Is Algebra 2 easy or hard?
I had Geometry last year and I was absolutely terrible at it. I did Algebra 1 the year before and I did really good. Last year baffled my parents a lot because I had never been bad at math, and I got like a C. I thought Algebra 2 was going to be a lot easier, and in some ways it is. But don't think it's an easy class in any way. It requires decent amounts of studying if you're not a naturally good at math student. I am doing better this year, like a B, but not as good as I hoped because of my heavy course work. I'm currently taking AP US history and AP Biology which are both hard courses plus my regular classes. It's not that easy but I'm juggling it alright. Overall, Algebra 2 could be considered easier than Geometry if you are more of a numbers person instead of shapes, but in my opinion it's still not an easy class that requires lots of studying.
Please please please help me with algebra!!?!?? i promise 10 points to the person who help me the most?
x = number of months, y = number of months after the first month MS = Money saved after x months The first month in the problem is merely x($50) = 1(50) = $50 the first month Thereafter, he increases each month by $5, so: MS = x($50) + y($5) So after two months he has: MS = 2($50) + 1($5)...remember, the first month he did not save an additional $5. We might want to re-write this as: MS = x($50) + (x - 1)($5) instead of using y, so after two months he has saved a total of: MS = 2($50) + (2 - 1)($5) = $200 + $5 = $205 In 6 months he will have saved: MS = 6($50) + (6 - 1)($5) = $300 + $5(5) = $300 + $25 = $325 The equation thus should be: MS = x($50) + (x - 1)($5) ---------------------------------------... Seventh month: MS = 7($50) + (7 - 1)($5) = $350 + $30 = $380 ---------------------------------------... This is the same kind of problem, only this time, in percents D = Diamond Value x = number of years D = $3500 + [(0.05)(x)*$3500)] D = $3500 + [(0.05)(6)*($3500)] D = $3500 + [0.3*$3500] D = $3500 + $1050 D = $4550 Remember that percents have to be in decimal percentage! so 5% = 5/100 = 0.05
ALGEBRA HELP ASAP!! (10 points promised)?
1. Express each ratio as a fraction in simplest form. 18 : 24 (Points : 4) 2. Solve. 4/7 = x - 3/21 (Points : 4) Option A: Option B: x = 15 Option C: Option D: x = 94 3. Write the number as a percent. 0.031 (Points : 4) 0.31% 3.1% 31% 310% 4. The ratio of two numbers is 5 to 3. The sum of the numbers is 16. What are the numbers? (Points : 4) 8 and 8 9 and 7 15 and 9 10 and 6 5. Solve. 5/6 = x/24 (Points : 4) 18 20 22 23 6. What is 16% of 50? (Points : 4) 7 8 9 10 7. Forty-two percent of what number is 168? (Points : 4) 40 70.6 400 705.6 8. Jacqueline drove 72 km on 6 L of gasoline. Which of the following equations can be used to find how far she can travel on a full tank of 50 L? (Points : 4) Option A: Option B: Option C: Option D: 9. What is 0.01% written as a decimal? (Points : 4) 0.0001 0.001 0.01 0.1 10. The population of a town decreased from 15,925 people to 8759 people. What was the approximate percent decrease? (Points : 4) 65% 55% 45% 35% 11. Ruiz invests $5500 at a simple interest rate of 4%. How much interest will he earn after 5 years? (Points : 4) $110,000 $11,000 $1100 $110
Can Someone Please Help Me With These Algebra Story Problems!? 10 POINTS TO THE BEST ANSWER! I PROMISE!?
