only created by radioactive decay on Earth.  Atomic nucleuses emitting alpha particles that are actually helium nucleuses.  They slow down and gain some electrons and turn into a helium atom.  It tends to be found in oil wells where you get a gas-proof layer of rock above a load of rocks containing radioactive elements.  They break down to helium.  It floats up and gets trapped, often at the top of an oil well . The amount of helium that we can access cheaply is very limited because not all our oil wells have it.

In a hot-air balloon rising vertically with a constant velocity of magnitude 5.00 m/s, the hot-air balloonist?

Let the bag take t sec to gain its maximum height (h)
=>By v = u - gt
=>0 = 5 - 9.8 x t
=>t = 0.51 sec
& by v^2 = u^2 - 2gh
=>0 = (5)^2 - 2 x 9.8 x h
=>h = 1.28m
(a) By v = u - gt
=>v = 5 - 9.8 x 0.25
=>v = 2.55 m/s (upward)
By s = ut - 1/2gt^2
=>h = 5 x 0.25 - 1/2 x 9.8 x (0.25)^2
=>h = 0.94 m
Thus position = 40 + 0.94 = 40.94m (from ground)
(a)(ii) Let it gain velocity v after falling from (40 + 1.28 =) 41.28m in (1-0.51 =) 0.49 sec
Thus by v = u + gt
=>v = 0 + 9.8 x 0.49 = 4.80 m/s
& by s = ut + 1/2gt^2
=>h = 0 + 1/2 x 9.8 x (0.49)^2
=>h = 1.18m
=>Thus position = 41.28 - 1.18 = 40.10m(from ground)
(b) Let it take t sec to fall 41.28m
=>By s = ut + 1/2gt^2
=>41.28 = 0 + 1/2 x 9.8 x t^2
=>t = √8.42
=>t = 2.90 sec
Time to strike ground after release (T) = 0.51 + 2.90 = 3.41 sec
(c) By v = u + gt
=>v = 0 + 9.8 x 2.90
=>v = 28.42 m/s
(d) 41.28 m
(e) do it yourself.

I think you are suggesting that walking around with some helium-filled balloons attached to you would take some of the weight off your legs and make it easier to walk.  The problem is that the balloons would have to be too large to be of any help.  It take about a cubic meter of helium to lift a kilogram.  A balloon about 4 m in diameter would have a volume of about 32 m^3 and would lift about 32 kg.  But how would you get it through doorways, onto buses, into elevators, etc.  Also, the slightest wind would blow you away.  This is not a practical way to help someone walk.

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