Magnetic fields and forces question?
For a) and b), use Ampere's Law: ⌡BdscosΘ = µI, where B is the magnetic field, ds is the tangential path of the Amperian Loop, Θ is the angle between these two, µ is the coeffiecent of magnetic permeability, and I is the current generating the electric field. Let the distance r represent the 0.18 m separation. IA is current from wire A and IB is current from wire B. a) ⌡BdscosΘ = µI ⌡Bds = µIA B⌡ ds = µIA B = µIA/2πr B = 2.2 x 10^-6 T b) For the other wire, just switch IA for IB. B = 4.6 x 10^-6 T c) Clearly these magnetic fields are not equal and opposite. The dependance of current in the equation does not allow since the currents are in fact different. d) Now that we have the magnetic field, we may use one of the magnetic force equations: F = ILBsinΘ Where I is the current, L is the length of the wires, and b is the magnetic field. Force on A due to B: F = ILBsinΘ =IALB = IALµIB/2πr Force per unit length on A due to B: F/L = IAµIB/2πr F/L = 9.1 x 10^-5 N/m For the other wire, the force will be the same because the equation has a dependance on both currents.
Physics: magnetic field and force question?
1. NO NO NO!! : ). Don't think of electric potential energy as the same as electric potential. However, they are related in that P.E.=EPE/q. 2. The size of the circle depends on how much charge is within and around the circle. Force and momentum of a charged field are related in that the force due to centripedal acceleration must be equal to the momentum given off in the tangential direction when floating around an orbit so as to not go out or into the center. The higher the charge of a particle, the larger the ring. If you know about photons and light, these work on the same principle in that when an electron is in a higher energy state, the way that an electron moves down to lower energy states is by releasing energy in the form of a photon. Thus, you can think of this as your 'size' of the particle. When at higher energy states, the electron is farther away from the center due to all of the energy that was once stored in it. Then once it releases its energy, the state of the electron lowers and a photon is released. So, more energy, bigger circle. Hope that helps!
Magnetic force question!?
Hi, It is situation no (1) i.e. Current in the wire flows straight down,the magnetic field points due west. See,the direction of magnetic force in a current carrying conductor can be determined with the help of Flemming's left hand rule.This rule states that: If the thumb,index finger and middle finger of left hand are kept in mutually perpendicular direction then,if the index finger denotes direction of magnetic field and middle finger shows current direction then the thumb will represent the direction of magnetic force. The flemming's left hand rule is also known as MOTOR RULE.
A magnetic field force question?
A cable 100 m long carries current of 50 A and is pointing due magnetic north and the magnetic field is 70 degs to the horizontal at this point. The cable is horizontal to the ground .. what is the force exerted by the magnetic field on the cable.. my problem is the answer given in the book seems incorrect.. dF = Idl x B I get this as the magnetic field of the earth will be constant over the length of the wire please tell me if this assumption is incorrect. 0.5*10^-4 T since current is constant.. and angle is constant.. the formula should simplify to F = I * L * B * sin theta.. since the cross product is the first turned into the second so that the angle is not 70 degs but 110 degs rotation between the current and the B field. F = 50*100*0.5*10^(-4) * sin(110) F = 0.235 N can you verify this answer the books answer is F = 7.15*10^-1 N which I think is incorrect..
Magnetic field and Magnetic Force?
No. incorrect to declare that magnetic field is a tension between charged debris. that's no longer sparkling. A magnetic field exists whilst an electric cutting-edge flows or whilst (as Richard states above) whilst a can charge is in action. enable us to declare, there are 3 extensive classifications for those motions. a million. Linear action interior the Z-axis as a results of actual tension or elastic collision. 2. Spiral action. that's the stress between charged debris. that's Electrostatic tension interior the X-axis. 3. Turbofan propulsion. that's the stress as a results of a charged particle in action. that's Magnetic field or tension interior the Y-axis. Michael Faraday defined strains OF tension interior the MAGNETIC field. to discover this, take a bar magnet, conceal it in a Newspaper, and drag it interior the unfastened dirt. Iron filings will carry onto the paper. Now, save the filings on a flat white paper, and draw the bar magnet below the paper. you will see the iron filings set up alongside the Magnetic strains of tension interior the Magnetic field. Q.O.D.
How to block out magnetic field force ?
This would work the same as blocking a signal except you would need a bigger inductor. Assuming that the field is electromagnetic other than that it couldn't be done. What you would do is have a capacitor go to a non-inverting amplifier and to have it's output go directly to one transistor and to have a resistor go to a second in series with it going the same direction as the transistors. Both transistors should be necessary to drain the capacitor. from the output of the non-inverting amplifier you would have an inverting amplifier feed back to the capacitor with a resistor. Another way is to use an exclusive or gate and to have 2 resistors feed back to it's inputs and have capacitors to ground. with a small inductor these circuits should be good for a house. If you need more please e-mail me.
Physics Magnetic force questions, how do i do these!?
So, i have no idea how to even start any of these. If you could explain how or give me an equation to get on the right track that would really help! There are 3 or 4 here. I just don't know where to begin any. Even if you can help with just one that would be great! Thank you so much A conducting bar of length 0.20 m and mass 21.0 g is suspended by a pair of flexible leads in a uniform 0.10 T magnetic field (directed into the page) as shown in the figure. What is the current required to remove the tension in the supporting leads? Supply a "-" sign if the current must flow from right to left. picture 1: http://i861.photobucket.com/albums/ab173/NorbertEh/HangingWire.jpg A 62.0 cm wire carries a current of 2.40 A. The wire is formed into a circular coil and placed in a Magnetic Field of intensity 1.90 T. Find the maximum torque that can act on the loop. The figure shows a rectangular loop of wire of 70 turns, 12.0 by 28.0 cm. It carries a curent of 1.06 A and is hinged at one side. What is the magnitude of the torque that acts on the loop, if it is mounted with its plane at an angle of 46.0 degrees to the direction of B, which is uniform and equal to 0.80 T? picture: http://i861.photobucket.com/albums/ab173/NorbertEh/TorqueOnSquareLoop.gif The diagram below depicts a wire carrying a current I = 4.80 A. The wire splits into two channels; of resistance = 7.45 and = 4.00 , and re-joins, forming a current loop in the shape of an isosceles triangle with base distance d = 5.75 cm and height L = 16.0 cm. The loop is entered into the space between the two poles of a magnet with a uniform magnetic field, B = 3.05 T, that runs from one pole to the other. The loop is placed such that the field lies in the plane of the loop. What is the magnitude of the torque on the circuit about the wire's axis? picture: http://i861.photobucket.com/albums/ab173/NorbertEh/TriangularWire.gif