1.) Rate is speed/distance the boat moved 24 miles/3 hours = 8 miles per hour On the return trip the boat moved 24 miles/4 hours which is only 6 miles per hour. This means that the current was moving at 2 miles per hour downstream, slowing the boat. 2.) You want the number of photos (x) that are equal in price at the two places, so you set up the following equation: 2.50 + 0.05x = 3.70 + 0.03x simplify to 0.02x = 1.20 divide to get x= 60 photos Now you can check this by plugging in 60 to each side of the equation. You will find that at 60 pictures, the price will be $5.50 at each location. 3.) I believe that you meant $5 bills and $10 bills and will go on this. 5x + 10y = 155 (this means that how many 5's plus how many 10's you have add up to $155.) next x+y=19 this means that the total number of bills is 19. so you have 5x + 10y = 155 x + y = 19 Now you can multiply the entire second equation by -5 to get. 5x + 10y =155 -5x -5y = -95 Now you can add the two equations together, eliminating the x value to get: 5y = 60 y=12 This means bob has 12 $10 bills Go back to x + y = 19 and plug in 12 for y x +12 =19 x=7 So bob had 7 $5's. So to check, 7 $5's is $35. And 12 $10's is $120. Together that is $155.
Math help. I'm so dumb! Algebra 1?
For the first one, separate it into two groups, and factor each group separately: 10k^2(5k-4) + 15(5k-4) So now you see that you have a common factor, (5k-4). You can combine the terms of 10k^2 and 15 to get (10k^2 + 15)(5k-4). You can also factor (10k^2 + 15) into 5(2k^2 + 3). So you now have: 5(2k^2 + 3)(5k-4) which is the solution. The other ones were already answered.
I really need help with three "easy" Algebra 2 Matrix problems?
So i'm taking online courses this summer, and being that i'm kinda doing things by myself I get a bit confused on what's going on. In a way i'm asking you to help me with homework, so don't take this question the wrong way and accuse me of making you do ALL of it. It's just these 3 and a few others actually (but i'll try to figure those others by myself, i'd like to know that I can figure out stuff). OKAY THIS IS NOT AN ENGLISH QUESTION!! Sorry? Here it goes: 1) What are the dimensions of the product of the following matrices? [2 -4] [-3 5 -1 2] [0 5] * [8 -3 7 0 ] [1 9] 2) What is the product of the following matrices? [8 -3] * [4 7] [-1 2] [6 0] 3) Find the product of the following matrices: [1 2] [5 4] [-4 3] * [5 2]
How do you do this algebra problem?
You promised your parents that you would wash the family car. You have not started the job and they are due home in 20 minutes. You can wash the car in 45 minutes and your sister claims she can do it in 30 minutes. If you work together how long will it take to do the job? Will this give you enough time before your parents return?
What is the best way to learn Algebra?
Roll up your sleeves and do it.Block out large chunks of time in regular intervals (… a few hours a day, ideally; but whatever your schedule allows). Sit down in a quiet place. Turn off televisions, phones, music, distractions, etc. Get a book(*), read a lesson, do 50 problems drilling the skills of that lesson.Repeat.I put an asterisk on “book,” to clarify that I mean a “book” in a functional sense. Maybe your “book” is electronic, for example. If your book is a website, you have to be very disciplined to not switch to some other site just for a few seconds to check in on something.You can watch videos if you want, and if you feel they’re helpful. But one thing is certain: you will never learn algebra 1 if you don’t do exercises. Ideally, lots of them.The good news is, you can do this in a short time. You can stop reading now if you like, but I’ll finish up with a little story from my education:I switched schools in 8th grade. Unbeknownst to me, the book I used in the first school was basically in the reverse order of the book I used at the next one. That meant I saw half of algebra 1 twice, and didn’t see the other half at all. Worse yet, I didn’t discover this until the final exam: I had no idea about half the stuff. So I got an F in the class.This was scary for me because (a) I knew I wasn’t an F student, and (b) the F meant I’d be placed into “math for dummies” next year. Fortunately, the F came in 8th grade. (For international readers: US colleges only look at your academic record from 9th grade on. So this F wouldn’t hurt me in that way.)In any case, I explained the situation to the 9th grade school administration, and somehow managed to get placed in the advanced math class on the condition I get up to speed on algebra by myself.So I did what I suggested above: over the summer, I worked through the first part of my algebra book. Sometimes I sat down for hours at a time, sometimes just 15–20 minutes a day. But I was relentless.If you can do that, you can learn algebra. In fact, you can learn a lot more.