At A Carnival The Centripetal Force Ride Spins At 5 Rad/sec.

How fast would earth have to spin for its centripetal force on its equator to equal its gravity?

Short answer: the Earth currently spins at 1040 mph or 1,674 kph. For centripetal force to equal gravitational force (9.81m/s^2) The Earth would have to spin at just over 17.06 times its current speed. That is 17,742 mph or 28,554 kph. A day/night cycle would be just over 1 hour, 24 mins, 23.48 seconds. I don’t know how to go about the atmosphere question.method: I see a couple people have already answered this but it looks fun so I’m going to do it anyways and see if I get the same answer (and I’ll try to explain it along the way).First off we will make two assumptions. 1) The Earth is a perfect sphere. 2) gravity is a constant 9.81 m/s^2.The Earth’s axis forms a 90 degree angle with the equator (I think this has to be true for any planet). Since this is 90 degrees and you only care about the spot on the equator, we can imagine the equator as a single spinning disc. A Google search tells us the average distance from the core to the equator is 6,371 km=6,371,000 m = r. We want acceleration a = 9.81 m/s^2. We have the equation a=(v^2)/r. Thenv=sqrt(a/r)=sqrt(9.81/6,371,000) radian per second.A period (T) is calculated by T=2*pi/v. SoT=2pi/(sqrt(9.81/6,371,000)) seconds.Hours would be a bit easier to grasp so lets get revolutions per hour. Note that a current day is about 1/24th of a revolution per hour so 24 hours make a day. 1/24 = 0.04167.Anyways, revolutions per hour = 3600/T. So revolutions = 3600/(2pi/(sqrt(9.81/6371000))) = 0.71097 revolutions per hour.So to produce the same effect as gravity, the Earth would have to move just over 17.06 times its current speed. The Earth currently spins at 1,674 kph at the equator. So The Earth would spin at 28,559 kph at the equator.As far as how long a day/night cycle would be, a current day is 24 hours so 24/17.06=84.39 minutes. Keeping things more exact we get a day/night cycle to be just over 1 hour, 24 mins, 23.48 secondsAs far as the question about how thin the atmosphere would be, I wouldn’t even know how to start.Also I wouldn’t trust this if I was the only one who had worked it out once but seeing two other people with answers similar to mine means that this is likely accurate.

Why is centrifugal force called pseudo force?

Why is centrifugal force called pseudo force?The reason is psychological, not physical.When an object is rotating, parts of it away from the center of rotation are subject to a force tending to push them farther away from the center of rotation. This is clearly evidenced to anyone who has witnessed the breakup of a grinding wheel, a centrifuge, a flywheel, and the like. People have been killed that way.If one considers such an event from a non-rotating point of view, such breakup can be seen considered to be a manifestation of the tendency of each part of an object to move in a straight line. If one considers such an event from a point of view rotating with the object, the same event can be seen as a manifestation of centrifugal force. Centrifugal force exists in one coordinate system, and does not exist (or, rather, has zero magnitude) in another.A fundamental characteristic of physics is that its laws are equally applicable in any coordinate system.Some systems are more easily understood in one coordinate system, some in another, but all are equally valid.My boss once cited a problem on which he and a colleague had worked for half an hour and failed to solve. I solved it in two minutes, using a rotating coordinate system, in which centrifugal force was perfectly real.Another example is gravity. In a coordinate system stationary with respect to Earth’s surface, it is non-zero. In a free-falling coordinate system, it is zero. Most of physics is much simpler in a free-falling coordinate system. Indeed, fundamental equations, such as [math]F = m a[/math], are always quoted in a free-falling coordinate system. They are much more complicated in a coordinate system with gravity, and are rarely quoted or used in that way.The psychological problem is that most people live most of the time on Earth’s surface, and most of the time rotate only at the sedate rate of Earth. Consequently, gravity is more familiar to them than centrifugal force. Those who don’t understand physics erroneously think that gravity is more real than centrifugal force. The difference is emotional, not real.

What is centrifugal force?

A force, arising from the body's inertia, which appears to act on a body moving in a circular path and is directed away from the centre around which the body is moving.Centrifugal forceThis is force in moving object in circular path. And this force is force pulling object outside from center of circle. This force have many application in day life.  This is principle of centrifugal force we come across in daily life Centrifuge machine is classic example of centrifugal force. Washing machine is also one example of this force.1.Washing MachinesWe are using washing machine daily. There are cloths are dried automatically. We use centrifugal force in this case. There wet cloths are moving circular path and force act on water particle in cloths and this force pull water to outer side. This water is removed from cloths and cloths are dried in this machine. Basic principle is centrifugal force acting on water.2.Buses at corner or circular pathWhen we are traveling in bus and bus comes to move or at corner. There is circular path of bus. And this time there is force acting on bus and centrifugal force acting on passenger and pull passenger from center to outside due to centrifugal force. And we are moved to outer edge of bus. This force is centrifugal force.3:Centrifuge machine and cream separationThis is classic application of centrifugal force. Centrifuge machine have electric motor and this motor connected to rod and this rod is placed to move. And this rod ends are set bottle containing milk. When this machine moves then this milk have pressure and solid part from this milk goes outside and this solid part is cream. In this way cream is separate from milk and used for other product. This is very common in our daily life. And principle is centrifugal force.

Is there a rotational speed at which the centripetal acceleration of a pistol spun on a table could actually cause the pistol to fire?

for most modern firearms, no . Many modern firearms have a variety of internal safeties. I’ll use the Glock as an example. Glock will not fire unless the trigger has been pulled to the rear. It also has a firing pin safety as well as a drop safety. These safety are very hard to describe without pictures so please see attached.Our “Safe Action”® System. Always safe and always ready.

Does centrifugal force actually exist? If so, why do high schools teach that it does not?

Centrifugal force is definitely real, in that you will definitely feel it should you happen to be a part of a rotating object. It is fictitious in the sense that it only exists in the form of an outward force in a rotating frame of reference. Again, the phenomenon will be experienced no matter what frame of reference you are in, but the source of that force, from your perspective, will change.Imagine you are on a merry-go-round. The merry-go-round is spinning. What happens? First, the merry-go-round, with the help of friction, imparts a force on you tangential to the circumference. This force causes you to have some kinetic energy, i.e. velocity in that same direction. The merry-go-round rotates. Thanks to friction, you rotate with it, but you haven't lost your kinetic energy from before and it continues to build up as your velocity increases.What has happened once the merry-go-round has made a rotation of 90°? Ideally, you would like to have a velocity component tangential to the merry-go-round. However, that's not what happens because objects like to go in straight lines and, if they are moving in a straight line, will continue to do so unless something stops them. The merry-go-round will have diverted your velocity somewhat from its original path (tangential to the merry-go-round at 0°), but you will still be moving with a large component in that direction, which is now perpendicular to the merry-go-round so, unless you are holding onto something, you are going to fly off.Now change to a rotating reference frame. In this frame, the merry-go-round is not moving. Of course, just because you decided to make your coordinate system rotate at the same frequency as the merry-go-round doesn't mean you will stop being flung off of the merry-go-round. Because the merry-go-round isn't moving in your frame of reference, though, you can't account for this phenomenon by evaluating its motion. Instead, you introduce the centrifugal force to describe what is happening. As we have seen, there is a very clear explanation for this phenomenon stemming from the inertial frame of reference but, for convenience (remember, it was for convenience that you decided to switch to a rotating frame of reference in the first place), it can be called a force and treated as a force (stemming from a centrifugal pseudo-potential) as long as you remain in a non-inertial frame.