Algebra 2 HELP Please? If G -1(y) is the inverse of G(x), which statements must be true?
Check all that apply. A.The range of G -1(y) is the domain of G(x). B.G -1(G(x)) = x C.The range of G -1(y) is the range of G(x). D.G(G -1(x)) = x E.The domain of G -1(y) is the range of G(x). F.The domain of G -1(y) is the domain of G(x).
Algebra 2 inverse functions?
When you find the inverse of a function, you switch the x and y values. This means that if you switch the x values of f(x) = √(x - 1), then that becomes the range. So, the domain of the first function will be the range of the second function. So, find the domain of the first; it will be any number that makes the quantity under the square root greater than or equal to 0, as you cannot have a negative under the square root. x - 1 ≥ 0 x ≥ 1 So, the domain of the first function is [1, ∞). This makes the range of its inverse [1, ∞) as well.
Algebra 2. Help? ? Inverse functions.?
1. If g(x)=3x - 5, then g negative 2 exponent(x) = 2. Let R={0,1,2,3} be the range of h(x) = x-7 the domain of h is 3 If f(x) = 3x + 1 = x-1 over 3 Then the ordered pair Of f(3) = 4. F(x) = 3x + 1 and f negative 1 exponent = X-1 over 3 then f(2) = 5. F(x) = 3x + 1 and f negative 1 exponent = X-1 over 3 Then the ordered pair of f negative 1 exponent(10 = 6. The inverse of a function is a function Always, sometimes or never. 7 which of the following functions has an inverse tht is not a function Y=x or y=2x+1 or y=x2 8. If f(a) = k, then which of the following must be true A. F(k) = a B. f negative 1 exponent(k) = a C. F negative 1 exponent(a) =k Please help!(: I've been trying to do this but I'm so tired from working all night and it's due by 5 tonight.
What is the range of the inverse of relation {(1, 7), (2, -4), (5, 6), (2, 8)}?
What is the range of the inverse of relation {(1, 7), (2, -4), (5, 6), (2, 8)}? {1, 2, 5} {-4, 6, 7, 8} {1, 5} {-4, 7, 8} Studying all day long and can't think!
Help with algebra 2 problem?
Let x, y, and z be individual elements. Our domain/codomain sets might look like this: Domain: x Codomain: y, z Recall that the term "Range" means ALL the elements to which a domain maps in a particular relation. In our case, the relation r has the mappings: x → y x → z Alternatively, r(x) = y r(x) = z Thus, relation r is clearly NOT a function, because a single input gives multiple outputs. A function is defined as a mapping of inputs to outputs in such a manner that each input maps to exactly one output. However, for the inverse, r^(-1), we have the two elements y and z mapping to x: y → x z → x Alternatively, r^(-1)(y) = x r^(-1)(z) = x Thus the inverse function r^(-1) IS a function, because each of its inputs maps to only one output. Keep in mind the idea of the vertical-line test. Although we don't have a graph here, you can still visualize points on a coordinate grid, inputs on the horizontal, outputs on the vertical axis. If the points line up vertically, you don't have a function, since a single input returns multiple outputs.
Algebra 2 help please please?
how do i find the domain and range algebraically for #3 & 4: 3. y = 20 - 2x^2 4. y = 25(-7x-4)^64 6.Let “M” be the set of motor vehicle owners who are registered in Ohio. Let “R” be the set of all motor vehicle registration numbers. Is the correspondence between M and R a function? Why, or why not? (12) A coupon for $5 off any lunch price states that a 15% tip will be added to the price before the $5 is subtracted. So, C(x) = x - 5 represents the price after the coupon reduction. T(x) = 1.15 x represents the price after the tip is applied. Calculate C(T(x)) and T(C(x)). Which composite function represents the conditions of the coupon? Find the inverse of the function. (13) g(x) = (7/3) x + 2 Solve. (16) “b” varies inversely as the square root of “c”. If b = 1 when c = 16, find b when c = 6. please help and if you ca show all work so i can learn to do them. :) thank you
Algebra 2 Functions Help?
YES, the inverse of a relation can most definitely can be a function. A function means that for every x there is one, and only one, y. On a graph, that means that if you draw a vertical line, it will only cross the graph once, thus only one y-coordinate for each x-coordinate. all lines that can be put in the form of y=mx+b are functions. the line x=k, where k is any constant, is not a function. the relation: x = a(y - k)² + h, where a is a constant and (h,k) is the vertex, is a parabola on it's side. Definitely not a function. it's inverse: y = a(x - h)² + k, is a parabola going up or down and definitely is a function. making it easier: x = y² is not a function, (ie, if x=4, y can be 2 or -2 and there can only be one y for each x) the inverse, however, is y = x², which is a function. A function and it's inverse are reflected over the line y=x. The x and y switch. Hope this helps! This could easily be a whole book or at least a chapter, but still I hope it helps. that's it! ;)
TI-84 Calculator Programs for Algebra 2 HELP?
Does anyone have manual code program/downloadable programs for the TI-84 for the following reasons..... - Descartes Rule - Solving Quadratic Equations (Factoring) - Determining if a function is even, odd, or niether - Stating the Domain & Range - Finding the Inverse of a function - General Term - Finding a specific term - Describing end behavior - Vertex Form - Geometric Sequences - Arithmetic Sequences - Pascals Triangle (Binomial Expansion) I have my Final in Algebra 2 AC comming up and i would like to check my work to make sure im doing it right; that way im not studying the wrong methods. I HAVE checked ti.com and there wasnt anything. Even ways on how to do the above topics on a calculator would be helpful! Thanks in advance!