Add maths coordinates geometry help?
The point P lies on the line joining A(9-1,-5) and B(11,13) such that AP= 1/3AB (i) Find the equation of the line perpendicular to AB and passing through P. The line perpendicular to AB passing through P and the line parallel to the x-axis passing through B intersect at the point Q (ii)Find the coordinates of the point Q. (iii)Find the area of the triangle PBQ.
Help with add math questions on coordinate geometry -circles ?
sorry, just working, no explanation a) 12y=7x+29→y=(7x+29)/12 x^2+y^2-16x+18y-48=0 x^2+(7x+29/12)^2 -16x+18(7x+29/12)-48=0 x^2+(49x^2+406x+841/144)-16x+(21x+87/2)... 144x^2+49x^2+406x+841-2304x+(3024x+1252... 288x^2+98x^2+812x+1682-4608x+3024x+1252... 386x^2-772+386=0 -> x^2-2x+1=0 (x-1)=0 x=1 12y=7(1)+29 y=3 b) 3y+2x+1=0 -> x=(-3y-1/2) x^2+y^2-8x+6y-27=0 (-3y-1/2)^2+y^2-8(-3y-1/2)+6y-27=0 (9y^2+6y+1/4)+y^2+12y+4+6y-27=0 9y^2+6y+1+4y^2+48y+16+24y-108=0 y^2+6y-7=0 y-1=0 -> y=1 and y+7=0 -> y=-7 when y=1, 3+2x+1=0 x=-2 when y=-7 3(-7)+2x+1 2x=20 x=10 Hope it helps. There's some equation that I simplify straight away.
Geometry Math Question helpp!?
Since AD and DC are marked as congruent, then they have equal lengths. Set the lengths equal to each other and solve the equation to find y. Then replace y with the value you find in the expression 2y in order to find the length of DC. AD = DC y+6=2y y+6-y=2y-y 6=y Since DC = 2y, DC = 2(6) = 12
Math; Geometry How do you find the coordinates of two vertices of a parallelogram?
Hi, I have a homework question. I have two vertices of a parallelogram they are A(2,3) and B(8,11). I also have an intersection of the diagonals which is X(7,6). How can i find the coordinates of the other two vertices? Thanks in advance:)
Can anyone help me with COORDINATE GEOMETRY - EQUATIONS OF LINES ??! Please!!?
#1 Indicate in standard form the equation of the line passing through the given points. A(4, 1), B(5, 2) #2 Indicate in standard form the equation of the line passing through the given points. R(3, 3), S(-6, -6) #3 Indicate in standard form the equation of the line passing through the given points. B(0, 0), C(4, -4) #4 Indicate in standard form the equation of the line passing through the given points. P(6, 2), Q(8, -4) #5 Indicate in standard form the equation of the line passing through the given points. M(0, 6), N(6, 0) #6 Indicate in standard form the equation of the line passing through the given points. E(-2, 2), F(5, 1) #7 Indicate in standard form the equation of the line passing through the given points. G(4, 6), H(1, 5) #8 Indicate in standard form the equation of the line passing through the given points. L(5, 0), M(0, 5) #9 Indicate in standard form the equation of the line passing through the given points. X(0, 6), Y(5, 6) #10 Indicate in standard form the equation of the line passing through the given point and having the given slope. A(5, 5), m = 3 #11 Indicate in standard form the equation of the line passing through the given point and having the given slope. B(6, 2), m = - 1/2 #12 Indicate in standard form the equation of the line passing through the given point and having the given slope. C(0, 4), m = 0 Please if you know how to solve help! Thank you!
Help with an add maths problem involving coordinate geometry?
This question giving me some trouble so thanks in advance to anyone who helps me! :D 1) In the quadrilateral ABCD Shown in the diagram, BD is the perpendicular bisector of AC. The midpoint of AC is M. The coordinates A and M are (2,6) and (5, 5) respectively. AB is parallel to OM. O, D and C are collinear points. Find: a) The coordinates of C b) The equation of AB, of BD and of CD. c) The coordinates of B and of D. d) The area of the quadrilateral ABCD. :) Thanks
Find Additional Coordinates?
You can add 2pi to the angle and it has no effect (because 2pi is 360 degrees, an entire circle). So #1 you could use an angle of -7pi/6 + 2pi = 5pi/6. If the restriction is -2pi < theta < 2pi then the book answer is wrong. (As an aside, if the the magnitude is 0 then any angle will work). For the second, subtact 2pi to get (3, -3pi/2). If you need to find a second alternate representation, then multiply the magnitude by -1 and add (or subtract( pi to the angle. That gives a negative vector in the opposite direction, i.e. overall it's the same. i.e. (3, pi/2) = (3, -3pi/2) = (-3, -pi/2) = (-3, 3pi/2)
How can I download a PDF of Coordinate Geometry by SK Goyal for the IIT JEE?
You can give me your email id in the comment section or personal message. I have hell lot of pdf books including cengage series, resnick halliday, N Avasthi, DC Pandey etc.So if you need them , you can contact me anytime I'll be more grateful to you if upvote.EDIT: I am adding few pdf links for time being. I will add more, do follow me for updates.Irodov-Problems_in_General_Physics (1).pdfNarendra Avasthi-Problems in physical chemistry for JEE Main & Advanced-Shri Balaji Publications (2014).pdfmechanics 2.pdfDavid Halliday, Robert Resnick, Jearl Walker-Fundamentals of Physics-Wiley (2010).pdfOrganic Chemistry-T. W. Graham Solomons (1).pdfThank you.
How should I prepare for trigonometry and coordinate geometry for IIT?
By doing quality questions asked in different ways like MCQ, Integer Types, Matrix Match.Now you need a quality book to complete the above task. I think for objective type examination books of G.Tewani are really good. I had his books for Calculus and Algebra. It really helped me a lot. Don’t worry about the theory. It has enough theory part needed to understand the concepts. Contains detailed examples. I am adding the links for trigonometry and coordinate.Buy Mathematics for Joint Entrance Examination JEE (Advanced): Coordinate Geometry Book Online at Low Prices in IndiaBuy Mathematics for Joint Entrance Examination JEE (Advanced): Trigonometry Book Online at Low Prices in IndiaPrepare well. :)All the best.