Alevel Physics Question

A-level physics question?

A ball is projected vertically upwards with speed 21 m s–1 from a point A, which is 1.5 m
above the ground. After projection, the ball moves freely under gravity until it reaches
the ground. Modelling the ball as a particle, find the time between the instant when the ball is projected from A and the instant when
the ball reaches the ground.

A level physics question?

a) Elastic behavior is when an object deforms by stretching the bonds between molecules (or atoms in case its an atomic crystalline structure). In plastic behavior, you are breaking and re-arranging the bonds. Let's consider a loaf of bread, like regular Wonder bread. If you just tug on the ends a lightly, the loaf will stretch a little, and when you release, it will spring back. That's elastic behavior. When you pull on the loaf forcefully, the loaf will tear. That's plastic behavior. When you release the loaf, some of it springs back, but the tears are still there. The spring back is elastic behavior, the persistence of the tears is plastic behavior.

b) repeated stress applied to an object such that it undergoes plastic deformation, leads to something called fatigue failure. When you bend the metal bar only slightly so that it remains in its elastic zone, then all of the bar springs back to the original state when you release it. If you bend it past its elastic zone, some of bar will spring back elastically, and the rest of it will remain plastically deformed (some bonds were stretched beyond their elastic limit and broke, and those bonds don't spring back). In most materials, microscopic cracks will form where the bonds are broken. You do that enough times, and the cracks will grow and propagate through the object until it fails.

Most structural objects that are subject to oscillating/vibrating stresses must be designed so that the object never gets bent past its elastic zone, or else, the part will grow closer to failure with every vibration. Or if you can't do that then you design the part so that it's replaceable, calculate the estimated part life, and always replace the part before it reaches the end of its life.

A-level Physics question?

Study really hard, and try to concentrate on your studies. I know you're probably already doing that, and its not working, so here are a few tips- Search for a tutor. If you can't afford one, try to have a study partner at least. Make sure your base is strong, if you forget the basics you can't build on it. Recheck your base. Search for videos online. This is a website I use pretty often, its really cool. It has all kinds of awesome videos, and the creator featured in Time Magazine's top 100 most influential. Google gave him 2 million USD. www.khanacademy.org
Ask us what you don't understand. Try to contact some people by email, see if they can help you. Put in the extra hour, and make sure you're fresh while you're studying. Set simple goals, and strive to fulfill them. Get your sleep. This is really important. (http://www.khanacademy.org/cs may be the section you're looking for btw) Ask your teacher's for explanations. Don't be embarrassed, what's important is that you UNDERSTAND. If all this doesn't work, only then consider switching. Hope this helped!

A-level Physics question!?

Yes an A grade at GCSE in Maths is good enough grounding and you don't have to do Maths at A level. Having said that they do help each other enormously. The Maths you learn will really help with the Physics(and Chem) and the Physics will really help with the Applied Maths.
If you want to study Physics at tertiary then a good founding in maths is essential, You'll find yourself doing some demanding Maths stuff at Uni in Physics

A-Level Physics Questions?

1. Dynamics question

A rocket stands vertically on its launching pad. Prior to ignition, the mass of the rocket and its fuel is 1900 kg. On ignition, gas is ejected from the rocket at a speed of 2500 ms^ -1 relative to the rocket, and fuel is consumed at a constant rate of 7.4 kgs^ -1. Find the thrust of the rocket and hence explain why there is an interval between ignition and lift-off.

(Note: take acceleration of free fall, g, to be 10 ms^ -2.)

Ans: 18500 N

2. Interference (Superposition) question

Sound from a small loudspeaker L reaches a point P by two paths which differ in length by 1.2 m. When the frequency of the sound is gradually increased, the rsultant intensity at P goes through a series of maxima and minima. A maximum occurs when the frequency is 1000 Hz and the next maximum occurs at 1200 Hz. What is the speed of sound in the medium between L and P?

Ans: 240 ms^ -1

A-level physics question about charge?

Hey, electric field is highest at the surface of the charged sphere and then reduces in radially outwards direction. Calculate the electric field as E = K.q/r where K is coulomb's constant, q is the charge on sphere and radius is the radius of charged sphere. As you can see q comes to be a function of r for any given E.
The above formula can be rearranged as q = E.r /K
This means that for a fixed value of E (3*10^6 in this case) q is directly proportional to r or inversely proportional to curvature (pointedness).
This means the lesser the radius of curvature (more pointed the object) the lesser its capacity to hold charge so that E doesn't exceed the stated value.

A-Level Physics question help?

This is Hook’s Law.
Basically the extension of a spring is linearly proportional to the load.
In other words double the load you double the extension.


Let the length of the spring before any load is added be c
Let extension per Newton be m
Let load be y Newtons

So length of spring (y) for N newtons is

y = mx + c EQUATION #1

This is the stand form of a straight line slope of m. I hope you recognise that.

But we know y =20 when x =10
And y =30 when x = 20

SO these two datum points are solutions to EQUATION #1

Remembering your co-ordinate geometry
Slope m = YStep/Xstep

m = (30-20)/(20-10) = 10/10 = 1

so we now know y = x + c

lets find c by putting in values for load 1

20 = 10 + c

so c = 20-10 =10

So the equation for the extension of the spring is just
y = x + 10 EQUATION #2

Using EQUATION #2 to answer the questions (Straight line graph)

question a) When no load x = 0 so y =10 so spring is 10cm with no load (not 10 Newtons)

question b) for load x=5 y = 5+10 = 15 so spring is 15cm long with a load of 5 Newtons

A-level physics questions?

definite an A grade at GCSE in Maths is stable sufficient grounding and you do no longer would desire to do Maths at a point. in spite of this they do help one yet another rather. the math you study will particularly help with the Physics(and Chem) and the Physics will particularly help with the utilized Maths. in case you prefer to examine Physics at tertiary then a stable founding in maths is mandatory, you will finally end up performing some demanding Maths stuff at Uni in Physics

A level physics question about potential?

The E.M.F. of a 6v battery is barely 6v off load via fact the present will boost a voltage is progressed around the internal resistance it incredibly is a ability difference (v=I x R) this reasons a decrease voltage on the terminals (V = E,M,F- v=I x R) as for something of a circuit the present bypass by using each and each sequence resistor a ability difference will boost proportional to the modern-day bypass and Resistance (V =I x R) so if the fee of two resistors have been equivalent the availability voltage may be halved,(Sum of the P.D,s equals the E.M.F.)